a; \(\dfrac{9}{4}\) - \(\dfrac{-11}{4}\)

= \(\dfrac{9}{4}\) + \(\dfrac{11}{4}\)

= \(\dfrac{20}{4}\)

= 5 

b; \(\dfrac{7}{8}\) - \(\dfrac{3}{-8}\) - \(\dfrac{1}{8}\)

=  \(\dfrac{7}{8}\) + \(\dfrac{3}{8}\) - \(\dfrac{1}{8}\)

= \(\dfrac{7+3-1}{8}\)

= \(\dfrac{9}{8}\) 

c; \(\dfrac{-5}{21}\) - \(\dfrac{25}{21}\) - \(\dfrac{-1}{21}\)

  = \(\dfrac{-5}{21}\) - \(\dfrac{25}{21}\) + \(\dfrac{1}{21}\)

 =  \(\dfrac{-5-25+1}{21}\)

= \(\dfrac{-29}{21}\)

a/ 8

b/ 63

c/ 12

d/17

e/ 16

f/4

g/ 32

a: 9-25=7-x-(25+7)

=>7-x-25-7=-16

=>-x-25=-16

=>x+25=16

hay x=-9

b: \(10+2\left|x\right|=2\cdot\left(3^2-1\right)\)

\(\Leftrightarrow2\left|x\right|=2\cdot8-10=6\)

=>x=3 hoặc x=-3

c: -6x=18

nên x=18:(-6)=-3

a: \(\dfrac{1}{3}+\dfrac{3}{35}< \dfrac{x}{210}< \dfrac{4}{7}+\dfrac{3}{5}+\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{70}{210}+\dfrac{18}{210}< \dfrac{x}{210}< \dfrac{120}{210}+\dfrac{126}{210}+\dfrac{105}{210}\)

\(\Leftrightarrow88< x< 441\)

b: Ta có: \(\dfrac{5}{3}+\dfrac{-14}{3}< x< \dfrac{8}{5}+\dfrac{18}{10}\)

\(\Leftrightarrow\dfrac{5}{3}-\dfrac{14}{3}< x< \dfrac{8}{5}+\dfrac{9}{5}\)

=>-9/3<x<17/5

=>-3<x<3,4

mà x là số nguyên

nên \(x\in\left\{-2;-1;0;1;2;3\right\}\)

a,\(x+5=\left|-18\right|\)

\(x+5=18\)

\(x=13\)

b,\(\left|-35\right|-x=\left|-5\right|\)

\(35-x=5\)

\(x=30\)

c,\(25-\left|x\right|=10\)

\(\left|x\right|=15\)

\(\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-15\end{matrix}\right.\)

Vậy x=15 hoặc x=-15.

d,\(\left|x-2\right|+7=12\)

\(\left|x-2\right|=5\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=5\\x-2=-5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-3\end{matrix}\right.\)

Vậy...

A.x+5=18

x=18-5

x=13

B.35-x=5

x=35-5

x=30

C,25-x=10

x=25-10

x=15

D.x=7

x-2=5

=35-7.-13
=37--91
=37+91=128

35--91

= 126                                         Đ/S : 126