\(\left(x^2+2\right)\left(x^2+2^5\right)\)

\(\Rightarrow\orbr{\begin{cases}x^2+2=0\\x^2+2^5=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x\in\varnothing\\x\in\varnothing\end{cases}}\)

vậy \(x\in\varnothing\)

a) 2^x*(1+2+4+8) = 480

     2^x*15           = 480

     2^x                      = 480/15

      2^x                = 32

=>   x                 = 5.

b) Lười giải quá bạn ơi, thông cảm.

10-2(x+3)=5(x-2)

7(x+3)=5(x-2)

7x+21=5x-10

7x-5x=-10-21

2x=-31

x=-15.5

3^x+3^x+1+3^x+2=351

3^x+3^x*3+3^x*3^2=351

3^x(3+3^2+1)=351

3^x*9=351

3^x=39

3^x=

a) sử dụng tính chất phân phối là sẽ làm đc

b)đặt chung 3^x ra là lm đc

a)Ta có 10- 2(x+3)= 5(x-2)

        10 - 2x-6=  5x-10

            14= 7x

             x = 2

b)  Ta có :              3^x +3^x+1+3^x+2=  351

                             3^x+3^x.3+3^x.3²=351

                            3^x(1+3+3²)=351

                             3^x.13=351

                               3^x=27

                                x=  3

cau 1: x=2

cau 2: x=3

ung ho nha cac ban ^_^

a, \(\left(-2\right)^2-2x^2=-50.\)

\(\Leftrightarrow4-2x^2=-50\)

\(\Leftrightarrow2x^2-54=0\)

\(\Leftrightarrow x^2-27=0\)

\(\Leftrightarrow\left(x-3\sqrt{3}\right)\left(x+3\sqrt{3}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=3\sqrt{3}\\x=-3\sqrt{3}\end{cases}}\)

\(\left(-2\right)^2-2x^2=-50\)

\(\Leftrightarrow x^2=\frac{-50-\left(-2\right)^2}{-2}\)

\(\Leftrightarrow x^2=27\)

\(\Leftrightarrow x=\pm\sqrt{27}\)

\(\Leftrightarrow x=\pm3\sqrt{3}\)

\(\frac{2}{x}-\frac{5}{x}=-9\)

\(\Leftrightarrow\frac{2-5}{x}=-9\)

\(\Leftrightarrow-3=-9x\)

\(\Leftrightarrow x=\frac{-3}{-9}=\frac{1}{3}\)

12x-4^3.8^3=2^2.(2^2)^3

12x.(2^2)^3.(2^3)^3=2^2.2^6

12x-2^6.2^9=2^8

12x-2^15=2^8

12x=2^8+2^15

12x=256+32768

12x=33024

x=33024/12

x=2752

cam on bn

bn co de thi toan lop 6 1 tiet ko cho mik xem nhe

\(\left(2x+1\right)^4-10^0=80\)

\(\left(2x+1\right)^4-1=80\)

\(\left(2x+1\right)^4=81\)

\(\left(2x+1\right)^4=3^4\)

\(\Rightarrow2x+1=3\)

\(\Rightarrow2x=2\)

\(\Rightarrow x=1\)

vay \(x=1\)

mk giup ban roi, gio ban giup lai mk di

nho k cho mk day

\(\left(2x+1\right)^4-10^0=80\)

\(\Leftrightarrow\left(2x+1\right)^4-1=80\)

\(\Leftrightarrow\left[\left(2x+1\right)^2\right]^2-9^2=0\)

\(\Leftrightarrow\left[\left(2x+1\right)+9\right]\left[\left(2x+1\right)-9\right]=0\)

.... tự làm nha đang bận gấp