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\(\frac{22}{5}x+\frac{2}{3}=\frac{-4}{5}\)
\(\Rightarrow\frac{22}{5}x=\frac{-4}{5}-\frac{2}{3}\)
\(\Rightarrow\frac{22}{5}x=\frac{-22}{15}\)
\(\Rightarrow x=\frac{-22}{15}\div\frac{22}{5}\)
\(\Rightarrow x=\frac{-1}{3}\)
Bài 1:
\(A=\left(\frac{-5}{11}+\frac{7}{22}-\frac{4}{33}-\frac{5}{44}\right):\left(38\frac{1}{122}-39\frac{7}{22}\right)\)
\(=\frac{-49}{132}:\left(-\frac{879}{671}\right)=\frac{2989}{105408}\)
Bài 2:
\(\frac{4}{5}-\left(\frac{-1}{8}\right)=\frac{7}{8}-x\)
<=> \(\frac{7}{8}-x=\frac{27}{40}\)
<=> \(x=\frac{7}{8}-\frac{27}{40}=\frac{1}{5}\)
Vậy...
\(\frac{-3}{4}:\left(\frac{2}{15}\cdot x\right)=3:\frac{2}{5}=\frac{15}{2}\)
\(\frac{2}{15}\cdot x=\frac{3}{4}:\frac{15}{2}=\frac{1}{10}\)
\(x=\frac{1}{10}:\frac{2}{15}=\frac{3}{4}\)
=>\(x=\frac{3}{4}\)
tk mik nha bạn
-3/4:(2/15*x)= 15/2
2/15*x= -3/4 :15/2 = -1/10
x= -1/10 :2/15 = -3/4
Vậy x = -3/4
\(4^3\cdot8^{25}\cdot9^3\)
\(=2^6\cdot2^{75}\cdot\left(3^2\right)^3\)
\(=2^{81}\cdot3^6\)
\(8^2\cdot125^3\cdot3^5\)
\(=2^6\cdot\left(5^3\right)^3\cdot3^5=2^6\cdot5^9\cdot3^5\)
Ta có: \(\frac{4^3\cdot8^{25}\cdot9^3}{8^2\cdot125^3\cdot3^5}\)
\(=\frac{2^{81}\cdot3^6}{2^6\cdot5^9\cdot3^5}=\frac{2^{75}\cdot3}{5^9}\)