13+4389+4
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xy + 3y + x = 4
xy + 3y + x + 1 = 4 + 1
(xy + 3y) + (x + 1) = 4 + 1
y(x+ 1) + (x+ 1) = 4
(x+ 1)(y + 1) = 4
4 = 2\(^2\); Ư(4) = {-4; - 2; - 1; 1; 2 ; 4}
Lập bảng giá trị ta có:
x+1 | -4 | -2 | -1 | 1 | 2 | 4 |
x | -5 | -3 | -2 | 0 | 1 | 3 |
y+1 | -1 | -2 | -4 | 4 | 2 | 1 |
y | -2 | -3 | -5 | 3 | 1 | 0 |
x;y∈Z | tm | tm | tm | tm | tm | tm |
Theo bảng trên ta có: x; y là:
(x; y) = (-5; -2); (-3; -3); (-2; -5); (0; 3); (1; 1) (3; 0)
Vậy các cặp số nguyên x; y thỏa mãn đề bài là:
(x; y) = (-5; -2); (-3; -3); (-2; -5); (1; 1); (3; 0)
1 The fatter she gets, the more tired she feels
2 The older she gets, the less he wants to travel
3 The more difficult the games are, the more excited the children are
4 The faster people drive, the more accidents happen
5 The more I meet him, the more I hate him
6 The less time my boss has, the better he works
He has read that novel many times before
When you come back, he has already bought the house
a = \(\frac{4a-5b}{6a+b}\) (1) và \(\frac{a}{b}=\frac23\)
Giải:
\(\frac{a}{b}=\frac23\) suy ra: a = \(\frac{2b}{3}\)
Thay a = 2b/3 vào (1) ta có:
2b/3 = \(\frac{\frac{4.2b}{3}-5b}{\frac{6.2b}{3}+b}\) = \(\frac{b.\left(\frac83-5\right)}{b.\left(4+1\right)}\) = (\(\frac83-\frac{15}{3}):5\) = - \(\frac73\times\frac15\) = - 7/15
b = - 7/15 : (2/3) = - \(\frac{7}{10}\)
a = 2b/3 = (-7/10) x (2/3) = -7/15
Vậy a = - 7/15; b = - 7/10
ba=32 suy ra: a = \(\frac{2 b}{3}\)
Thay a = 2b/3 vào (1) ta có:
2b/3 = \(\frac{\frac{4.2 b}{3} - 5 b}{\frac{6.2 b}{3} + b}\) = \(\frac{b . \left(\right. \frac{8}{3} - 5 \left.\right)}{b . \left(\right. 4 + 1 \left.\right)}\) = (\(\frac{8}{3} - \frac{15}{3} \left.\right) : 5\) = - \(\frac{7}{3} \times \frac{1}{5}\) = - 7/15
b = - 7/15 : (2/3) = - \(\frac{7}{10}\)
a = 2b/3 = (-7/10) x (2/3) = -7/15
Vậy a = - 7/15; b = - 7/10
\(\frac{208}{384}\) = a - \(\frac{2}{24}\)
\(\frac{13}{24}\) = a - \(\) \(\frac{2}{24}\)
a = \(\frac{13}{24}+\frac{2}{24}\)
a = \(\frac{15}{24}\)
a = \(\frac58\)
13 + 4389 + 4
= (11 + 4389) + (2 + 4)
= 4400 + 6
= 4406
4406