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1/2+1/6+1/12+1/20+1/30=5/6
2/3+2/15+2/35+2/63+2/99=10/11
a) 1/2+1/6+1/12+1/20+1/30 = 5/6
b ) 2/3+2/15+2/35+2/63+2/99 = 10/11
tk m nhé
Tk mình đi mọi người mình bị âm nè!
ai tk mình mình tk lại cho!!!
( 1/13 + 1/15 + 1/35 + 1/63 + 1/99 ) x X = 2/3
X = 2/3 : ( 1/13 + 1/15 + 1/35 + 1/63 + 1/99 )
X = 286/85
k mình đi mình đang bị âm
1/15+1/35+1/63+1/99+1/143
=1/3.5+1/5.7+1/7.9+1/9.11+1/11.13
=1/2.(2/3.5+2/5.7+2/7.9+2/9.11+2/11.13
=1/2.(1/3-1/5+1/5-1/7+1/6-1/9+1/9-1/11+1/11-1/13=1/2.(1/3-1/13)=1/2.10/39=5/39
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\)
\(=1-\left(\frac{1}{2}-\frac{1}{2}\right)-\left(\frac{1}{3}-\frac{1}{3}\right)-......-\left(\frac{1}{6}-\frac{1}{6}\right)-\frac{1}{7}\)
\(=1-\frac{1}{7}\)
\(=\frac{6}{7}\)
1/2+1/6+1/12+1/20+1/30+1/42
=1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7
=1-1/7
=6/7
\(\frac{2}{3}.\frac{3}{4}.\frac{4}{5}=\frac{2}{3}.\frac{3}{4}.\frac{4}{5}\)
=> 1=1
\(\frac{1}{3}\) \(+\) \(\frac{1}{15}\) \(+\) \(\frac{1}{35}\) \(+\) \(\frac{1}{63}\) \(+\) \(\frac{1}{99}\)
\(=\) \(\frac{5}{11}\)
\(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}\)
\(=\frac{5}{11}\)
1\(\frac{1}{3}+\frac{1}{5x3}+\frac{1}{5x7}+\frac{1}{9x7}+\frac{1}{9x11}=\frac{1+1+1+1+1}{11}=\frac{5}{11}\)
\(=\frac{1}{1\times3}+\frac{1}{3\times5}+\frac{1}{5\times7}+\frac{1}{7\times9}+\frac{1}{9\times11}\)
\(=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
\(=\frac{1}{2}\left(1-\frac{1}{11}\right)\)
\(=\frac{1}{2}\times\frac{10}{11}=\frac{5}{11}\)
1/3+1/15+1/35+1/63+1/99=5/11
31 ++ \frac{1}{15}151 ++ \frac{1}{35}351 ++ \frac{1}{63}631 ++ \frac{1}{99}991
== \frac{5}{11}115