làm hộ tớ với

Để tính giá trị của biểu thức 1/3 - 3/4 - (-3/5) + 1/64 - (-2/9) - 1/36 + 1/15, ta thực hiện các phép tính theo thứ tự từ trái qua phải:

1/3 - 3/4 = 4/12 - 9/12 = -5/12
-5/12 - (-3/5) = -5/12 + 3/5 = -25/60 + 36/60 = 11/60
11/60 + 1/64 = 11/60 + 1/64 = 704/3840 + 45/3840 = 749/3840
749/3840 - (-2/9) = 749/3840 + 256/1152 = 749/3840 + 256/1152 = 2881/11520
2881/11520 - 1/36 = 2881/11520 - 320/11520 = 2561/11520
2561/11520 + 1/15 = 2561/11520 + 768/11520 = 3329/11520

Vậy giá trị của biểu thức là 3329/11520.

\(\dfrac{1}{3}-\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{1}{64}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)

\(=\left(\dfrac{1}{3}-\dfrac{2}{9}-\dfrac{1}{36}\right)+(-\dfrac{3}{4}+\dfrac{1}{64})+(-\dfrac{3}{5}+\dfrac{1}{15})\)

\(=\left(\dfrac{12}{36}-\dfrac{8}{36}-\dfrac{1}{36}\right)+\left(-\dfrac{48}{64}+\dfrac{1}{64}\right)+(-\dfrac{9}{15}+\dfrac{1}{15})\)

\(=\dfrac{1}{12}+\dfrac{-47}{64}-\dfrac{8}{15}=\dfrac{80}{960}-\dfrac{705}{960}-\dfrac{512}{960}\)

\(\dfrac{80-705-512}{960}=-\dfrac{1137}{960}=-\dfrac{379}{320}\)

sai đề hay sao í

Mk trả lời câu hỏi này mà

15: A= 1/3-3/4+3/5+1/2007-1/36+1/15-2/9

Sửa đề: 

A=-3/4-2/9-1/36+1/3+3/5+1/15+1/2007

=-27/36-8/36-1/36+5/15+9/15+1/15+1/2007

=-1+1+1/2007=1/2007

16:

\(A=\dfrac{1}{3}+\dfrac{3}{5}+\dfrac{1}{15}-\dfrac{3}{4}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{64}\)

\(=\dfrac{5+9+1}{15}+\dfrac{-27-8-1}{36}+\dfrac{1}{64}\)

=1/64

17:

=1/2-1/2+2/3-2/3+3/4-3/4+4/5-4/5+5/6-5/6-6/7

=-6/7

a) \(\frac{1}{3}-\frac{3}{4}-\left(\frac{-3}{5}\right)+\frac{1}{64}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)

=\(\left(\frac{1}{3}+\frac{3}{5}+\frac{1}{15}\right)-\left(\frac{3}{4}+\frac{2}{9}+\frac{1}{36}\right)+\frac{1}{64} \)

=\(\frac{5+9+1}{15}-\frac{27+8+1}{36}+\frac{1}{64}\)

= \(1+1+\frac{1}{64}=2\frac{1}{64}\)

a: \(\left(5+\frac15-\frac29\right)-\left(2-\frac{1}{23}-\frac{3}{35}+\frac56\right)-\left(8+\frac27-\frac{1}{18}\right)\)

\(=5+\frac15-\frac29-2+\frac{1}{23}+\frac{3}{35}-\frac56-8-\frac27+\frac{1}{18}\)

\(=\left(5-2-8\right)+\left(\frac15+\frac{3}{35}-\frac27\right)+\left(-\frac29-\frac56+\frac{1}{18}\right)+\frac{1}{23}\)

\(=\left(-5\right)+\left(\frac{7}{35}+\frac{3}{35}-\frac{10}{35}\right)+\left(-\frac{4}{18}-\frac{15}{18}+\frac{1}{18}\right)+\frac{1}{23}\)

\(=-5+\left(-\frac{18}{18}\right)+\frac{1}{23}=-6+\frac{1}{23}=-\frac{138}{23}+\frac{1}{23}=-\frac{137}{23}\)

c: \(-\frac57-\left(-\frac{5}{67}\right)+\frac{13}{10}+\frac12+\left(-\frac16\right)+1\frac{3}{14}-\left(-\frac25\right)\)

\(=-\frac57+\frac{5}{67}+\frac{13}{10}+\frac12-\frac16+\frac{17}{14}+\frac25\)

\(=\left(-\frac57+\frac{17}{14}+\frac12\right)+\left(\frac{13}{10}+\frac25-\frac16\right)+\frac{5}{67}\)

\(=\left(-\frac{10}{14}+\frac{17}{14}+\frac12\right)+\left(\frac{13}{10}+\frac{4}{10}-\frac16\right)+\frac{5}{67}\)

\(=\left(\frac{7}{14}+\frac12\right)+\left(\frac{17}{10}-\frac16\right)+\frac{5}{67}=1+\frac{5}{67}+\frac{51}{30}-\frac{5}{30}\)

\(=\frac{72}{67}+\frac{46}{30}=\frac{72}{67}+\frac{23}{15}=\frac{2621}{1005}\)

d: \(\frac35:\left(-\frac{1}{15}-\frac16\right)+\frac35:\left(-\frac13-1\frac{1}{15}\right)\)

\(=\frac35:\left(-\frac{2}{30}-\frac{5}{30}\right)+\frac35:\left(-\frac{5}{15}-\frac{16}{15}\right)\)

\(=\frac35:\left(-\frac{7}{30}\right)+\frac35:\left(-\frac{21}{15}\right)\)

\(=\frac35\cdot\frac{-30}{7}+\frac35\cdot\frac{-5}{7}=\frac35\cdot\left(-\frac{30}{7}-\frac57\right)\)

\(=\frac35\cdot\left(-\frac{35}{7}\right)=\frac35\cdot\left(-5\right)=-3\)

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