Mn giúp mình với, mình cần trước 10h sáng mai ạ. Mình cảm ơn trước ạ.
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1 Yesterday was cooler than today
2 Salim is the most beautiful in her team
3 His house is the highest in my city
4 No one in her class is as intelligent as Lan
5 BJ is one of the greatest tennis players in the world
1. Yesterday was colder than today.
2. Salim is the most beautiful in her team.
3. His house is the highest house in my city.
4.No one in her class is more intelligent than Lan
8. BJ isthe greatest tennis player in the world.
Câu 14:
a: Thay x=36 vào B, ta được:
\(B=\frac{6-3}{6+1}=\frac37\)
b: \(A=\frac{2\sqrt{x}}{\sqrt{x}+3}+\frac{\sqrt{x}+1}{\sqrt{x}-3}+\frac{3-11\sqrt{x}}{9-x}\)
\(=\frac{2\sqrt{x}\cdot\left(\sqrt{x}-3\right)+\left(\sqrt{x}+1\right)\left(\sqrt{x}+3\right)+11\sqrt{x}-3}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\)
\(=\frac{2x-6\sqrt{x}+x+4\sqrt{x}+3+11\sqrt{x}-3}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=\frac{3x+9\sqrt{x}}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\)
\(=\frac{3\sqrt{x}\left(\sqrt{x}+3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=\frac{3\sqrt{x}}{\sqrt{x}-3}\)
Câu 12:
a: Thay x=49 vào A, ta được:
\(A=\frac{49-4}{\sqrt{49}-2}=\frac{45}{7-2}=\frac{45}{5}=9\)
b: \(B=\frac{2}{\sqrt{x}-2}+\frac{3}{\sqrt{x}+2}-\frac{x-5\sqrt{x}+2}{4-x}\)
\(=\frac{2\left(\sqrt{x}+2\right)+3\left(\sqrt{x}-2\right)+x-5\sqrt{x}+2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\)
\(=\frac{2\sqrt{x}+4+3\sqrt{x}-6+x-5\sqrt{x}+2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\frac{x}{x-4}\)







