\(\left(-17\right)+5+5+17\)

\(=\left(-12\right)+5+17\)

\(=\left(-7\right)+17\)

\(=10\)

(-17)+5+8+17

=-17+17+5+8+=0+13.

=13

ai k mình mình k lại

`31/17+(-5/13)+(-8/3)-14/17`

`=(31/17-14/17)-(5/13-8/3)`

`=17/17-(15/39-104/39)`

`=1-(-89/39)`

`=1+89/39`

`=39/39+89/39`

`=128/39`

\(1\dfrac{14}{15}-\dfrac{5}{17}-\dfrac{12}{17}-\dfrac{14}{15}\\ =\left(1\dfrac{14}{15}-\dfrac{14}{15}\right)-\left(\dfrac{5}{17}+\dfrac{12}{17}\right)\\ =\left[1+\left(\dfrac{14}{15}-\dfrac{14}{15}\right)\right]-1=1-1=0\)

\(=\dfrac{11}{17}:\dfrac{19}{40}+\dfrac{11}{17}:\dfrac{23}{20}=\dfrac{11}{17}\cdot\left(\dfrac{40}{19}+\dfrac{20}{23}\right)=\dfrac{11}{17}\cdot\dfrac{1300}{437}=\dfrac{14300}{7429}\)

1) \(\left(3x-1\right)\left(2x+7\right)-\left(12x^3+8x^2-14x\right):2x\)

\(=6x^2+19x-7-6x^2-4x+7=15x\)

2) \(\left(63^3-37^3\right):26+63.37\)

\(=\left(63-37\right)\left(63^2+63.37+37^2\right):26+63.37\)

\(\left[26\left(63^2+63.37+37^2\right)\right]:26+63.37\)

\(63^2+2.63.37+37^2=\left(63+37\right)^2=100^2=10000\)

17+5(-17)

=17.1+5(-17)

=-17.(-1)+5.(-17)

=-17.(-1+5)

=-17.4

=-68

k nah...^_^...kb nữa!!!

17 + 5(-17)

= 17 + (-5) . 17

= 17 . [(-5 + 1]

= 17 . (-4)

= -68

a) 5.2² - 18 : 3

= 5.4 - 18 : 9

= 20 - 2

= 18

b) 17 . 85 + 15 . 17 - 120

= 17 . (85 + 15) - 120

= 17 . 100 - 120

= 1700 - 120

= 1580

c) 2³ . 17 - 2³ . 14

= 8 . 17 - 8 . 14

= 8 . (17 - 14)

= 8 . 3

= 24

a) 5 . 2² – 18 : 3² 

= 5.4 – 18 : 9

= 20 – 2

= 18

b) 17 . 85 + 15 . 17 – 120

= 17. (85 + 15) – 120

= 17.100 – 120

= 170 – 120

= 50

c) 2³ . 17 – 2³ . 14

= 2³.(17 - 14)

= 2³.3

= 8.3

= 24

\(=\dfrac{9}{23}\left(\dfrac{5}{17}-\dfrac{22}{17}\right)+11+\dfrac{9}{23}=11\)

a: =-3/24-40/24

=-43/24

b: \(=\dfrac{6}{54}\cdot\dfrac{49}{35}=\dfrac{1}{9}\cdot\dfrac{7}{5}=\dfrac{7}{45}\)

c: \(=\dfrac{6}{5}+\dfrac{4}{3}=\dfrac{18+20}{15}=\dfrac{38}{15}\)

d: \(=\dfrac{31}{17}-\dfrac{14}{17}-\dfrac{5}{13}-\dfrac{8}{13}=1-1=0\)