có kết quả r mà

\(a\)) \(\left(4^2.4^3\right):2^{10}\)

   \(=4^5:2^{10}\)

   \(=\left(2^2\right)^5:2^{10}\)

   \(=2^{10}:2^{10}\)

   \(=1\)  

    \(b\)) \(\left(0,6\right)^5:\left(0,2\right)^6\)

    \(=\left(\frac{3}{5}\right)^5:\left(\frac{1}{5}\right)^6\)

     \(=\frac{3^5}{5^5}:\frac{1^6}{5^6}\)

      \(=\frac{3^5}{5^5}.5^6\)

        \(=\frac{3^5.5^6}{5^5}\)

        \(=3^5.5\)

         \(=243.5\)

          \(=1215\)

 \(c\)) \(\left(2^7.9^3\right):\left(6^5.8^2\right)\)

     \(=\left[2^7.\left(3^2\right)^3\right]:\left[\left(2.3\right)^5.\left(2^4\right)^2\right]\)

      \(=\left(2^7.3^6\right):\left[2^5.3^5.2^8\right]\)

       \(=\left(2^7.3^6\right).\left(\frac{1}{2^5.3^5.2^8}\right)\)

         \(=\frac{2^7.3^6.1}{\left(2^5.2^8\right).3^5}\)

           \(=\frac{2^7.3^6}{2^{13}.3^5}\)

           \(=\frac{3}{2^6}\)

           \(=\frac{3}{64}\)

4/7 *1/3+5/7:2/3

\(\frac{4}{21}\)+ \(\frac{15}{14}\)= \(\frac{53}{42}\)

=4/21+15/14

=53/42

\(A=10^2-\left(5^2.4-4^3.3\right)+2^3\)

\(A=10^2-\left(100-4^3.3\right)+2^3\)

\(A=10^2-\left(100-192\right)+2^3\)

\(A=10^2-\left(-92\right)+2^3\)

\(A=192+2^3\)

\(A=200\)

\(\left|2x-1\right|=\dfrac{3}{2}\\ \Rightarrow\left[{}\begin{matrix}2x-1=\dfrac{3}{2}\\2x-1=-\dfrac{3}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=-\dfrac{1}{4}\end{matrix}\right.\)

Thay \(x=\dfrac{5}{4}\) vào D ta có:

\(D=4x+3=4.\dfrac{5}{4}+3=5+3=8\)

Thay \(x=-\dfrac{1}{4}\) vào D ta có:

\(D=4.\dfrac{-1}{4}+3=-1+3=2\)

Để \(D=\dfrac{3}{2}\)

\(\Leftrightarrow4x+3=\dfrac{3}{2}\\ \Leftrightarrow4x=-\dfrac{3}{2}\\ \Leftrightarrow x=-\dfrac{3}{8}\)

2+4+6+8+...+2014+2016

Số số hạng là:(2016-2):2+1=1008

Tống dãy trên là:(2016+2).1008:2=1017072

3+5+7+9+...+2013

Số số hạng là:(2013-3):2+1=1006

Tổng dãy trên là:(2013+3).1006:2=1014048

(2+4+6+8+...+2014+2016)-(3+537393...+2013)=1017072-1014048=3024

nhớ k nha

3/8 + 1/2 = 7/8

9/8 - 1/6 = 23/24

a: =1/2(3/4+1)=1/2x7/4=7/8

b: =9/8-1/6=27/24-4/24=23/24

Để biểu thức đề bài cho có giá trị nguyên thì \(5\sqrt{x}-6⋮2\sqrt{x}-3\)

\(\Leftrightarrow10\sqrt{x}-12⋮2\sqrt{x}-3\)

\(\Leftrightarrow2\sqrt{x}-3\in\left\{-3;-1;1;3\right\}\)

\(\Leftrightarrow2\sqrt{x}\in\left\{0;2;4;6\right\}\)

hay \(x\in\left\{0;1;4;9\right\}\)