a) 3⁵.3⁹.3²⁰.81⁴ = 3⁵.3⁹.3²⁰.3¹⁶=3^5+9+20+16=3⁵⁰

b) (5¹⁶.5¹³).25³=5²⁹.5⁶=5²⁹⁺⁶=5³⁵

nhớ k nha

a) 3⁵ . 3⁹ . 3²⁰ . 81⁴ = 3⁵ . 3⁹ . 3²⁰ . 3¹⁶ = 3⁵⁰
b) ( 5¹⁶ . 5¹³ ) . 25³ = 5²⁹ . 5⁶ = 5³⁵
c) 2⁴ . 5⁴ = ( 2 . 5 )⁴ = 10⁴

\(1)\)\(M=3^0+3^2+3^4+3^6+...+3^{58}\)

\(M=\left(3^0+3^2\right)+\left(3^4+3^6\right)+...+\left(3^{57}+3^{58}\right)\)

\(M=\left(3^0+3^2\right)+3^4\left(3^0+3^2\right)+...+3^{57}\left(3^0+3^2\right)\)

\(M=10+3^4.10+...+3^{57}.10\)

\(M=10\left(1+3^4+...+3^{57}\right)\)

\(M=\overline{...0}\)

Vậy \(M\) có chữ số tận cùng là \(0\)

Chúc bạn học tốt ~ 

thank you very much

a) ta có: 27⁵=3¹⁵

             243³=3¹⁵

Vì 3¹⁵=3¹⁵ =>27⁵=243³

Vậy 27⁵=243³

b) Ta có:8⁵=2¹⁵

             3⁷<4⁷=2¹⁴

Vì 2¹⁵>2¹⁴=>8⁵>3⁷

Vậy 8⁵>3⁷

5^2+3^2-(5^16:25^7+3^4:3)

=5^2+3^2-[5^16:5^14+3^4:3)

=25+9-[5^2+3^3]

=25+9-[25+27]

=34-52=-18

= 5² + 3² - (25 + 27)

= 25 + 9 - 52

= 34 - 52

= -18 ( âm 18 nha)

k cho mik nha

Bài 2: 

a: \(\Leftrightarrow\left(19x+50\right):14=5^2-4^2=9\)

=>19x+50=126

=>19x=76

hay x=4

b: \(\Leftrightarrow3^x\cdot2=10\cdot3^{12}+8\cdot3^{12}\)

\(\Leftrightarrow3^x\cdot2=3^{12}\cdot18\)

\(\Leftrightarrow3^x=3^{14}\)

hay x=14

c: \(\Leftrightarrow720:\left(41-2x+5\right)=8\cdot5=40\)

=>46-2x=18

=>2x=28

hay x=14

giúp mik với mn ơi mik cần gấp

b, 2B=3²+3³+3⁴+3⁵+3⁶

2B-B=3+3⁶

a, \(3^4\div3^2-\left[120-\left(2^6.2+5^2.2\right)\right]\)

\(=3^2-\left\{120-\text{[}2.\left(2^6+5^2\right)\text{]}\right\}\)

\(=3^2-\left(120-2\cdot89\right)\)

\(=9--58=9+58=67\)

1. \(a,3^4:3^2-\left[120-(2^6\cdot2+5^2\cdot2)\right]\)

\(=3^2-\left[120-\left\{(2^6+5^2)\cdot2\right\}\right]\)

\(=3^2-\left[120-\left\{(64+25)\cdot2\right\}\right]\)

\(=9-\left[120-89\cdot2\right]\)

\(=9-\left[120-178\right]=9-(-58)=67\)

b, Tương tự như bài a

2.a,\(4^x\cdot5+4^2\cdot2=2^3\cdot7+56\)

\(\Leftrightarrow4^x\cdot5+16\cdot2=8\cdot7+56\)

\(\Leftrightarrow4^x\cdot5+32=56+56\)

\(\Leftrightarrow4^x\cdot5+32=112\)

\(\Leftrightarrow4^x\cdot5=80\)

\(\Leftrightarrow4^x=16\Leftrightarrow4^x=4^2\Leftrightarrow x=2\)

\(b,24:(2x-1)^3-2=1\)

\(\Leftrightarrow24:(2x-1)^3=3\)

\(\Leftrightarrow(2x-1)^3=8\)

\(\Leftrightarrow(2x-1)^3=2^3\)

\(\Leftrightarrow2x-1=2\)

Làm nốt là xong thôi