\(\frac46\) + \(\frac{7}{13}\) + \(\frac{17}{9}\) + \(\frac{19}{13}\) + \(\frac19\) + \(\frac{14}{6}\)

= (\(\frac46\) + \(\frac{14}{6}\)) + (\(\frac{7}{13}\) + \(\frac{19}{13}\)) + (\(\frac{17}{9}+\frac19\))

= 3 + 2 + 2

= 5 + 2

= 7

a; \(\frac{19}{13}\) + \(\frac{14}{6}\) + \(\frac19\) + \(\frac46\) + \(\frac{7}{13}\) + \(\frac{17}{9}\)

= (\(\frac{19}{13}\) + \(\frac{7}{13}\)) + (\(\frac{14}{6}\) + \(\frac46\)) + (\(\frac19\) + \(\frac{17}{9}\))

= 2 + 3 + 2

= 5 + 2

= 7

b; \(\frac{1919}{2323}\) x \(\frac{464646}{747474}\) x \(\frac{37}{19}\)

= \(\frac{19}{23}\) x \(\frac{23}{37}\) x \(\frac{37}{19}\)

= \(\frac{19\times23\times37}{19\times23\times37}\)

= 1

Bài 1:

a) \(2\frac{1}{4}+1\frac{1}{2}-1\frac{4}{5}\)

=\(\frac{9}{4}\)+\(\frac{3}{2}\)-\(\frac{9}{5}\)

=\(\frac{45}{20}+\frac{30}{20}-\frac{36}{20}\)

=\(\frac{39}{20}\)

b) \(2\frac{2}{3}\times3\frac{1}{4}:2\frac{3}{4}\)

\(\frac{8}{3}\times\frac{13}{4}:\frac{11}{4}\)

=\(\frac{8}{3}\times\frac{13}{4}\times\frac{4}{11}\)

=\(\frac{104}{33}\)

Bài 2:

a) \(\frac{7}{9}+\frac{4}{5}+\frac{11}{9}+\frac{6}{5}\)

=\(\left(\frac{7}{9}+\frac{11}{9}\right)+\left(\frac{4}{5}+\frac{6}{5}\right)\)

=2+2

=4

b) \(\frac{21}{36}\times\frac{39}{14}\times\frac{54}{13}\)

=\(\frac{21\times39\times54}{36\times14\times13}\)

=\(\frac{675}{100}\)

dung ko ban

\(=\left(-\dfrac{1}{6}-\dfrac{5}{6}\right)+\left(\dfrac{25}{9}+\dfrac{2}{9}\right)=-1+3=2\)

Câu 6: Tính bằng cách hợp lí:

 25/9 - 1/6 + 4/18 -5/6 = (25/9+4/18)+(-1/6-5/6)

                                   =3-1

                                  =2

`4/6+7/13+17/9+19/13+1/9+14/6`

`=(4/6+14/6)+(7/13+19/13)+(17/9+1/9)`

`=18/6+26/13+18/9`

`=3+2+2`

`=7`

\(A=\dfrac{5}{11}.\dfrac{5}{7}+\dfrac{5}{11}.\dfrac{2}{7}+\dfrac{6}{11}=\dfrac{5}{11}\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\dfrac{6}{11}=\dfrac{5}{11}.1+\dfrac{6}{11}=\dfrac{5}{11}+\dfrac{6}{11}=\dfrac{11}{11}=1\)

\(B=\dfrac{3}{13}.\dfrac{6}{11}+\dfrac{3}{13}.\dfrac{9}{11}-\dfrac{3}{13}.\dfrac{4}{11}=\dfrac{3}{13}\left(\dfrac{6}{11}+\dfrac{9}{11}-\dfrac{4}{11}\right)=\dfrac{3}{13}.1=\dfrac{3}{13}\)

\(C=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right).0=0\)

a) 1 - 3 + 5 - 7 + 9 - 11

= (1 - 3) + (5 - 7) + (9 - 11)

= (-2) + (-2) + (-2)

= -6

b) -14 - 16 - 18 - ... - 92

= - (14 + 16 + 18 + .... + 92)

Áp dụng công thức tính dãy số ta có :

14 + 16 + 18 + .... + 92 = 2120

= -2120

c) 15 + 18 + 21 + .... + 63 + 66 + 70

= (15 + 18 + 21 + ..... + 66) + 70

Áp dụng công thức tính dãy số ta có :

15 + 18 + ..... + 66 = 729

= 729 + 70

= 8799

d) 2 - 3 + 4 - 5 + 6 - 7 + 8 - 9 + 10

= (2 - 3) + (4 - 5) + (6 - 7) + (8 - 9) + 10

= (-1) + (-1) + (-1) + (-1) + 10

= 6

a)1-3+5-7+9-11=-6

A=(6 : 35−116 x 67) : (415 x 1011+5211)A=(6 : 35−116 x 67) : (415 x 1011+5211)

A=(6 : 35−76 x 67) : (215 x 1011+5711)A=(6 : 35−76 x 67) : (215 x 1011+5711)

A=(10−1) : (4211+5711)A=(10−1) : (4211+5711)

A=9 : 9A=9 : 9

A=1

a) 145 + 86 + 14 + 55 = ( 145 + 55 ) + (86 + 14 )

= 200 + 100

= 300

b) 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = ( 1+9 +2 + 8) + ( 3 + 7 + 4 + 6 ) + 5

= 20 + 20 + 5

= 45