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Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
1. a) 4.415.8.25.125
= (4.25). (8.125).415
= 100.1000.415
= 100000.415
= 41500000
b) 2.31.12+4.42.6+8.27.3
= (2.31.12)+(4.42.6)+(8.27.3)
= (2.12).31+(4.6).42+(8.3).27
= 24.31+24.42+24.27
= 24 (31+42+27)
= 24.100
= 2400
7: \(\left(xy+4\right)^2-\left(2x+2y\right)^2\)
=(xy+4-2x-2y)(xy+4+2x+2y)
=[x(y-2)-2(y-2)][x(y+2)+2(y+2)]
=(x-2)(y-2)(x+2)(y+2)
8: \(81x^2-64y^2=\left(9x\right)^2-\left(8y\right)^2\)
=(9x-8y)(9x+8y)
9: \(\left(a^2+b^2+5\right)^2-4\left(ab+2\right)^2\)
\(=\left(a^2+b^2+5\right)^2-\left(2ab+4\right)^2\)
\(=\left(a^2+b^2+5-2ab-4\right)\left(a^2+b^2+5+2ab+4\right)\)
\(=\left\lbrack\left(a-b\right)^2+1\right\rbrack\left\lbrack\left(a+b\right)^2+9\right\rbrack\)
10: \(\left(x-1\right)^2-\left(x+1\right)^2\)
=(x-1-x-1)(x-1+x+1)
=2x*(-2)=-4x
11: \(8x^3-\frac18=\left(2x\right)^3-\left(\frac12\right)^3=\left(2x-\frac12\right)\left(4x^2+2x\cdot\frac12+\frac14\right)\)
\(=\left(2x-\frac12\right)\left(4x^2+x+\frac14\right)\)
12: \(\frac{1}{25}x^2-64y^2=\left(\frac15x\right)^2-\left(8y\right)^2=\left(\frac15x-8y\right)\left(\frac15x+8y\right)\)
13: \(x^3+\frac{1}{27}=x^3+\left(\frac13\right)^3=\left(x+\frac13\right)\left(x^2-\frac13x+\frac19\right)\)
a,183:93=(18-9)3=729
b,còn lại tự làm ,làm mẫu đến đây thôi
l.i.k.e cho mình nha Nguyen vu dang nguyen
mình cũng hỏi về cái này gấp nha ai biết trả lời câu nào thì trả
Bài 2:
a: \(\Leftrightarrow\left(x-5\right)\left(x+5\right)-\left(x+5\right)=0\)
=>(x+5)(x-6)=0
=>x=-5 hoặc x=6
b: \(\Leftrightarrow4x^2-4x+1-4x^2+1=0\)
=>-4x+2=0
hay x=1/2
c: \(\Leftrightarrow\left(x^2+4\right)\left(x^2-1\right)=0\)
=>x=1 hoặc x=-1
Bài 1:
\(555-5\cdot\left\lbrack409-\left(2^3\cdot3-21\right)^2-310\right\rbrack\)
\(=555-5\cdot\left\lbrack409-\left(8\cdot3-21\right)^2-310\right\rbrack\)
\(=555-5\cdot\left\lbrack409-3^2-310\right\rbrack=555-5\cdot\left(400-310\right)=555-5\cdot90\)
=555-450
=105
Bài 2:
a: \(10x+187=617^{10}:617^9\)
=>10x+187=617
=>10x=617-187=430
=>\(x=\frac{430}{10}=43\)
b: \(5^{x+2}=25^4\)
=>\(5^{x+2}=\left(5^2\right)^4=5^8\)
=>x+2=8
=>x=8-2=6
c: 2x+17⋮x+4
=>2x+8+9⋮x+4
=>9⋮x+4
=>x+4∈{1;-1;3;-3;9;-9}
=>x∈{-3;-5;-1;-7;5;-13}
a)
\(\text{( 25 – 2x )³ : 5 – 3^2 = 4^2}\)
\(\text{( 25 – 2x )³ : 5 – 9 = 16}\)
\(\text{( 25 – 2x )³ : 5 = 16 + 9}\)
\(\text{( 25 – 2x )³ : 5 = 25}\)
\(\text{( 25 – 2x )³ = 25 . 5}\)
\(\text{( 25 – 2x )³ = 125}\)
\(\text{( 25 – 2x )³ = 5³}\)
\(\text{25 – 2x = 5}\)
\(\text{2x = 25 – 5}\)
\(\text{2x = 20}\)
\(\text{x = 10}\)
\(\text{________________________________________}\)
b)
\(\text{2.3^x = 10.3^12 + 8.27^4}\)
\(\text{2.3^x = 10.3^12 + 8.(3^3)^4}\)
\(\text{2.3^x = 3^12 . (10+8)}\)
\(\text{2.3^x = 3^12 . 18}\)
\(\text{3^x = 3^12 . 18:2}\)
\(\text{3^x = 3^12 . 9}\)
\(\text{3^x = 3^12 . 3^2}\)
\(\text{3^x = 3^14}\)
\(\text{=> x=14}\)