\(B=\frac{5.2^{15}.3^{30}-5.7^5.2^5.2^{12}}{5^4.2^{14}.3^{14}.3^7.3^7-2^2.3.2^{15}.7^5}\)

=> \(B=\frac{5.2^{15}.3^{30}-5.7^5.2^{17}}{5^4.2^{14}.3^{28}-2^{17}.3.7}\)

=> \(B=\frac{5.2.3^{30}-5.7^5.2^3}{5^4.3^{28}-2^3.3.7}=0,144\)

Bài 1:

a: \(A=15\cdot31\cdot2+5\cdot27\cdot6+10\cdot42\cdot3\)

\(=30\cdot31+30\cdot27+30\cdot42\)

\(=30\left(31+27+42\right)\)

\(=30\cdot100=3000\)

b: \(B=3\cdot5^2+160:\left(9-5\right)^2\)

\(=3\cdot25+160:4^2\)

=75+160:16

=75+10

=85

c: \(C=10^3\cdot\left\lbrace540-\left\lbrack6^3+\left(5\cdot4^2+104\right)\right\rbrack\right\rbrace\)

\(=1000\cdot\left\lbrace540-\left\lbrack216+5\cdot16+104\right\rbrack\right\rbrace\)

=1000{540-[216+80+104]

=1000*{540-400}

=1000*140

=140000

\(\dfrac{-8}{3}\)

=( 2¹⁹⁹⁹+2¹⁹⁹⁹.2⁵): (2¹⁹⁹⁰⁺⁹)
=2¹⁹⁹⁹.(1+2⁵): 2¹⁹⁹⁹
=2¹⁹⁹⁹.(1+2⁵): 2¹⁹⁹⁹
=2¹⁹⁹⁹. (1+2⁵): 2¹⁹⁹⁹
=1.(1+32)
=1.33
=33

 

đúng hộ mik

a, \(\dfrac{3}{5}\). (\(-\dfrac{9}{11}\)) + \(\dfrac{-3}{5}\).\(\dfrac{2}{11}\) + \(\dfrac{3}{5}\)

= \(\dfrac{3}{5}\).( - \(\dfrac{9}{11}\) - \(\dfrac{2}{11}\) + 1)

= \(\dfrac{3}{5}\).(- \(\dfrac{11}{11}\) + 1)

= \(\dfrac{3}{5}\).(1-1)

= \(\dfrac{3}{5}\).0

= 0