3^x-2+3^x=270
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\(3^{x+4}+3^{x+2}=270\)
\(3^{x+2+2}+3^{x+2}=270\)
\(3^{x+2}\cdot3^2+3^{x+2}\cdot1=270\)
\(3^{x+2}\left(3^2+1\right)=270\)
\(3^{x+2}\cdot10=270\)
\(3^{x+2}=270:10\)
\(3^{x+2}=27\)
\(3^{x+2}=3^3\)
\(x+2=3\)
\(x=1\)
3x + 3x+2 = 270
=> 3x.(1 + 32) = 270
=> 3x.(1 + 9) = 270
=> 3x.10 = 270
=> 3x = 270 : 10
=> 3x = 27
=> 3x = 33
=> x = 3
\(3^x+3^{x+2}=270\)
\(=>3^x\left(1+3^2\right)=270\)
\(=>3^x.10=270\)
\(=>3^x=27\)
\(=>x=3\)
\(3^{x+2}+3^x=270\)
=> \(3^x\cdot3^2+3^x\cdot1=270\)
=> \(3^x\left(3^2+1\right)=270\)
=> \(3^x\cdot10=270\)
=> \(3^x=270:10=27\)
=> \(x=3\)
3x+2 + 3x = 270
=> 3x x 32 + 3x = 270
3x x(32 + 1) =270
3x x 10 = 270
3x = 27
3x = 33
=> x = 3
( x - 2 ) . 3 - 270 : 45 = 120
( x - 2 ) . 3 - 6 = 120
( x - 2 ) . 3 = 120 + 6
( x - 2 ) . 3 = 126
x - 2 = 126 :3
x - 2 = 42
x = 42 + 2
x = 44
\(\left(x-2\right)\times3-270:45=120\)
\(\Rightarrow\left(x-2\right)\times3-6=120\)
\(\Rightarrow\left(x-2\right)\times3=120+6\)
\(\Rightarrow\left(x-2\right)\times3=126\)
\(\Rightarrow x-2=126:3\)
\(\Rightarrow x-2=42\)
\(\Rightarrow x=42+2\)
\(\Rightarrow x=44\)
Vậy x = 44
_Chúc bạn học tốt_
\(\left(x-2\right)\cdot3-270:45=120\)
\(\left(x-2\right)\cdot3-6=120\)
\(\left(x-2\right)\cdot3=120+6\)
\(\left(x-2\right)\cdot3=126\)
\(x-2=42\)
\(x=44\)
\(\left(x-2\right).3-6=120\Leftrightarrow\left(x-2\right).3=126\Leftrightarrow x-2=42\Leftrightarrow x=44\)
3\(^{x-2}\) + 3\(^{x}\) = 270
3\(^{x-2}\) (1 + 9) = 270
3\(^{x-2}\).10 = 270
3\(^{x-2}\) = 270 : 10
3\(^{x-2}\) = 27
3\(^{x-2}\) = 3\(^3\)
\(x-2=3\)
\(x=3+2\)
\(x=5\)
Vậy \(x=5\)
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