7² - 7 . ( 13 . x ) =14

 => 49 - 7.( 13.x) = 14

 => 7.(13.x) = 49 -14 = 35

 => 13.x = 35 : 7 = 5

 => x = 5 : 13

 => x = 5/13 

9 x 5⁵ : ( 5⁷ : 5⁴ ) + 2³ x 5

= 9 x 5⁵ : 5³ + 8 x 5

= 9 x 5² + 40

= 225+40

= 265

Thế này à:

a, \(\frac{2^{13}+25}{2^{10}}\)

b, \(\frac{21^2.14.125}{35^5.6}\)

c,\(\frac{45^3.20^4.18^2}{180^5}\)

d, \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

2 mũ 13 ta chia cho 2 mũ 10 ta có là 2 mũ 3 chuyển thành 8 rồi cộng cho 25 ta có là 33

a ) 4⁵ . 4 . 4⁷ = 4⁵ . 4¹ . 4⁷ = 4¹³

b ) 4 . 4³ . 4⁵ . 4⁶ = 4¹ . 4³ . 4⁵ . 4⁶ = 4¹⁵

c ) x . x³ . x⁴ = x¹ . x³ . x⁴ = x⁸

d ) x⁵ . x⁴ . x⁷ . x⁶ = x²²

\(4^2\cdot120-4^3\cdot17+4^2\cdot34\)

\(=4^2\left(120-4\cdot17+34\right)\)

\(=16\left(120-68+34\right)\)

\(=16\cdot86=1088\)

\(7^3\cdot9+3^2\cdot7^4-45\cdot539\)

\(=7^3\cdot9+9\cdot7^4-45\cdot7^2\cdot11\)

\(=7^2\left(7\cdot9+9\cdot7^2-45\cdot11\right)\)

\(=49\left(63+9\cdot49-495\right)\)

\(=49\left(63+441-495\right)\)

\(=49\cdot9=441\)

Đặt A=\(\frac{1}{3}.5+\frac{1}{5}.7+...+\frac{1}{97}.99\)

=>A=\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}\)

=>2A=\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}\)

=>2A=\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\)

=>2A=\(\frac{1}{3}-\frac{1}{99}=\frac{33}{99}-\frac{1}{99}=\frac{32}{99}\)

=>A=\(\frac{32}{99}:2=\frac{32}{99}.\frac{1}{2}=\frac{32}{198}=\frac{16}{99}\)

967 là đáp án

công thức tính đâu bạn?

\(27^3.9^4.243=3^{3.3}.3^{2.4}.3^5\)

\(3^9.3^8.3^5=3^{22}\)

\(25^3.125^2=5^{2.3}.5^{3.2}=5^6.5^6=5^{12}\)

(7*x-11)^3 = 2^5 * 5^2 +200

(7*x-11)^3 = 32*25+200

(7*x-11)^3=800+200

(7*x-11)^3=1000

=>(7*x-11)^3=(1000)^3

7*x-11=1000

7x=1000+11

7x=1011

x=1011/7

(7.x-11)^3=2^5.5^2+200

(7.x-11)^3=32.25+200

(7.x-11)^3=800+200

(7.x-11)^3=1000

(7.x-11)^3=10^3

7x-11=10

7x=10+11

7x=21

x=21/7

x=3

(3x - 6).3 = 3⁴

3x - 6 = 3⁴ : 3

3x - 6 = 3³

3x - 6 = 27

3x = 27 + 6

3x  =33

x = 33:3

x=11

12x - 34 = 3².3⁵

12x - 34 = 3⁷

12x - 34 = 2187

12x = 2187 + 34

12x = 2221

x = 2221:12

x=2221/12