a: \(\frac{47}{15}>\frac{15}{15}=1;1=\frac{35}{35}>\frac{29}{35}\)

Do đó: \(\frac{47}{15}>\frac{29}{35}\)

b: \(\frac{1999}{2001}<\frac{2001}{2001}=1;1=\frac{11}{11}<\frac{12}{11}\)

Do đó: \(\frac{1999}{2001}<\frac{12}{11}\)

c: \(\frac{2021}{2020}>\frac{2020}{2020}=1;1=\frac{2022}{2022}>\frac{2019}{2022}\)

Do đó: \(\frac{2021}{2020}>\frac{2019}{2022}\)

bạn quy đồng hai phân số lên rồi so sánh 

bài dài mình ngại giải

what the not

a)26,72+13/100 +21/40 = 5344/200+26/200+105/200=(5344+26+105)/200=219/8=27,375
c)3/4+15/40+69/300=150/200+75/200+46/200=(150+75+46)/200=271/200=1,355

ta có:19/20<20/20 và 20/20<21/20 nên 19/20<20/21

phần còn lại cậu tự giải nốt đi mình chịu 

nhớ k mình nha

\(\frac{17}{15}=\frac{493}{435};\frac{31}{29}=\frac{465}{435};493>465=>\frac{17}{15}>\frac{31}{29}\)

\(\frac{17}{15}\)>\(\frac{31}{29}\)

a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)

Đến đây tự tính nha !

b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)

1. 27/5 x 91/12 x 125/9 x 96/13

2. 2539/35 x 7/90 + 561/35 x 7/90

3. 31/7 : (2/5 x 31/7)

4. (29 x 15/23 x 36/29) : 5/23

\(\frac{7}{13}=1-\frac{5}{13}< 1-\frac{5}{8}=\frac{3}{8}\)

7/3 > 3/8

15/32 < 17/29

học tốt

a) \(\dfrac{25}{37}\times\dfrac{18}{29}+\dfrac{18}{29}\times\dfrac{12}{37}\)

\(=\dfrac{18}{29}\times\left(\dfrac{25}{37}+\dfrac{12}{37}\right)\)

\(=\dfrac{18}{29}\times\dfrac{37}{37}\)

\(=\dfrac{18}{29}\times1\)

\(=\dfrac{18}{29}\)

b) \(\dfrac{31}{85}\times\dfrac{11}{19}+\dfrac{31}{85}\times\dfrac{12}{19}-\dfrac{42}{19}\times\dfrac{31}{85}\)

\(=\dfrac{31}{85}\times\left(\dfrac{11}{19}+\dfrac{12}{19}-\dfrac{42}{19}\right)\)

\(=\dfrac{31}{85}\times\dfrac{-19}{19}\)

\(=\dfrac{31}{85}\times-1\)

\(=-\dfrac{31}{85}\)

c) \(\dfrac{16}{53}:\dfrac{17}{9}-\dfrac{16}{53}:\dfrac{17}{8}\)

\(=\dfrac{16}{53}:\left(\dfrac{9}{17}-\dfrac{8}{17}\right)\)

\(=\dfrac{16}{53}:\dfrac{1}{17}\)

\(=\dfrac{16}{901}\)

c) \(\dfrac{1}{5}\times\dfrac{12}{31}\times\dfrac{4}{3}+\dfrac{19}{31}\times\dfrac{4}{15}\)

\(=\dfrac{4}{15}\times\dfrac{12}{31}+\dfrac{19}{31}\times\dfrac{4}{15}\)

\(=\dfrac{4}{15}\times\left(\dfrac{12}{31}+\dfrac{19}{31}\right)\)

\(=\dfrac{4}{15}\times\dfrac{31}{31}\)

\(=\dfrac{4}{15}\times1\)

\(=\dfrac{4}{15}\)

a: =18/29*(25/37+12/37)

=18/29

b: =31/85(11/19+12/19-42/19)

=-31/85

c; =16/53(9/17+8/17)=16/53

d: =4/15(12/31+19/31)=4/15