Cgcr

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4+8+7+9+5+2+1+3*0=36

4 + 8+7+9+5+2 +1 +0

[(1+9)+(2+8)+(3+7)+(4+6)+5]x2

=(10+10+10+10+5)x2

=45x2

=90

50x2+2x10

=2x(50+10)

=2x60

=120

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

C1: \(\left(\frac{3}{5}+\frac{4}{9}\right)\cdot\frac{3}{8}=\frac{47}{45}\cdot\frac{3}{8}=\frac{141}{360}=\frac{47}{120}\)

C2: \(\left(\frac{3}{5}+\frac{4}{9}\right)\cdot\frac{3}{8}=\frac{3}{5}\cdot\frac{3}{8}+\frac{4}{9}\cdot\frac{3}{8}=\frac{9}{40}+\frac{12}{72}=\frac{47}{120}\)

C1: ( \(\frac{3}{5}+\frac{4}{9}\) ) * \(\frac{3}{8}\) 

= \(\frac{47}{45}\) * \(\frac{3}{8}\) = \(\frac{47}{120}\) 

C2: Đề

= 3/5 * 3/8 + 4/9 * 3/8

= 9/40 + 1/6

= 47/120

\(a,2\times3=6\)

\(6\times2=12\)

\(10\times2=20\)

\(1\times2=2\)

\(b,5\times7=35\)

\(9\times5=45\)

\(5\times8=40\)

\(1\times5=5\)

9 x 5 = 45

9 x 6 = 54

9 x 7 = 63

9 x 8 = 72

9 x 9 = 81

45

54

63

91

Bài 1 :

a , x = 675

b , x = 1764

c , x = 0

Bài 2 :

a , x = 3 , 2 , 1 , 0

b , x = 6 , 5 , 4 , 3 , 2 , 1 , 0

c , x = 3 , 4

Bài 1:Tìm x

a, x:5=27\(x\)5

    x:5=135

    x  =135\(x\)5

    x  =675

b, x:7=36\(x\)7

    x:7=252

    x  =252\(x\)7

    x  =1764

c,x\(x\)132=312 x (5-3-2)

  x\(x\)132=312x0

x\(x\)132=0

x          =0:132

x          =0

B1

a) 17 b) 6 c) 112 d)9687

B2

100-x=33

x=100-33

x= 67

Ko bít

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1 - 2 + 3 - 4 + 5 - 6 + 7 - 8 + 9

= (9 - 8) + (7 - 6) + (5 - 4) + (3 - 2) + 1

= 1 + 1 + 1 + 1 + 1

= 1 x 5

= 5

5

10+9-8+7-6+5-4+3-2+1-0

= 10 +[(9 - 8) + (7 - 6) + (5 - 4) + (3 - 2) + (1 - 0)]

= 10 + [1 + 1 + 1 + 1 + 1]

= 10 + 1 x 5

= 10 + 5

= 15

15