cứu cứu xong tui tăng sp cho
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Noise pollution is any loud sound that is either harmful or annoying to humans and animals. Generally, noise is produced by household appliances, big trucks, vehicles and motorbikes on the road, as well as planes and helicopters flying over cities, and loudspeakers. Noise pollution can cause stress, illnesses, hearing loss, sleep loss, and lost productivity. Its health effects include anxiety, stress, headaches, irritability, and nervousness. Therefore, noise-producing industries, airports, and bus terminals should be located far from living areas. Moreover, officials should check the misuse of loudspeakers, outdoor parties, discos, and public announcement systems. By doing so, we can reduce noise pollution and protect people’s health
Em tách nhỏ ra để hỏi, không đăng cả đề như thế này, em nhé!
Ta có \(\dfrac{a^3}{a^2+b^2}=a-\dfrac{ab^2}{a^2+b^2}\ge a-\dfrac{ab^2}{2ab}=a-\dfrac{b}{2}=\dfrac{2a-b}{2}\)(áp dụng cosi cho \(a^2+b^2\ge2ab\))
\(\dfrac{b^3}{b^2+1}=b-\dfrac{b}{b^2+1}\ge b-\dfrac{b}{2b}=b-\dfrac{1}{2}=\dfrac{2b-1}{2}\)(áp dụng cosi cho\(b^2+1\ge2b\))
\(\dfrac{1}{a^2+1}=1-\dfrac{a^2}{a^2+1}\ge1-\dfrac{a^2}{2a}=1-\dfrac{a}{2}=\dfrac{2-a}{2}\)( áp dụng cosi cho \(a^2+1\ge2a\))
Cộng vế theo vế
\(\dfrac{a^3}{a^2+b^2}+\dfrac{b^3}{b^2+1}+\dfrac{1}{a^2+1}\ge\dfrac{2a-b+2b-1+2-a}{2}\)\(\ge\dfrac{a+b+1}{2}\left(đpcm\right)\)
Dấu "=" xảy ra <=> a=b=1
Ta có:
\(36=2^2.3^2\)
\(54=2.3^3\)
\(ƯCLN\left(36;54\right)=2.3=6\)
\(BCNN\left(36;54\right)=2^2.3^3=4.27=108\)
10: \(\left(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\right)^2\)
\(=\left(\sqrt{3-\sqrt{5}}\right)^2+\left(\sqrt{3+\sqrt{5}}\right)^2+2\cdot\sqrt{\left(3-\sqrt{5}\right)\left(3+\sqrt{5}\right)}\)
\(=3-\sqrt{5}+3+\sqrt{5}+2\cdot\sqrt{9-5}\)
\(=6+2\cdot2=10\)
11: \(\left(\sqrt{\sqrt{7}+\sqrt{3}}+\sqrt{\sqrt{7}-\sqrt{3}}\right)^2\)
\(=\left(\sqrt{\sqrt{7}+\sqrt{3}}\right)^2+\left(\sqrt{\sqrt{7}-\sqrt{3}}\right)^2+2\cdot\sqrt{\left(\sqrt{7}+\sqrt{3}\right)\left(\sqrt{7}-\sqrt{3}\right)}\)
\(=\sqrt{7}+\sqrt{3}+\sqrt{7}-\sqrt{3}+2\cdot\sqrt{7-3}\)
\(=2\sqrt{7}+2\cdot2=2\sqrt{7}+4\)
12: \(\left(\sqrt{\sqrt{11}+\sqrt{7}}-\sqrt{\sqrt{11}-\sqrt{7}}\right)^2\)
\(=\left(\sqrt{\sqrt{11}+\sqrt{7}}\right)^2+\left(\sqrt{\sqrt{11}-\sqrt{7}}\right)^2-2\cdot\sqrt{\left(\sqrt{11}-\sqrt{7}\right)\left(\sqrt{11}+\sqrt{7}\right)}\)
\(=\sqrt{11}+\sqrt{7}+\sqrt{11}-\sqrt{7}-2\cdot\sqrt{11-7}\)
\(=2\sqrt{11}-4\)
13:
\(\sqrt{\sqrt{2}-1}\cdot\sqrt{2-\sqrt{3-\sqrt{2}}}\cdot\sqrt{2+\sqrt{3-\sqrt{2}}}\)
\(=\sqrt{\sqrt{2}-1}\cdot\sqrt{4-\left(3-\sqrt{2}\right)}\)
\(=\sqrt{\sqrt{2}-1}\cdot\sqrt{\sqrt{2}+1}\)
\(=\sqrt{2-1}=1\)
14:
\(\sqrt{4+\sqrt{8}}\cdot\sqrt{2+\sqrt{2+\sqrt{2}}}\cdot\sqrt{2-\sqrt{2+\sqrt{2}}}\)
\(=\sqrt{4+2\sqrt{2}}\cdot\sqrt{\left(2+\sqrt{2+\sqrt{2}}\right)\left(2-\sqrt{2+\sqrt{2}}\right)}\)
\(=\sqrt{4+2\sqrt{2}}\cdot\sqrt{4-2-\sqrt{2}}\)
\(=\sqrt{\left(4+2\sqrt{2}\right)\left(2-\sqrt{2}\right)}\)
\(=\sqrt{8-4\sqrt{2}+4\sqrt{2}-4}=\sqrt{4}=2\)
\(B=\dfrac{3}{1x2}+\dfrac{3}{2x3}+...+\dfrac{3}{50x51}\)
\(B=3x\left(\dfrac{1}{1x2}+\dfrac{1}{2x3}+...+\dfrac{1}{50x51}\right)\)
\(B=3x\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{50}-\dfrac{1}{51}\right)\)
\(B=3x\left(1-\dfrac{1}{51}\right)=3x\dfrac{50}{51}=\dfrac{150}{51}\)







làm được câu nào thì làm cho tui nhé thanks
Bài 1
a. 9/4
b.-1/5
Bài 2.
a.6
b. 22/15