2007 + 2007 + 2007 + 2007 x 4 = 14049

2007 + 2007 + 2007 + 2007 x 4 = 14049 bạn nha . 

2007 + 2007 + 2007 + 2007 + 2007 - 2007 x 5

= 2007 x 5 - 2007 x 5

= 2007 x ( 5 - 5 )

= 2007 x 0

= 0

1

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A=B

2007 + 2007 + 2007 + 2007 = 2007 x 4 = 8028

1052 + 1052 + 1052 = 1052 x 3 = 3156

\(A=x^6-2007x^5+2007x^4-2007x^3+2007x^2-2007x+2007\)

\(=x^6-2006x^5-x^5+2006x^4+x^4-2006x^3-x^3+2006x^2+x^2-2006x-x+2006+1\)

\(=x^5\left(x-2006\right)-x^4\left(x-2006\right)+x^3\left(x-2006\right)-x^2\left(x-2006\right)+x\left(x-2006\right)-\left(x-2006\right)+1\)

\(=\left(x^5-x^4+x^3-x^2+x-1\right)\left(x-2006\right)+1\)

Thay x = 2006

\(\Leftrightarrow A=1\)

Vậy A = 1 tại x = 2006

\(A=x^6-2007.x^5+2007.x^4-2007.x^3+2007.x^2-2007.x+2007\)

\(=x^6-\left(x+1\right).x^5+\left(x+1\right).x^4-...+x+1\)

\(=x^6-x^6-x^5+x^5+x^4-x^4-...-x+1\)

\(=1\)

https://hentaiz.net/

2007+2007+2007+2007 x 4

= 2007 x 3+2007 x 4

= 2007 x (3+4)

= 2007 x 7

= 14049

\(2007+2007+2007+2007\times4\)

\(=2007\times3+2007\times4\)

\(=2007\times\left(3+4\right)\)

\(=2007\times7\)

\(=14049\)

2.006/2.007 + 2.007/2.008 < 2006 + 2.007/2.007 + 2.008

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