a) \(3^x\cdot3=243\)

\(\Rightarrow3^{x+1}=243\)

\(\Rightarrow3^{x+1}=3^5\)

\(\Rightarrow x+1=5\)

\(\Rightarrow x=4\)

b) \(2^x\cdot162=1024\)

Xem lại đề

c) \(64\cdot4^x=168\)

Xem lại đề

d) \(2^x=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

a: =>3^x=81

=>x=4

b: =>2^x=1024/16^2=4

=>x=2

c: =>4^x=16^8/64=4^16/4^3=4^13

=>x=13

a: \(\Leftrightarrow\left[{}\begin{matrix}x>3\\x< -4\end{matrix}\right.\)

b: -2<x<5

giải chi tiết được không ạ?

c: \(\Leftrightarrow\left(x-5\right)\left(x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)

3:

a: 3^x*3=243

=>3^x=81

=>x=4

b; 2^x*16^2=1024

=>2^x=4

=>x=2

c: 64*4^x=16^8

=>4^x=4^16/4^3=4^13

=>x=13

d: 2^x=16

=>2^x=2^4

=>x=4

a: \(6=2\cdot3;21=3\cdot7;27=3^3\)

=>BCNN(6;21;27)=\(2\cdot3^3\cdot7=14\cdot27=378\)

x∈BC(6;21;27)

=>x∈B(378)

mà x<2000

nên x∈{378;756;1134;1512;1890}

b: \(12=2^2\cdot3;15=3\cdot5;20=2^2\cdot5\)

=>BCNN(12;15;20)=\(2^2\cdot3\cdot5=4\cdot3\cdot5=12\cdot5=60\)

x∈BC(12;15;20)

=>x∈B(60)

mà 440<x<500

nên x=480

c: \(5=5;10=2\cdot5;25=5^2\)

=>BCNN(5;10;25)=\(5^2\cdot2=25\cdot2=50\)

x∈BC(5;10;25)

=>x∈B(50)

mà x<400

nên x∈{50;100;150;200;250;300;350}

d: \(3=3;5=5;6=2\cdot3;9=3^2\)

=>BCNN(3;5;6;9)=\(2\cdot3^2\cdot5=10\cdot9=90\)

x∈BC(3;5;6;9)

=>x∈B(90)

mà 150<=x<=250

nên x=180

e: \(16=2^4;21=3\cdot7;25=5^2\)

=>BCNN(16;21;25)=\(2^4\cdot3\cdot7\cdot5^2=8400\)

x∈BC(16;21;25)

=>x∈B(8400)

mà x<=400

nên x=0

f: \(5=5;7=7;8=2^3\)

=>BCNN(5;7;8)=\(5\cdot7\cdot2^3=35\cdot8=280\)

x∈BC(5;7;8)

=>x∈B(280)

mà x<=500

nên x∈{0;280}

g: \(12=2^2\cdot3;5=5;8=2^3\)

=>BCNN(12;5;8)=\(2^3\cdot3\cdot5=8\cdot3\cdot5=24\cdot5=120\)

x∈BC(12;5;8)

=>x∈B(120)

mà 60<=x<=180

nên x=120

h: \(3=3;4=2^2;5=5;10=2\cdot5\)

=>BCNN(3;4;5;10)=\(2^2\cdot3\cdot5=60\)

x∈BC(3;4;5;10)

=>x∈B(60)

mà x<200

nên x∈{60;120;180}

k: \(7=7;14=2\cdot7;21=3\cdot7\)

=>BCNN(7;14;21)=\(7\cdot2\cdot3=42\)

x∈BC(7;14;21)

=>x∈B(42)

mà x<=210

nên x∈{0;42;84;126;168;210}

a: (x+1)(y-2)=0

=>\(\begin{cases}x+1=0\\ y-2=0\end{cases}\Rightarrow\begin{cases}x=-1\\ y=2\end{cases}\)

b: (x-5)(y-7)=1

=>(x-5;y-7)∈{(1;1);(-1;-1)}

=>(x;y)∈{(6;8);(4;6)}

c: (x+4)(y-2)=2

=>(x+4;y-2)∈{(1;2);(2;1);(-1;-2);(-2;-1)}

=>(x;y)∈{(-3;4);(-2;3);(-5;0);(-6;1)}

d: (x+3)(y-6)=-4

=>(x+3;y-6)∈{(1;-4);(-4;1);(-1;4);(4;-1);(2;-2);(-2;2)}

=>(x;y)∈{(-2;2);(-7;7);(-4;10);(1;5);(-1;4);(-5;8)}

e: (x+7)(5-y)=-6

=>(x+7)(y-5)=6

=>(x+7;y-5)∈{(1;6);(6;1);(-1;-6);(-6;-1);(2;3);(3;2);(-2;-3);(-3;-2)}

=>(x;y)∈{(-6;11);(-1;6);(-8;-1);(-13;4);(-5;8);(-4;7);(-9;2);(-10;3)}

f: (12-y)(6-y)=-2

=>(x-12)(y-6)=2

=>(x-12;y-6)∈{(1;2);(2;1);(-1;-2);(-2;-1)}

=>(x;y)∈{(13;8);(14;7);(11;4);(10;5)}

a) 3\(^x\) . 3 = 243

3\(^x\) = 81

3\(^x\) = 3\(^4\)

=> = 4 

b) 64 . 4\(^x\) = 16\(^8\)

4\(^3\) . 4\(^x\) = 4\(^{16}\)

4\(^{3+x}\) = 4\(^{16}\)

=> 3 + x = 16

x = 13

Học tốt

Đúng thì t cho mk

a) 3^x . 3 = 243 

243 = 3^5 

3^4 . 3 = 234 

nên x = 4 

b) 64 . 4^x = 16^8

4^3 . 4^x = ( 4^2)^8 

4^3 . 4^x = 4^16 

4^(4+x) = 4^16 

x = 4^16 : 4^4 

x = 4^12 

x = 12

Bài 1: 

a: \(=6x^3-10x^2+6x\)

b: \(=-2x^3-10x^2-6x\)

Bài 4: 

a: =>3x+10-2x=0

=>x=-10

c: =>3x²-3x²+6x=36

=>6x=36

hay x=6

Bài 1:

\(a,=6x^3-10x^2+6x\\ b,=-2x^3-10x^2-6x\)

Bài 4:

\(a,\Leftrightarrow3x+10-2x=0\Leftrightarrow x=-10\\ b,\Leftrightarrow x\left(2x^2+9x-5\right)-\left(2x^3+9x^2+x+4,5\right)=3,5\\ \Leftrightarrow2x^3+9x^2-5x-2x^3-9x^2-x-4,5=3,5\\ \Leftrightarrow-6x=8\Leftrightarrow x=-\dfrac{4}{3}\\ c,\Leftrightarrow3x^2-3x^2+6x=36\Leftrightarrow x=6\)

Bài 1:

\(a,=7xy\left(2x-3y+4xy\right)\\ b,=x\left(x+y\right)-5\left(x+y\right)=\left(x-5\right)\left(x+y\right)\\ c,=\left(x-y\right)\left(10x+8\right)=2\left(5x+4\right)\left(x-y\right)\\ d,=\left(3x+1-x-1\right)\left(3x+1+x+1\right)\\ =2x\left(4x+2\right)=4x\left(2x+1\right)\\ e,=5\left[\left(x-y\right)^2-4z^2\right]=5\left(x-y-2z\right)\left(x-y+2z\right)\\ f,=x^2+8x-x-8=\left(x+8\right)\left(x-1\right)\\ g,\left(x+y\right)^3-\left(x+y\right)=\left(x+y\right)\left[\left(x+y\right)^2-1\right]\\ =\left(x+y\right)\left(x+y-1\right)\left(x+y+1\right)\\ h,=x^2+3x+x+3=\left(x+3\right)\left(x+1\right)\)

Bài 1: 

a: =42x53+47x42

=42x100

=4200

b: =1152-374-1152-65+374=-65

c: =(-1)+(-1)+...+(-1)+211

=211-105

=106

Giúp mik bài 2 và 3 nữa nha