24^5 K+1

@Bé Bin bạn có biết cách giải không zậy

`2023xx6+7xx2023-2023`

`=2023xx(6+7-1)`

`=2023xx12=24276`

2023×6+7×2023−2023

=2023×6+7×2023−2023x1

=2023×(6+7−1)

=2023×12

=24276

2030 × 4 +2023 × 2 + 3 × 2023

 =8120 + 4046 + 6069

=18235

= 4x2023+2023x2+2023 x1 + 3x2023
=2023x (4+2+3+1)
= 2023 x 10
= 20230
cảm ơn bạn đã đọc!

Tính

C. \(\left(6^{2023}-6^{2023}\right):6^{2021}\)

\(=6^{2023}:6^{2021}-6^{2023}:6^{2021}\)

\(=6^2-6^2\)

\(=36-36\)

\(=0\)

C = (6²⁰²³ - 6²⁰²³): 6²⁰²¹

C = 0: 6²⁰²¹

C = 0

\(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}=\dfrac{1}{2023}=\dfrac{1}{a+b+c}\)

\(\dfrac{a+b}{ab}+\dfrac{a+b}{c\left(a+b+c\right)}=0\)

\(\left(a+b\right)\left(\dfrac{1}{ab}+\dfrac{1}{c\left(a+b+c\right)}\right)=0\)

\(\left(a+b\right)\left[\dfrac{ab+bc+ca+c^2}{abc\left(a+b+c\right)}\right]=0\)

\(\left(a+b\right)\left(b+c\right)\left(c+a\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}a=-b\\b=-c\\c=-a\end{matrix}\right.\)

Đến đây bạn thay vào nữa là được nhé

cảm ơn nhìu

\(\text{ 2023 x 10 - 2023 x 8 - 2023}\)

\(\text{= 2023 x (10-8-1)}\)

\(\text{= 2023 x 1}\)

\(\text{= 2028}\)

   2023 \(\times\) 10 - 2023 \(\times\) 8 - 2023

= 2023 \(\times\) 10 - 2023 \(\times\) 8 - 2023 \(\times\) 1

= 2023 \(\times\) (10 - 8 - 1)

= 2023 x 1

= 2023 

\(\dfrac{x-2023}{6}+\dfrac{x-2023}{10}+\dfrac{x-2023}{15}+\dfrac{x-2023}{21}=\dfrac{8}{21}\)

\(\left(x-2023\right)\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+\dfrac{1}{21}\right)=\dfrac{8}{21}\)

\(\left(x-2023\right).\dfrac{8}{21}=\dfrac{8}{21}\)

\(x-2023=1\)

\(x=2024\)

Vậy..............

\(...\Rightarrow\left(x-2023\right)\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+\dfrac{1}{21}\right)=\dfrac{8}{21}\)

\(\Rightarrow\left(x-2023\right)\left(\dfrac{35+21+14+1}{210}\right)=\dfrac{8}{21}\)

\(\Rightarrow\left(x-2023\right).\dfrac{71}{210}=\dfrac{8}{21}\)

\(\Rightarrow\left(x-2023\right).\dfrac{71}{210}=\dfrac{8}{21}.\dfrac{210}{71}=\dfrac{80}{71}\)

\(\Rightarrow x-2023=\dfrac{80}{71}\Rightarrow x=\dfrac{80}{71}+2023=\dfrac{143713}{71}\)

...

\(2023\times28+2023\times34-2023\times52\)

\(=2023\times\left(28+34-52\right)\)

\(=2023\times10\)

\(=20230\)

`# \text {DNamNgV}`

`2023 \times 28 + 2023 \times 34 - 2023 \times 52`

`= 2023 \times (28 + 34 - 52)`

`= 2023 \times 10 `

`=20230`

kết quả là 1022 nhé bạn