a, \(\left|x-3\right|-16=-4\Leftrightarrow\left|x-3\right|=12\)

\(\Leftrightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}\Leftrightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}}\)

b, \(26-\left|x+9\right|=-13\Leftrightarrow\left|x+9\right|=39\)

\(\Leftrightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}\Leftrightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}}\)

f, \(9x+25=-\left(2x-58\right)\Leftrightarrow9x+25=-2x+58\)

\(\Leftrightarrow11x-33=0\Leftrightarrow x=3\)

Làm nốt nhé ! 

a. \(\left|x-3\right|-16=-4\)

\(\Rightarrow\left|x-3\right|=12\)

\(\Rightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}\)

b. \(26-\left|x+9\right|=-13\)

\(\Rightarrow\left|x+9\right|=39\)

\(\Rightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}\)

c. \(5-\left(10-x\right)=7\)

\(\Rightarrow10-x=-2\)

\(\Rightarrow x=12\)

d. \(11+\left(15-x\right)=1\)

\(\Rightarrow15-x=-10\)

\(\Rightarrow x=25\)

e. \(8x-75=5x+21\)

\(\Rightarrow8x-5x=75+21\)

\(\Rightarrow3x=96\)

\(\Rightarrow x=32\)

f. \(9x+25=-\left(2x-58\right)\)

\(\Rightarrow9x+25=-2x+58\)

\(\Rightarrow9x+2x=58-25\)

\(\Rightarrow11x=33\)

\(\Rightarrow x=3\)

g. \(\left|x+3\right|=4\)

\(\Rightarrow\orbr{\begin{cases}x+3=4\\x+3=-4\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-7\end{cases}}\)

h. \(15-\left|2x-1\right|=\left|-8\right|\)

\(\Rightarrow15-\left|2x-1\right|=8\)

\(\Rightarrow\left|2x-1\right|=7\)

\(\Rightarrow\orbr{\begin{cases}2x-1=7\\2x-1=-7\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)

a) Ta có: \(7-\left(2x+4\right)=-\left(x+4\right)\)

\(\Leftrightarrow7-2x-4=-x-4\)

\(\Leftrightarrow-2x+3+x+4=0\)

\(\Leftrightarrow-x+7=0\)

\(\Leftrightarrow-x=-7\)

hay x=7

Vậy: S={7}

b) Ta có: \(\dfrac{2+x}{5}-0.5x=\dfrac{1-2x}{4}+0.25\)

\(\Leftrightarrow\dfrac{4\left(2+x\right)}{20}-\dfrac{0.5x\cdot20}{20}=\dfrac{5\left(1-2x\right)}{20}+\dfrac{20\cdot0.25}{20}\)

\(\Leftrightarrow4\left(2+x\right)-10x=5\left(1-2x\right)+5\)

\(\Leftrightarrow8+4x-10x=5-10x+5\)

\(\Leftrightarrow-6x+8=-10x+10\)

\(\Leftrightarrow-6x+8+10x-10=0\)

\(\Leftrightarrow4x-2=0\)

\(\Leftrightarrow4x=2\)

hay \(x=\dfrac{1}{2}\)

Vậy: \(S=\left\{\dfrac{1}{2}\right\}\)

d) Ta có: \(\dfrac{x-1}{59}+\dfrac{x-2}{58}+\dfrac{x-3}{57}=\dfrac{x-59}{1}+\dfrac{x-58}{2}+\dfrac{x-57}{3}\)

\(\Leftrightarrow\dfrac{x-1}{59}-1+\dfrac{x-2}{58}-1+\dfrac{x-3}{57}-1=\dfrac{x-59}{1}-1+\dfrac{x-58}{2}-1+\dfrac{x-57}{3}-1\)

\(\Leftrightarrow\dfrac{x-60}{59}+\dfrac{x-60}{58}+\dfrac{x-60}{57}=\dfrac{x-60}{1}+\dfrac{x-60}{2}+\dfrac{x-60}{3}\)

\(\Leftrightarrow\left(x-60\right)\left(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}\right)-\left(x-60\right)\left(1+\dfrac{1}{2}+\dfrac{1}{3}\right)=0\)

\(\Leftrightarrow\left(x-60\right)\left(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}-1-\dfrac{1}{2}-\dfrac{1}{3}\right)=0\)

mà \(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}-1-\dfrac{1}{2}-\dfrac{1}{3}\ne0\)

nên x-60=0

hay x=60

Vậy: S={60}

Tính: \(=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}=\frac{11.3^{29}-3^{30}}{4.3^{28}}=\frac{3^{28}\left(11.3-3^2\right)}{4.3^{28}}=\frac{24}{4}=6\)

Tìm x:

<=> (2x-15)⁷- (2x-15)⁵=0

<=>  (2x-15)⁵  .[(2x-15)²-1]=0

<=>  (2x-15)⁵ = 0  hoặc (2x-15)²-1 = 0

+) (2x-15)⁵=0 <=> 2x - 15 = 0 <=> x = 15/2

+) (2x-15)² - 1 = 0 <=>  (2x-15)² = 1 <=> 2x - 15 = 1 <=> 2x = 16 <=> x = 8 hoặc 2x - 15 = -1 <=> 2x = 14 <=> x = 7

Vậy x = {15/2 ;  8 ; 7}

tìm chứ số tận cùng

58³³= 58.58³² = 58. (58²)¹⁶ = 58. (....4)¹⁶ = 58. (....4²)⁸ = 58. (....6)⁸  = 58 x ....6 =....8

a) \(\left(2x-1\right)+\frac{3}{15}=\frac{3}{2}\)

\(\Rightarrow2x-1=\frac{3}{2}-\frac{3}{15}=\frac{13}{10}\)

\(\Rightarrow2x=\frac{13}{10}+1=\frac{23}{10}\)

\(\Rightarrow x=\frac{23}{20}\)

b) \(x+\frac{46}{15}=1,5\)

\(\Rightarrow x+\frac{46}{15}=\frac{3}{2}\)

\(\Rightarrow x=\frac{3}{2}-\frac{46}{15}\)

\(\Rightarrow x=\frac{-47}{30}\)

c) \(\left(-2x+1\right)+\frac{3}{15}=\frac{5}{3}\)

\(\Rightarrow-2x+1=\frac{5}{3}-\frac{3}{15}=\frac{22}{15}\)

\(\Rightarrow-2x=\frac{7}{15}\Rightarrow x=\frac{-7}{30}\)

\(8x-75=5x+21\)

\(8x-5x=75+21\)

\(3x=96\)

\(x=32\)

Vậy \(x=32.\)

\(9x+25=-\left(2x-58\right)\)

\(9x+25=-2x+58\)

\(9x+2x=-25+58\)

\(11x=33\)

\(x=3\)

Vậy \(x=3.\)

\(15-\left|2x-1\right|=-8\)

\(\left|2x-1\right|=23\)

\(\Rightarrow\orbr{\begin{cases}2x-1=23\\2x-1=-23\end{cases}\Rightarrow}\orbr{\begin{cases}2x=24\\2x=-22\end{cases}}\Rightarrow\orbr{\begin{cases}x=12\\x=-11\end{cases}}\)

Vậy \(x\in\left\{12;-11\right\}\)

8x-5x=75+21

3x=96

x=32

9x+25=-2x+58

9x+2x=58-25

11x=33

x=3

1/ 3-2x+4+6x=x+7+3x

⇔-2x+6x-x-3x=0

⇔0x=0 (Vô số nghiệm)

2/-6(1,5-2x)=3(-15+2x)

⇔-9+12x=-45+6x

⇔6x+36=0

⇔6(x+6)=0

⇔x+6=0

⇔x=-6

Vậy S ϵ {-6}

3/ 3(2x-5)+5(x-1)=4(x+1)

⇔6x-15+5x-5=4x+4

⇔7x=24

⇔x=\(\dfrac{24}{7}\) 

Vậy S ϵ {\(\dfrac{24}{7}\)}

1) Ta có: \(3-2x+4+6x=x+7+3x\)

\(\Leftrightarrow4x+7=4x+7\)

\(\Leftrightarrow4x+7-4x-7=0\)

\(\Leftrightarrow0x=0\)(luôn đúng)

Vậy: S={x|\(x\in R\)}

2) Ta có: \(-6\cdot\left(1.5-2x\right)=3\left(-15+2x\right)\)

\(\Leftrightarrow-9+12x=-45+6x\)

\(\Leftrightarrow12x-9+45-6x=0\)

\(\Leftrightarrow6x+36=0\)

\(\Leftrightarrow6x=-36\)

hay x=-6

Vậy: S={-6}

3) Ta có: \(3\left(2x-5\right)+5\left(x-1\right)=4\left(x+1\right)\)

\(\Leftrightarrow6x-15+5x-5=4x+4\)

\(\Leftrightarrow11x-20-4x-4=0\)

\(\Leftrightarrow7x-24=0\)

\(\Leftrightarrow7x=24\)

\(\Leftrightarrow x=\dfrac{24}{7}\)

Vậy: \(S=\left\{\dfrac{24}{7}\right\}\)

a) 17 + x = -5 + 2x

=> x - 2x = -5 - 17

=> -x = -22

=> x = 22

b) 15 - 3x = -22 - 4x 

=> -3x + 4x = -22 - 15

=> x = -37

c) 47 - (4x + 5) = -(3x - 2)

=> 47 - 4x - 5 = -3x + 2

=> -4x + 3x = 2 - 47 + 5

=> -x = -40

=> x = 40

d) -58 + (3 - 7x) = 15 - 8x

=> -58 + 3 - 7x = 15 - 8x

=> -7x + 8x =15 + 58 - 3

=> x = 70

mình không biết cái này bác mình đưa cho mình cái đề nên mình không biết trang mấy nữa 

Mình không viết lại đề nhé!

a) 27 - x + 15 + x = x + 2

-x + x - x = 2 - 15 - 27

-x = -40

x = 40

b) 8x - 75 = 5x +21

8x - 5x = 21 + 75

3x = 96

x = 32

c) 15 - |2x - 1| = |-8|

15 - 2x + 1 = 8

-2x = 8 -1 -15

-2x = -8

x = 4 

d) 9x + 25 = -(2x - 58)

9x + 25 = -2x + 58

9x +2x = 58 - 25

7x = 33

x = 33/7