e) 5(3-2x)+5(x-4)=6-4x

⇔15-10x+5x-20-6+4x=0

⇔-x-11=0

hay -x=11

⇔x=-11

Vậy: x=-11

g) 2(4x-8)-7(3+x)=|-4|(3-2)

⇔8x-16-21-7x=4

⇔x-37=4

hay x=41

Vậy: x=41

k) -7(5-x)-2(x-10)=15

⇔-35+7x-2x+20=15

⇔5x-15=15

hay 5x=30

⇔x=6

Vậy: x=6

m) -4(x+1)+(89x-3)=24

⇔-4x-4+89x-3=24

⇔85x-7=24

⇔85x=31

hay \(x=\frac{31}{85}\)(ktm x∈Z)

Vậy: x∈∅

q) 10(x-7)-8(x+5)=6*(-5)+24

⇔10x-70-8x-40=-6

⇔2x-110=-6

⇔2x=104

hay x=52

Vậy: x=52

Cảm ơn nhé

a) \(\dfrac{x}{5}=\dfrac{2}{5}\)

\(\Rightarrow5x=10\)

\(\Leftrightarrow x=2\)

Vậy x = 2

b) ĐKXĐ: \(x\ne0\)

 \(\dfrac{3}{-8}=\dfrac{6}{-x}\)

\(\Rightarrow-3x=-48\)

\(\Leftrightarrow x=16\)

Vậy x = 16

c) \(\dfrac{1}{9}=\dfrac{-2x}{10}\)

\(\Rightarrow-18x=10\)

\(\Leftrightarrow x=-\dfrac{5}{9}\)

Vậy \(x=-\dfrac{5}{9}\)

d) ĐKXĐ: \(x\ne0\)

 \(\dfrac{3}{x}-5=\dfrac{-9}{x}+2\)

\(\Leftrightarrow\dfrac{3-5x}{x}=\dfrac{-9+2x}{x}\)

\(\Rightarrow3-5x=-9+2x\)

\(\Leftrightarrow7x=12\)

\(\Leftrightarrow x=\dfrac{12}{7}\)

Vậy \(x=\dfrac{12}{7}\)

e) ĐKXĐ: \(x\ne0\)

 \(\dfrac{x}{-2}=\dfrac{-8}{x}\)

\(\Rightarrow x^2=16\)

\(\Leftrightarrow x=\pm4\)

Vậy \(x=\pm4\)

a) Ta có: \(\dfrac{x}{5}=\dfrac{2}{5}\)

\(\Leftrightarrow x=\dfrac{2\cdot5}{5}=2\)

Vậy: x=2

b) Ta có: \(\dfrac{3}{-8}=\dfrac{6}{-x}\)

\(\Leftrightarrow-x=\dfrac{6\cdot\left(-8\right)}{3}=-16\)

hay x=16

Vậy: x=16

đùa nhau à

?

1) 

g) \(24+5x\text{=}7^5:7^3\)

\(24+5x\text{=}7^{5-3}\)

\(24+5x\text{=}7^2\text{=}49\)

\(5x\text{=}49-24\text{=}25\)

\(x\text{=}5\)

h) \(x:2^2\text{=}2^3\)

\(x\text{=}2^3.2^2\)

\(x\text{=}2^5\text{=}32\)

2) 

a) \(2^{10}.8.2^3\text{=}2^{10}.2^3.2^3\text{=}2^{10+3+3}\text{=}2^{16}\)

\(b)3^5:27\text{=}3^5:3^3\text{=}3^{5-3}\text{=}3^2\)

\(c)5^2.125\text{=}5^2.5^3\text{=}5^{2+3}\text{=}5^5\)

\(d)6^6:36\text{=}6^6:6^2\text{=}6^{6-2}\text{=}6^4\)

1.

g) \(24+5x=7^5:7^3\left(=7^{5-3}\right)\) -> Trong ngoặc ko cần viết nha

\(24+5x=7^2=49\)

\(5x=49-24\)

\(5x=25\)

\(x=25:5\)

\(=>x=5\)

h) \(x:2^2=2^3\)

\(x=2^3.2^2\)

\(=>x=2^5\)

2.

a) \(2^{10}.8.2^3=2^{10}.\left(2^3\right)2^3=2^{10+3+3}=2^{16}\)

b) \(3^5:27=3^5:\left(3^3\right)=3^{5-3}=3^2\)

c) \(5^2.125=5^2.\left(5^3\right)=5^{2+3}=5^5\)

d) \(6^6:36=6^6:\left(6^2\right)=6^{6-2}=6^4\)

Công thức:

\(a^m.a^n=a^{m+n}\)

\(a^m:a^n=a^{m-n}\)

\(#Wendy.Dang\)

g) x - [ 42 + (-28)] = -8

\(\Rightarrow x-\left(42-28\right)=-8\)

\(\Rightarrow x-14=-8\)

\(\Rightarrow x=-8+14\)

\(\Rightarrow x=6\)

e) | x - 3| = |5| + | -7|

\(\Rightarrow\left|x-3\right|=5+7\)

\(\Rightarrow\left|x-3\right|=12\)

\(\Rightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}\)

nhiều quá :((

\(a,2\left(x-5\right)-3\left(x+7\right)=14\)

\(2x-10-3x-21=14\)

\(-x-31=14\)

\(-x=45\)

\(x=45\)

\(b,5\left(x-6\right)-2\left(x+3\right)=12\)

\(5x-30-2x-6=12\)

\(3x-36==12\)

\(3x=48\)

\(x=16\)

\(c,3\left(x-4\right)-\left(8-x\right)=12\)

\(3x-12-8+x=0\)

\(4x-20=0\)

\(4x=20\)

\(x=5\)

Cố nốt nha bn ! 

cảm ơn, bn nha:)))

mà hình như bạn TOP 3 trả lời câu hỏi pải ko nhỉ???