5^11x49^6+5^11x7^11/125^4x7^11+9x35^11

=5^11x7^11(7+1)/5^11x7^11(5+9)

=7+1/5+9

=4/7

Hok tốt(mik làm hơi tắt mong thông cảm  ^-^ )

a, \(\frac{25^{11}.4^{33}}{8^{15}.10^{22}}=\frac{\left(5^2\right)^{11}.\left(2^2\right)^{33}}{\left(2^3\right)^{15}.\left(2.5\right)^{22}}=\frac{5^{22}.2^{66}}{2^{45}.2^{22}.5^{22}}=\frac{5^{22}.2^{66}}{2^{67}.5^{22}}=\frac{1}{2}\)

b,\(\frac{8^4.5^8.9^3}{125^3.4^7.27}=\frac{\left(2^3\right)^4.5^8.\left(3^2\right)^3}{\left(5^3\right)^3.\left(2^2\right)^7.3^3}=\frac{2^{12}.5^8.3^6}{5^9.2^{14}.3^3}=\frac{3^3}{5.2^2}=\frac{27}{20}\)

Bạn làm nốt nhé cũng tương tự thôi !!!!!!!!!

......................?

mik ko biết

mong bn thông cảm !$$%

Ai nhanh mình k

Câu a:

(7\(^{2017}\) - 7\(^{2015}\)) ⋮ (7\(^{2014}\).7)

= 7\(^{2015}\).(7\(^2\) - 1) ⋮ 7\(^{2015}\)

= (7\(^{2015}\) : 7\(^{2015}\)).(49 - 1)

= 1.48

= 48

Câu b:

(2\(^{13}\) + 2\(^5\)) : (2\(^{10}\) + 2\(^2\))

= 2\(^5.\)(2\(^8\) + 1):[2\(^2\).(2\(^8\) + 1)]

= (2\(^5:2^2\)).[(\(2^8+1):\left(2^8+1\right)\)]

= 2\(^3\).1

= 8

(125³ . 7⁴ - 5⁹ .49²) : 2005²⁰⁰⁶

= (5^9 * 7^4 - 5^9 * 7^4) :2005^2006

= 0 : 2005^2006

= 0

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