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1) 4n = 4096
<=> 4n = 46
<=> n = 6
=> x = 6
2) 5n = 15625
<=> 5n = 56
<=> n = 6
=> x = 6
3) 6n + 3 = 216
<=> 6n + 3 = 63
<=> n + 3 = 0
<=> n = 0
=> n = 0
4) 4n - 1 = 1024
<=> 4n - 1 = 45
<=> n - 1 = 5
<=> n = 6
=> n = 6
Đặt tổng trên = A
\(A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{4096}+\frac{1}{8192}\)
\(A.2=2+1+\frac{1}{2}+\frac{1}{4}+...+\frac{1}{2048}+\frac{1}{4096}\)
\(A.2-A=\left(2+1+\frac{1}{2}+\frac{1}{4}+...+\frac{1}{2048}+\frac{1}{4096}\right)-\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{4096}+\frac{1}{8192}\right)\)
\(A=2-\frac{1}{8192}=\frac{16383}{8192}\)
Đặt A = 1 + 1/2 + 1/4 + 1/8 + ... + 1/4096 + 1/8192
2A = 2 + 1 + 1/2 + 1/4 + ... + 1/2048 + 1/4096
2A - A = (2 + 1 + 1/2 + 1/4 + ... + 1/2048 + 1/4096) - (1 + 1/2 + 1/4 + 1/8 +... + 1/4096 + 1/8192)
A = 2 - 1/8192
A = 16383/8192
A = 1+2+4+8+...+8192
A = 2 0 + 2 1 + 2 2 + 2 3 +...+2 13
2A = 2 1+2 2+2 3+2 4+...+2 14
2A ‐ A = 2 14 ‐ 2 0
=> A = 2 14 ‐ 1
= 16781312 + 1 = 16781313
k tớ nhé
k ết bạn nha
li -ke cho tớ thật nhiều tuần sau li -ke lại cho
Đặt A=1/2+1/4+1/8+1/16+1/32+...+1/2048+1/4096
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{12}}\)
\(2A=2\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)
\(2A=1+\frac{1}{2}+...+\frac{1}{2^{11}}\)
\(2A-A=\left(1+\frac{1}{2}+...+\frac{1}{2^{11}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)
\(A=1-\frac{1}{2^{12}}\)
a) n = 4 ; n = 5
b) n = 6 ; n = 6
c) n = 0 ; n = 6
a) \(4^n=4096\Rightarrow4^n=4^6\Rightarrow n=6\)
b) \(5^n=15625\Rightarrow5^n=5^6\Rightarrow n=6\)
c) \(6^{n+3}=216\Rightarrow6^{n+3}=6^3\Rightarrow n+3=3\Rightarrow n=0\)
d) \(x^2=x^3\Rightarrow x^3-x^2=0\Rightarrow x^2\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
e) \(3^{x-1}=27\Rightarrow3^{x-1}=3^3\Rightarrow x-1=3\Rightarrow x=4\)
f) \(3^{x+1}=9\Rightarrow3^{x+1}=3^2\Rightarrow x+1=2\Rightarrow x=1\)
g) \(6^{x+1}=36\Rightarrow6^{x+1}=6^2\Rightarrow x+1=2\Rightarrow x=1\)
h) \(3^{2x+1}=27\Rightarrow3^{2x+1}=3^3\Rightarrow2x+1=3\Rightarrow2x=2\Rightarrow x=1\)
i) \(x^{50}=x\Rightarrow x^{50}-x=0\Rightarrow x\left(x^{49}-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}=1=1^{49}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
4n = 4096
4n = 212
n = 12
5n = 15625
5n = 56
n = 6
6n+3 = 216
6n+3 = 23.33
6n+3 = 63
n + 3 = 3
4n + 1 = 4096
4n + 1 = 48
=> n + 1 = 8
=> n = 8 - 1
=> n = 7
vậy n = 7
\(4^{n+1}=4096\)
\(n=5\)
4n+1=4096
Mà: 46=4096
=> 4n+1=46
=>n+1=6
=>x=6-1
=>n=5