= 1/10

tinh nhu cc

Ta có: \(x=5\cdot2^{2020}-5\cdot2^{2018}+5\cdot2^{2016}-\cdots-5\cdot2^6+5\cdot2^4-5\cdot2^2+5\)

\(=5\left(2^{2020}-2^{2018}+2^{2016}-2^{2014}+\cdots+2^4-2^2+1\right)\)

Đặt \(A=2^{2020}-2^{2018}+2^{2016}-2^{2014}+\cdots+2^4-2^2+1\)

=>\(4A=2^{2022}-2^{2020}+2^{2018}-2^{2016}+\cdots+2^6-2^4+2^2\)

=>\(4A+A=2^{2022}-2^{2020}+2^{2018}-2^{2016}+\cdots+2^6-2^4+2^2+2^{2020}-2^{2018}+2^{2016}-2^{2014}+\cdots+2^4-2^2+1\)

=>\(5A=2^{2022}+1\)

TA có: \(x=5\left(2^{2020}-2^{2018}+2^{2016}-2^{2014}+\cdots+2^4-2^2+1\right)\)

=>x=5A

=>\(x=2^{2022}+1\)

=>\(x-y=2^{2022}+1-2^{2022}=1\)

=>x và y là hai số tự nhiên liên tiếp

đề gì thế

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ai giải hộ bài: Tìm giá trị nhỏ nhất của biểu thức giá trị tuyệt đối C = – 2|x – y + 1| – 3|y – 2| – 4. đố ai giải dc :))))

siêu dễ luôn

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