10-3+15-8+5+3+8426+41-5-2+41+58-32-2+562+885+852-56
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9: \(=5\cdot9+14\cdot8-40=45+112-40=5+112=117\)
10: \(=215+\left(-38+58\right)+\left(90-852\right)\)
\(=215+20+90-852\)
=-527
a;(18 - 9 x 2)x (2+ 4 + 6 + 8 + 10)
= (18 - 18)x (2+ 4 + 6+ 8 +10)
= 0 x (2+ 4+ 6+ 8 + 10)
= 0
b; (7 x 8 -56): (2+ 4 + 6 +8 + 112)
= (56 - 56) : (2 +4 +6+ 8+ 112)
= 0 : (2 + 4+ 6 + 8+ 112)
= 0
c; (2 + 125 + 6 + 145 + 112) x (42 - 6 x 7)
= (2+ 125+ 6 + 145+ 112) x (42 - 42)
= (2 + 125+ 6 + 145+ 112) x 0
= 0
Câu d:
(12 x 6 - 12 x 4 - 12 x 2) x (347 + 125)
= 12x(6 - 4 -2) x (347 + 125)
= 12 x (2 - 2) x (347 + 125)
= 12 x 0 x (347 + 125)
= 0 x (347 + 125)
= 0
3)\(\dfrac{-41}{32}\left(\dfrac{15}{8}-\dfrac{16}{41}\right)+\dfrac{15}{8}\left(\dfrac{41}{32}-\dfrac{8}{3}\right)\)
=\(\dfrac{-41}{32}.\dfrac{15}{8}-\dfrac{-41}{32}.\dfrac{16}{41}+\dfrac{15}{8}.\dfrac{41}{32}-\dfrac{15}{8}.\dfrac{8}{3}\)
=\(\left(\dfrac{-41}{32}.\dfrac{15}{8}+\dfrac{15}{8}.\dfrac{41}{32}\right)+\dfrac{-16}{41}.\dfrac{-41}{32}-\dfrac{15}{8}.\dfrac{8}{3}\)
=\(0+\dfrac{1}{2}-5=\dfrac{-9}{2}\)
4)\(\dfrac{13}{29}\left(\dfrac{29}{5}-\dfrac{45}{8}\right)-\dfrac{45}{8}\left(\dfrac{9}{8}-\dfrac{13}{29}\right)\)
=\(\dfrac{13}{29}.\dfrac{29}{5}-\dfrac{45}{8}.\dfrac{13}{29}-\dfrac{45}{8}.\dfrac{9}{8}-\dfrac{45}{8}.\dfrac{13}{29}\)
=\(\left(\dfrac{45}{8}.\dfrac{13}{29}-\dfrac{45}{8}.\dfrac{13}{29}\right)-\dfrac{13}{29}.\dfrac{29}{5}-\dfrac{45}{8}.\dfrac{9}{8}\)
=\(0-\dfrac{13}{5}-\dfrac{405}{64}=\dfrac{-2857}{320}\)
a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)
=>\(\left[2\left(10-x\right)+51\right]:3=5\)
=>\(\left[2\left(10-x\right)+51\right]=15\)
=>\(2\left(10-x\right)=15-51=-36\)
=>10-x=-36/2=-18
=>\(x=10-\left(-18\right)=10+18=28\)
b: \(\left(x-12\right)-15=20-\left(17+x\right)\)
=>\(x-12-15=20-17-x\)
=>\(x-27=3-x\)
=>\(2x=30\)
=>\(x=\dfrac{30}{2}=15\)
c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)
=>\(720-\left[41-2x+5\right]=8\cdot5=40\)
=>\(\left[41-2x+5\right]=720-40=680\)
=>-2x+46=680
=>-2x=680-46=634
=>\(x=\dfrac{634}{-2}=-317\)

=10821
10.790