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a; \(\frac35+\frac{14}{7}+\frac{4}{10}\)
= \(\frac35\) + 2 + \(\frac25\)
= (\(\frac35\) + \(\frac25\)) + 2
= 1+ 2
= 3
b; \(\frac27+\frac37+\frac47+\frac57+\frac67\)
= \(\frac57+\frac47+\frac57+\frac67\)
= \(\frac97+\frac57+\frac67\)
= \(\frac{14}{7}+\frac67\)
= \(\frac{20}{7}\)
+) = \(\frac{20}{7}\)
+) = \(\frac{101}{22}\)
tk mik nha
mik khỏi chép lại đề
+) = \(\frac{7}{2}+\frac{33}{7}-\frac{75}{14}\)
= \(\frac{49}{14}+\frac{66}{14}-\frac{75}{14}\)
= \(\frac{115}{14}-\frac{75}{14}\)
= \(\frac{20}{7}\)
+) = \(\frac{9}{2}+\frac{1}{2}:\frac{11}{2}\)
= \(\frac{9}{2}+\frac{1}{2}\)x \(\frac{2}{11}\)
= \(\frac{9}{2}+\frac{1}{11}\)
= \(\frac{99}{22}+\frac{2}{22}\)
= \(\frac{101}{22}\)
tk nha b
A,\(\frac{7}{13}+\frac{1}{7}+\frac{18}{30}=\frac{49}{91}+\frac{13}{91}+\frac{18}{30}=\frac{62}{91}+\frac{18}{30}=\frac{1860}{2730}+\frac{1638}{2730}=\frac{583}{455}\)
B,\(\left(\frac{20}{21}+\frac{3}{14}\right)-\frac{2}{3}=\left(\frac{280}{294}+\frac{63}{294}\right)-\frac{2}{3}=\frac{7}{6}-\frac{2}{3}=\frac{21}{18}-\frac{12}{18}=\frac{9}{18}=\frac{1}{2}\)
C,\(=\frac{17}{5}+\frac{31}{7}=\frac{119}{35}+\frac{155}{35}=\frac{234}{35}\)
\(3\frac{1}{2}=\frac{7}{2};4\frac{5}{7}=\frac{33}{7}\)
\(3\frac{1}{2}+4\frac{5}{7}-\frac{5}{14}\)
\(=\frac{7}{2}+\frac{33}{7}-\frac{5}{14}\)
\(=\frac{49}{14}+\frac{66}{14}-\frac{5}{14}\)
\(=\frac{115}{14}-\frac{5}{14}\)
\(=\frac{110}{14}=\frac{55}{7}\)


\(\frac23+\frac45=\frac{10}{15}+\frac{12}{15}=\frac{10+12}{15}=\frac{22}{15}\)
\(\frac37+\frac{7}{14}=\frac{6}{14}+\frac{7}{14}=\frac{6+7}{14}=\frac{13}{14}\)
\(5+\frac13=\frac{15}{3}+\frac13=\frac{15+1}{3}=\frac{16}{3}\)