1.

=3/5x(3/7+4/7)+2/5x(13/9-4/9)

=3/5x1+2/5x1

=3/5+2/5

=1

2.Xx(3/4+4/5)=7/10

Xx31/20=7/10

X         =7/10:31/20

X         =14/31

\(\frac{3}{5}\cdot\frac{3}{7}+\frac{3}{5}\cdot\frac{4}{7}+\frac{2}{5}\cdot\frac{13}{9}-\frac{2}{5}\cdot\frac{4}{9}\)

\(=\frac{3}{5}\cdot\left(\frac{3}{7}+\frac{4}{7}\right)+\frac{2}{5}\cdot\left(\frac{13}{9}-\frac{4}{9}\right)\)

\(=\frac{3}{5}\cdot1+\frac{2}{5}\cdot1\)\(=\frac{3}{5}+\frac{2}{5}=1\)

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\(\frac{3}{4}\cdot x+\frac{4}{5}\cdot x=\frac{7}{10}\)

\(\left(\frac{3}{4}+\frac{4}{5}\right)\cdot x=\frac{7}{10}\)

\(\frac{31}{20}\cdot x=\frac{7}{10}\)

\(x=\frac{7}{10}:\frac{31}{20}\)

\(x=\frac{14}{31}\)

(x+5)^3 = 64 = (-4)^3

x + 5 = -4

x = - 9         

2006 x [43 x 10 - 2 x 43 x 5] +100

=2006x0+100

=0+100

=100

64x4+18x4+9x8

=256+72+72

=400

44x5+18x10+20x5

=220+180+100

=500

3x4+4x6+9x2+18

=12+24+18+18

=72

2x5+5x7+9x3

=10+35+27

=72

15:5+27:5+8:5

=[15+27+8]:5

=10

99:5-26:5-14:5

=[99-26-14]:5

=11.8

Câu cuối sai đề nha mà nếu đề như vậy thì đó là toán lớp 6

Cảm ơn bạn I LOVE YOU rất nhiều mình đang vội ,cảm ơn bạn nhé!!!

\(x^{64}=x\)

\(\Rightarrow\hept{\begin{cases}x=0\\x=1\end{cases}}\)

vậy \(\hept{\begin{cases}x=0\\x=1\end{cases}}\)

\(\left(x-1\right)^4=9\left(x-1\right)^2\)

\(\left(x-1\right)^4-9\left(x-1\right)^2=0\)

\(\left(x-1\right)^2.\left[\left(x-1\right)^2-3^2\right]=0\)

\(\left(x-1\right)^2.\left(x-1-3\right)\left(x-1+3\right)=0\)

\(\left(x-1\right)^2.\left(x-4\right)\left(x-2\right)=0\)

\(\Rightarrow\left(x-1\right)^2=0\)hoặc \(\orbr{\begin{cases}x-4=0\\x-2=0\end{cases}}\)

\(\Rightarrow x-1=0\)hoặc \(\orbr{\begin{cases}x=4\\x=2\end{cases}}\)

vậy \(x=1\)hoặc \(\orbr{\begin{cases}x=4\\x=2\end{cases}}\)

x = -1;0;1.

x = 0 . 

Có chép nhầm đề ko

ko bạn ơi

(\(\dfrac{11}{12}\) + \(\dfrac{11}{12.23}\)  + \(\dfrac{11}{23.24}\) + ... + \(\dfrac{11}{89.100}\)) + \(x\) = \(\dfrac{5}{3}\)

Em xem lại nhé chứ \(\dfrac{11}{23.24}\) không hợp quy luật dãy số.

a) \(x=-\dfrac{3}{5}\times\dfrac{9}{7}=-\dfrac{27}{35}\)

b) \(x\left(0,4-\dfrac{1}{5}\right)=\dfrac{3}{4}\)

\(x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)

a, \(x=-3,5.\dfrac{9}{7}=-\dfrac{9}{2}\)

b, \(\dfrac{2}{5}x-\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)

x={-599}

Ta có ; 1 + (-3) + 5 + (-7) + ...... + x = -600

<=> -2 + -2 + ...... + -2 + x = -600

Mà trc x là thui nói lun x = 1199

1: 6(x-2)-y(2-x)=10

=>6(x-2)+y(x-2)=10

=>(x-2)(y+6)=10

=>(x-2;y+6)∈{(1;10);(10;1);(-1;-10);(-10;-1);(2;5);(5;2);(-2;-5);(-5;-2)}

=>(x;y)∈{(3;4);(12;-5);(1;-16);(-8;-7);(4;-1);(7;-4);(0;-11);(-3;-8)}

2: 3x-2xy+3y=6

=>x(3-2y)+3y-4,5=6-4,5

=>-x(2y-3)+1,5(2y-3)=1,5

=>(2y-3)(-x+1,5)=1,5

=>(2y-3)(-2x+3)=3

=>(2x-3)(2y-3)=-3

=>(2x-3;2y-3)∈{(1;-3);(-3;1);(-1;3);(3;-1)}

=>(x;y)∈{(2;0);(0;2);(1;3);(3;1)}

3: 6x-xy+2y=5

=>x(6-y)+2y-12=5-12=-7

=>-x(y-6)+2(y-6)=-7

=>(y-6)(-x+2)=-7

=>(x-2)(y-6)=7

=>(x-2;y-6)∈{(1;7);(7;1);(-1;-7);(-7;-1)}

=>(x;y)∈{(3;13);(9;7);(1;-1);(-5;5)}