30:17=
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(-4) + (-440) + (-6) + 440 = -4 - 440 - 6 + 440 = -10
(17 - 30) - (2015 + 17 - 30) = 17 - 30 - 2015 - 17 + 30 = 17 - 17 - 30 + 30 - 2015 = -2015
13 + 21.5 - (198 : 11 - 8)
= 13 + 105 - 10
= 108
272 : 16 - 5 +4 (30 - 5 - 255 : 17)
= 17 - 5 + 4. ( 30 - 5 - 15 )
= 16 . 10
= 160
15.24 - 14.5 (145 : 5 - 27)
= 360 - 70 ( 29 - 27 )
= 290 . 2
= 580
18.3 - 18.2 + 3 (51 : 17)
= 54 - 36 + 3 . 3
= 54 - 36 + 9
= 27
(64 + 115 + 36) - 25.8
= 215 - 200
= 15
15.8 - (17 - 30 + 83) - 144 : 6
= 120 - 70 - 24
= 26
250 : 50 - (46 - 75 + 54) : 5
= 5 - 25 : 5
= 5 - 5
= 0
13 (17 - 95 + 83) : 5 - 18 : 9
= 13. 5 : 5 - 2
= 65 : 5 - 2
= 13 - 2
= 11
140 - 180(47 - 90 + 43) + 7
= 140 - 180 . 0 + 7
= 140 + 7
= 147
24 (15 + 30 + 85 - 120):10
= 24. 10 : 10
= 240 : 10
= 24
27 + 73 - 30 : (25 -10)
= 27 + 73 - 30 : 15
= 27 + 73 - 2
= 98
18 - 4 (27 - 90 + 73) : 10
= 18 - 4. 10 : 10
= 18 - 40 : 10
= 18 - 4
= 14
Bài 2: Tính
140 - [ 25 : (4 mũ 2 - 11) + 4 ]
= 140 - [25 : (16 - 11) + 4 ]
= 140 - [ 25 : 5 + 4 ]
= 140 - [ 5 + 4]
= 140 - 9
= 131
a,(-17)+5+8+17=[(-17)+17]+5+8=0+13=13
b. 30+12+(-20)+(-12)=[12+(-12)]+30+(-20)=0+10=10
Nho k minh nha
a: \(17\cdot85+15\cdot17-120\)
\(=17\left(85+15\right)-120\)
=1700-120
=1580
b: \(2^3\cdot17-2^3\cdot14\)
\(=2^3\left(17-14\right)\)
\(=8\cdot3=24\)
c: \(20-\left\lbrack30-\frac{\left(5-1\right)^2}{2}\right\rbrack\)
\(=20-30+\frac{4^2}{2}\)
\(=-10+\frac{16}{2}=-10+8=-2\)
d: \(80-\left(4\cdot5^2-3\cdot2^2\right)\)
\(=80-\left(4\cdot25-3\cdot4\right)\)
=80-100+12
=92-100
=-8
e: \(27\cdot77+24\cdot27-27\)
\(=27\left(77+24-1\right)\)
\(=27\cdot100=2700\)
f: \(174:\left\lbrace2\cdot\left\lbrack36+\left(4^2-23\right)\right\rbrack\right\rbrace\)
\(=\frac{174}{2\cdot\left(36+16-23\right)}=\frac{87}{52-23}=\frac{87}{29}=3\)
\(\left(\frac{17}{28}+18.29+\frac{19}{30}+\frac{30}{31}\right).\left(\frac{-5}{12}+\frac{1}{4}+\frac{1}{6}\right)\)
\(=\left(\frac{17}{28}+18.29+\frac{19}{30}+\frac{30}{31}\right).\left(\frac{-5}{12}+\frac{3}{12}+\frac{2}{12}\right)\)
\(=\left(\frac{17}{28}+18.29+\frac{19}{30}+\frac{30}{31}\right).\left(\frac{-2}{12}+\frac{2}{12}\right)\)
\(=\left(\frac{17}{28}+18.29+\frac{19}{30}+\frac{30}{31}\right).0\)
\(=0\)
a) 2 + (-25) + 41+ (-2) + 25 +(-41)
= (-2 + 2) + (-25 + 25) + (-41 +41)
=0 + 0 + 0
=0
b) 10+ ( -17) +5 + (-7)+ 17 + (-15)
= (-15+10+5) + (-17+7) + 7
= 0 + 0 + 7
= 7
c)(-22) + (-14) + 17 + (-24) + 13+ 30
= [(-22) + (-14) + (-24)] + (17 + 13 + 30)
=-60 + 60
=0
a) 2 + (-25) + 41+ (-2) + 25 +(-41)
= (-2 + 2) + (-25 + 25) + (-41 +41)
=0 + 0 + 0
=0
30/17
30 : 17 = 1 dư 13
30 : 17 = \(\frac{30}{17}\)