Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có:
\(B=\frac{2015+2016}{2016+2017}=\frac{2015}{2016+2017}+\frac{2016}{2016+2017}\)
vì: \(\frac{2015}{2016}>\frac{2015}{2016+2017}\)VÀ \(\frac{2016}{2017}>\frac{2016}{2016+2017}\)
\(\Rightarrow\)\(\frac{2015}{2016}+\frac{2016}{2017}>\frac{2015}{2016+2017}+\frac{2016}{2016+2017}\)
\(\Rightarrow\)\(\frac{2015}{2016}+\frac{2016}{2017}>\frac{2015+2016}{2016+2017}\)
\(\Rightarrow A>B\)
Vậy: \(A>B\)
\(\frac{2015+2016}{2016+2017}=\frac{2015}{2016+2017}+\frac{2016}{2016+2017}\)
\(\frac{2015}{2016}>\frac{2015}{2016+2017}\)
\(\frac{2016}{2017}>\frac{2016}{2016+2017}\)
\(A>B;\frac{2015}{2016}+\frac{2016}{2017}>\frac{2015+2016}{2016+2017}\)
\(\frac{1}{6}.\frac{1}{3}+\frac{17}{6}.\frac{1}{3}+\frac{2015}{2016}-1\)
\(=\frac{1}{3}\left(\frac{1}{6}+\frac{17}{6}\right)+\frac{2015}{2016}-1\)
\(=\frac{1}{3}.3+\frac{2015}{2016}-1\)
\(=1-1+\frac{2015}{2016}=\frac{2015}{2016}\)
\(\frac{1}{6}\times\frac{1}{3}+\frac{17}{6}\times\frac{1}{3}+\frac{2015}{2016}-1\)
\(=\left(\frac{1}{6}+\frac{17}{6}\right)\times\frac{1}{3}+\frac{2015}{2016}-1\)
\(=3\times\frac{1}{3}+\frac{2015}{2016}-1\)
\(=1+\frac{2015}{2016}-1\)
\(=0+\frac{2015}{2016}=\frac{2015}{2016}\)
Theo mik là bỏ 2015
<=> \(\frac{2017-1}{2014+2016}\)
\(=\frac{2016}{4030}\)
= ??? (bạn tự rút gọn nhé)
a)\(\frac{2013}{2015}< \frac{2014}{2016}\)
b)\(\frac{2013+2014}{2014+2015}< \frac{2013}{2014}+\frac{2014}{2015}\)
Ta có:
\(2016^{0^{2015}}+1=1+1=2\)
sau chu so 02015 no doc doc vay ban
2016^0^2015=1
=> 2016^0^2015+1=1+1=2 nhé!
\(2016^{0^{2015}}=1\) nên 1+1=2
= 1 + 1 = 2
\(2016^{0^{2015}}+1=\left(2016^0\right)^{2015}+1=1^{2015}+1=1+1=2\)
=20161+1=2016+1=2017
bằng 2 mha
\(2016^{0^{2015}}+1=1+1=2\)
đung ko bạn wá dễ
20160^2015+1= (20160)2015+1=12015+1=1+1=2
\(2016^{0^{2015}}+1=1^{2015}+1=2\)
day ma toan lop 5
\(2016^{0^{2015}}+1=2016^0+1=1+1=2\)
k hộ mik