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NM
30 tháng 8 2021

ta có : \(a=\frac{bc}{d}\)nên : \(a+d>b+c\Leftrightarrow\frac{bc}{d}+d>b+c\Leftrightarrow bc+d^2>bd+cd\)

\(\Leftrightarrow bc-bd-cd+d^2>0\Leftrightarrow\left(b-d\right)\left(c-d\right)>0\) điều này luôn đúng do b>c>d

Vậy ta có đpcm

31 tháng 8 2021

rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

15 tháng 8 2018

bạn ơi bạn làm dc chưa

a, \(a>b\) nên \(a-b>0\)

\(c>d\) nên \(c-d>0\)

Do đó : \(a-b+c-d>0\)

\(\Leftrightarrow a+c-\left(b+d\right)>0\)

\(\Leftrightarrow a+c>b+d\)

b, \(a>b>0\)nên \(\frac{a}{b}>1\)

\(c>d>0\)nên \(\frac{c}{d}>1\)

\(\Rightarrow\frac{a}{b}.\frac{c}{d}>1\)

\(\Leftrightarrow\frac{ac}{bd}>1\)

\(\Leftrightarrow ac>bd\)

31 tháng 5 2017

Hỏi gì mà khó dữ vậy!!!!!

31 tháng 5 2017

sory minh moi lop 5 thoi