\(\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+100\right)}{100.1+99.2+...+1.100}\)

\(\frac{1+1+2+1+2+3+...+1+2+...+100}{100.1+99.2+...+1.100}\)

\(=\frac{1.100+2.99+3.98+...+100.1}{100.1+99.2+...+1.100}\)

\(=1\)

dễ quớ đi!

Ai ngu mới hỏi câu dễ thế

\(\frac{1+\left[1+2\right]+\left[1+2+3\right]+...+\left[1+2+3+...+100\right]}{100.1+99.2+98.3+...+2.99+1.100}=\frac{1.2:2+2.3:2+3.4:2+...+100.101:2}{100.1+99.2+98.3+...+2.99+1.100}\)

\(=\frac{\frac{1}{2}\left[1.2+2.3+3.4+...+100.101\right]}{100.1+99.2+98.3+...+2.99+1.100}=\frac{\frac{1}{2}\cdot\frac{1}{3}\left[1.2.3-0.1.2+2.3.4-1.2.3+...+100.101.102-99.100.101\right]}{1.100+2.100-1.2+3.100-2.3+...+100.100-99.100}\)

\(=\frac{\frac{1}{6}\cdot100.101.102}{100\left[1+2+3+...+100\right]-\left[1.2+2.3+...+99.100\right]}=\frac{171700}{100\cdot\frac{100.101}{2}-\frac{99.100\cdot101}{3}}\)

\(=\frac{171700}{505000-333300}=\frac{171700}{171700}=1\)

AI THẤY ĐÚNG NHỚ ỦNG HỘ NHÉ

Tử số  \(=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}\)

\(=\left(1+\frac{1}{100}\right)+\left(\frac{1}{2}+\frac{1}{99}\right)+...+\left(\frac{1}{50}+\frac{1}{51}\right)\)

\(=\frac{101}{1.100}+\frac{101}{2.99}+...+\frac{101}{50.51}\)

\(=101.\left(\frac{1}{1.100}+\frac{1}{2.99}+...+\frac{1}{50.51}\right)\)

Mẫu số \(=\frac{1}{1.100}+\frac{1}{2.99}+...+\frac{1}{99.2}+\frac{1}{100.1}\)

\(=2.\left(\frac{1}{1.100}+\frac{1}{2.99}+...+\frac{1}{50.51}\right)\)

=> phân số đề bài cho \(=\frac{101}{2}\)

= 99 nha ban

3N = 1.2.3+2.3(4-1)+3.4.(5-2)+.+99.100.(101-98)

3N = 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+.+99.100.101-98.99.100

3N = 99.100.101

3N=33.100.101=333300

b)

tổng này có  99-10+1=90 (số hạng):

10,11 + 11,12 + 12,13 +............+ 98,99 + 99,100 =

10,100 + 11,11 + 12,12 + .......... + 98,98 + 99,99 =

(10,10 + 99,99) x 90 : 2 = 4954,05

c)

R=1.(2-1)+2.(3-1)+.....+100.(101-1)

=1.2-1.1+2.3-1.2+......+100.101-1.100

=(1.2+2.3+.....+99.100+100.101)-(1+2+3+...+100)

=[1.2.3+2.3.(4-1)+........100.101.(102-99)]:3+[(100+1).100:2]

(tổng trên chia cho 3 nên cuối cùng chia 3)

=(1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+.....100.101.102-99.100.101):3+5050

=(100.101.102) :3 +5050

=348450

d)=1.100+2.(100-1)+.....+100.(100-99)

=1.100+2.100-1.2+3.100-2.3+........+100.100-99.100

=100.(1+2+3+.......+100)-(1.2+2.3+3.4+....+99.100)

=100.\(\frac{101.100}{2}-\frac{99.100.101}{3}\) =505000-333300=171700

p/s mỏi tay, bấm mình nhé

=1.100 + 2.(100-1) + 3.(100 - 2 ) +..... + 99 .(100 - 98) + 100 .(100 - 99 )

=1.100 + 2. 100 - 1.2 + 3.100 - 3.2 +...+ 99 . 100 - 99 . 98 + 100 .100 - 100.99

= 100 (1 + 2 + 3 +... +100) - (1.2 +3 .2 +...+ 99.98 + 100.99 

=100.100.101 /2 - 99.100.101 / 3 

= 505000 - 333300= 171700 

                                                                Đ/S : 171700

A = 1.100 + 2.99 + 3.98 + 98.3 + 99.2 + 100.1

1.100 = 1.100 = 1.100

2.99 = 2.(100 - 1) = 2.100 - 1.2

3.98 = 3.(100 - 2) = 3.100 - 2.3

4.97 = 4.(100 - 3) = 4.100 = 3.4

...............................................................

100.1 = 100.(100 - 99) = 100.100 - 99.100

Cộng vế với vế ta có:

A = 1.100+2.100+...+99.100+100.100 - (1.2 +2.3+ 3.4+...+99.100)

Đặt B = 1.100 + 2.100+...+99.100 + 100.100

C = 1.2 + 2.3 + 3.4 +...+ 99.100

A = B - C

B = 1.100 + 2.100 + ...+ 99.100 + 100.100

B = 100.(1+ 2+ ... + 99+ 100)

B = 100.(100 + 1) x 100 : 2

B = 505000

C = 1.2 + 2.3 + 3.4 +...+ 99.100

3C = 1.2.3 + 2.3.3 +..+99.100.3

1.2.3 = 1.2.3

2.3.3 = 2.3.(4 - 1) = 2.3.4 - 1.2.3

99.100.3 = 99.100.(101 - 98)=99.100.101-98.99.100

Cộng vế với vế ta có:

3C = 99.100.101

C = 99.100.101 : 3

C = 333300

A = B - C

A = 505000 - 333300

A = 171700

Câu b:

A = 9+99+ 999+...+9999...99(1000 chữ số 9)

9 = - 1 + 10

99 = - 1 + 100

999 = - 1 + 1000

...............................

999...999 = -1 + 1000...00(1000 chữ số 0)

Cộng vế với vế ta có:

B = - 1 x 1000 + 11111...10(1000 chữ số 1)

B = 111....110110 (999 chữ số 1)