A=chia hết cho 2 ko chia hết cho 5

B=chia hết cho cả 2 và 5

C=chia hết cho 2 ko chia hết cho 5

Cậu ơi có phải đề bài là như thế này không?                           

 tìm các số nguyên để 8 x ( n+ 3 ) chia hết cho (2 x -1)

khó đọc quá , bn sửa lại nội dung co mik xem đc không :VV

xin loi vi may toi ko viet dau duoc

goi 3 so do la a,b,c Ta co 
4a=3b=2c =>a/(1/4)=b/(1/3)=c/(1'2) =(a+b+c)/(1/2+1/3+1/4)=162.5/(13/12)=150
Vay a= 150.(1/4)=37.5 

tick nha

37.5Nguyễn Tùng Anh

tick nhé

Ta có: 2x + 1 = 2017

=> 2x = 2017 - 1

=> 2x = 2016

=> x = 2016 : 2

=> x = 1008

Vậy x = 1008.

cam mon bn!

10,92*0,5*6,15*4*2

=5,46*6,15*4*2

=33,579*4*2

=134,316*2

=268,632

2*4,23*1,25:0,25*10

=8,46*1,25:0,25*10

=10,575:0,25*10

=42,3*10

=423

**** các bạn

268,632

423

tick nha

a)(11*9-100+1):(1*2*3*4*5*6*7*8*9*10)

=0:(1*2*3*4*5*6*7*8*9*10)

=0

a)(11*9-100+1):(1*2*3*4*5*6*7*8*9*10)
=0:(1*2*3*4*5*6*7*8*9*10)
=0

hacker 2k6

Ta có :

\(5^{2017}:\left(5^{2015}.16+5^{2015}.9\right)\)\(=5^{2017}:\left[5^{2015}\left(16+9\right)\right]\)

\(=5^{2017}:\left[5^{2015}.5^2\right]=1\)

2/ \(4.\left(2017-16x\right)=10^2-2^5\)

\(\Rightarrow4.2017-4.4^2x=100-25\)

\(\Rightarrow8068-4^3.x=75\)

\(\Rightarrow64x=8068-75\)

\(\Rightarrow64x=7993\)

\(\Rightarrow x=\frac{7993}{64}\)

\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+..+\frac{1}{x\left(x+2\right)}=\frac{20}{41}\)

\(\frac{1}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{x.\left(x+2\right)}\right)=\frac{20}{41}\)

\(\frac{1}{2}\left(\frac{3-1}{1.3}+\frac{5-3}{3.5}+\frac{7-5}{5.7}+...+\frac{\left(x+2\right)-x}{x\left(x+2\right)}\right)=\frac{20}{41}\)

\(\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+2}\right)=\frac{20}{41}\)

\(\frac{1}{2}\left(1-\frac{1}{x+2}\right)=\frac{20}{41}\)

\(1-\frac{1}{x+2}=\frac{20}{41}:\frac{1}{2}\)

\(1-\frac{1}{x+2}=\frac{40}{41}\)

\(\frac{1}{x+2}=1-\frac{40}{41}\)

\(\frac{1}{x+2}=\frac{1}{41}\)

\(x+2=41\)

\(x=41-2\)

\(x=39\)

Tìm x 

a) \(\frac{1}{1\times3}+\frac{1}{3\times5}+\frac{1}{5\times7}+...+\frac{1}{x\times\left(x+2\right)}=\frac{20}{41}\)

\(\Rightarrow\frac{1}{2}\times\left(\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+...+\frac{2}{x\times\left(x+1\right)}\right)=\frac{20}{41}\)

\(\Rightarrow\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+...+\frac{2}{x\times\left(x+2\right)}=\frac{20}{41}:\frac{1}{2}\)

\(\Rightarrow\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+...+\frac{2}{x\times\left(x+2\right)}=\frac{40}{41}\)

\(\Rightarrow1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{\left(x+2\right)}=\frac{40}{41}\)

\(\Rightarrow1-\frac{1}{x+2}=\frac{40}{41}\)

\(\Rightarrow\frac{1}{x+2}=1-\frac{40}{41}\)

\(\Rightarrow\frac{1}{x+2}=\frac{1}{41}\)

\(\Rightarrow x+2=41\)

\(\Rightarrow x=41-2\)

\(\Rightarrow x=39\)

Vậy x = 39