1a, (-3,8) + [ (-5,7)+3,8]

= (-3,8+3,8) -5,7

= -5,7

b, 31,4 +[6,4 +(-18)]

= 31,4 - 11,6

= 19,8

c,[(9,6 )+4,5 ] +[9,6 +(-1,5)]

= 9,6 +9,6 +(4,5-1,5)

= 19,2 +3

=22,2

d, [ (-4,9) + (-7,8)] +[1,9+2,8]

= (-4,9 +1,9)+ (-7,8+2,8)

= -3 -5

=-8

e, (3,1-2,5)-(-2,5+3,1)

= (3,1-3,1)+(2,5-2,5)

=0

f, (5,3 -2,8 )- (4+5,3)

= (5,3-5,3) -2,8-4

= -6,8

g, -(251,3 +281 )+ 3,251 -(1-281)

= -251,3-281+3,251 -1+281

= (-281+281) -251,3 +3,251 -1

= -249,049

h,-(3/54+3/4)-(-3/4 +2/5)

= -3/54-3/4 +3/4 +2/5

=(-3/4+3/4) -3/54 +2/5

=123/270

chúc bạn học tốt

lấy mt bấm phắt là ra

a) \(\left|2,5-x\right|-1,3=0\)

th1: \(2,5-x\ge0\Leftrightarrow x\le2,5\)

\(\Rightarrow\left|2,5-x\right|-1,3=0\Leftrightarrow2,5-x-1,3=0\Leftrightarrow x=1,2\left(tmđk\right)\)

th2: \(2,5-x< 0\Leftrightarrow x>2,5\)

\(\Rightarrow\left|2,5-x\right|-1,3=0\Leftrightarrow x-2,5-1,3=0\Leftrightarrow x=3,8\left(tmđk\right)\)

vậy \(x=1,2;x=3,8\)

b) \(1,6.\left|x-0,2\right|=0\Leftrightarrow\left|x-0,2\right|=0\Leftrightarrow x-0,2=0\Leftrightarrow x=0,2\) vậy \(x=0,2\)

c) \(\left|\dfrac{1}{3}-x\right|-\left|\dfrac{-3}{7}\right|=0\)

th1: \(\dfrac{1}{3}-x\ge0\Leftrightarrow x\le\dfrac{1}{3}\)

\(\Rightarrow\left|\dfrac{1}{3}-x\right|-\left|\dfrac{-3}{7}\right|=0\Leftrightarrow\dfrac{1}{3}-x-\dfrac{3}{7}=0\Leftrightarrow x=\dfrac{-2}{21}\left(tmđk\right)\)

th2: \(\dfrac{1}{3}-x< 0\Leftrightarrow x>\dfrac{1}{3}\)

\(\Rightarrow\left|\dfrac{1}{3}-x\right|-\left|\dfrac{-3}{7}\right|=0\Leftrightarrow x-\dfrac{1}{3}-\dfrac{3}{7}=0\Leftrightarrow x=\dfrac{16}{21}\left(tmđk\right)\)

vậy \(x=\dfrac{-2}{21};x=\dfrac{16}{21}\)

d) \(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

th1: \(x+\dfrac{4}{15}\ge0\Leftrightarrow x\ge\dfrac{-4}{15}\)

\(\Rightarrow\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\Leftrightarrow x+\dfrac{4}{15}-3,75=-2,15\)

\(\Leftrightarrow x=\dfrac{4}{3}\left(tmđk\right)\)

th2: \(x+\dfrac{4}{15}< 0\Leftrightarrow x< \dfrac{-4}{15}\)

\(\Rightarrow\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\Leftrightarrow-x-\dfrac{4}{15}-3,75=-2,15\)

\(\Leftrightarrow x=\dfrac{-28}{15}\left(tmđk\right)\)

vậy \(x=\dfrac{4}{3};x=\dfrac{-28}{15}\)

e) ta có : \(\left|x-1,5\right|\ge0\forall x\) và \(\left|2,5-x\right|\ge0\forall x\)

\(\Rightarrow\left|x-1,5\right|+\left|2,5-x\right|=0\Leftrightarrow\left\{{}\begin{matrix}x-1,5=0\\2,5-x=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=1,5\\x=2,5\end{matrix}\right.\) 2 giá trị này khác nhau \(\Rightarrow\) phương trình vô nghiệm

bài 1 :
b) (x-1/2 )² = 0
<=> x - 1/2 = 0
<=> x = 0+ 1/2
<=> x = 1/2
c) ( x - 2 ) ² = 1
<=> x -2 = 1
<=> x = 1 +2 = 3
d) ( 2x -1 )³ = -8
<=> ( 2x - 1) ³ = ( -2 ) ³
<=> 2x - 1 = -2
<=> 2x = -2+1 = -1
<=> x = -1/2

Bài 2 :
c) 3^2x-1=243
<=> 3^2x-1= 3⁵
<=> 2x-1 = 5
<=> 2x = 6
<=> x = 6:2 = 3

Mk chỉ giải đc như vậy thôi
bạn thông cảm nhé !

mấy câu kia cần nữa k

trả lời nhanh nha!!!

Hồng Phúc Nguyễn bn hk cx giỏi nhỉ bn giúp mk bài này nha

xin bn đấy!!!

cảm on bạn

mình làm lại câu b) nha

b) |x-3|=-4

th1: x-3=-4

x=3+(-4)

x=-1

th2: x-3=4

x=3+4

x=7

b) \(\left|x-3\right|=-4\)

t/h1:\(x-3=-4\)

\(x=3-\left(-4\right)\)

\(x=7\)

t/h2:\(x-3=4\)

\(x=3-4\)

\(x=-1\)

a: \(=0.5\cdot10-\dfrac{1}{7}+15=20-\dfrac{1}{7}=\dfrac{139}{7}\)

b: \(=6\cdot\dfrac{-2}{3}+12\cdot\dfrac{4}{9}+18\cdot\dfrac{-8}{27}\)

\(=-4+\dfrac{16}{3}-\dfrac{16}{3}=-4\)

c: \(=\left(\dfrac{5}{2}+\dfrac{3}{8}-\dfrac{5}{8}+\dfrac{2}{3}\right):\left(\dfrac{17}{2}+\dfrac{49}{4}-\dfrac{17}{8}+\dfrac{34}{15}\right)\)

\(=\dfrac{35}{12}:\dfrac{2507}{120}=\dfrac{350}{2507}\)

a: \(\left(x-2,5\right)^2=-27\)

mà \(\left(x-2,5\right)^2\ge0\forall x\)

nên x∈∅

b: \(81^{x}:3^{x}=9\)

=>\(\left(\frac{81}{3}\right)^{x}=9\)

=>\(27^{x}=9\)

=>\(\left(3^3\right)^{x}=3^2\)

=>\(3^{3x}=3^2\)

=>3x=2

=>\(x=\frac23\)

c: \(\left(2x+1\right)^2=64\)

=>\(\left[\begin{array}{l}2x+1=8\\ 2x+1=-8\end{array}\right.\Rightarrow\left[\begin{array}{l}2x=7\\ 2x=-9\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac72\\ x=-\frac92\end{array}\right.\)

d: \(2^{4-x}=16\)

=>\(2^{4-x}=2^4\)

=>4-x=4

=>x=4-4=0

bằng 1