a) 12 x 18 + 14 x 3 - 255 : 17

= 216 + 42 - 15

= 243

b) 68 + 42 x 5 - (198 : 11 - 8)

= 68 + 210 - (18 - 8)

= 68 + 210 - 10

= 268

\(D=12\cdot\left(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{22}+...+\frac{1}{97}-\frac{1}{202}\right)\)

\(D=12\cdot\left(\frac{1}{6}-\frac{1}{202}\right)\)

\(D=12\cdot\frac{49}{303}\)

\(D=\frac{588}{303}\)

Cau 1)

21+(x+23)=50

X+23=50-21

X=29-23

X=6

Cau 2)

125+(x-100)=150

X-100=150-125

X=25+100

X=125

e cảm ơn chị ạ!

You chép mạng à?

a: \(3636:\left(12\cdot x-91\right)=36\)

=>\(12x-91=\frac{3636}{36}=101\)

=>12x=91+101=192

=>\(x=\frac{192}{12}=16\)

b: \(446+2\cdot\left(125-x\right)=546\)

=>\(2\left(125-x\right)=546-446=100\)

=>125-x=50

=>x=125-50=75

c: \(\left(x-36\right):18=10+2\)

=>\(\left(x-36\right):18=12\)

=>\(x-36=18\cdot12=216\)

=>x=216+36=252

\(a,36.19+36.81\)

\(=36.\left(19+81\right)\)

\(=36.100\)

\(=3600\)

\(b,8.12.125.5\)

\(=\left(125.8\right)\left(12.5\right)\)

\(=1000.60\)

\(=60000\)

\(c,\)chịu 

c,7 x 9 + 14 x 27 + 21 x 36 / 21 x 27 + 42 x 81 + 63 x 108

7 x 9 + 14 x 27 + 21 x 36 / 7 x 3 x 9 x 3 + 14 x 3 x 27 x 3 + 21 x 3 x 36 x 3

1 / 3 x 3 + 3 x 3 + 3 x 3

1 / 9 + 9 + 9

1 / 27

Ta có: 3636:(12x−91)=36

12x–91=3636:36

12x–91=101

12x=101+91

12x=192

x=192:12

x=16

Vậy x=16

440 + 2. (125 – x) = 546

2. (125 - x)=546 - 440

2. (125 - x)=106

125 - x=106 : 2

125 - x=53

x=125-53

x=72

9

7<9<18

\(18⋮x\)và \(7\le x< 18\)

Vì \(18⋮x\)

\(\Rightarrow\)\(x\inƯ\left(18\right)=\left\{1;2;3;6;9;18\right\}\)

Mà \(7\le x< 18\)

\(\Rightarrow\)\(x\in\left\{9\right\}\)

Vậy chọn đáp án \(D.9\)

cái này bạn phải xét âm dương nha :

mik lm ví dụ hoy :

\(\left|x+7\right|+2x=14\)

Th1 : \(x-7\ge0\Rightarrow x\ge7\)PT trở thành :

\(x-7+2x=14\)

\(\Rightarrow3x=21\Rightarrow x=4\)( tm đk )

Th2 : \(\left|x-7\right|< 0\Rightarrow x< 7\)PT trở thành :

\(7-x+2x=14\)

\(\Rightarrow x=7\)( ko tm đk )

Vậy x = 4

a)

b) \(\hept{\begin{cases}x-5=9\\x-1=9\end{cases}}\Rightarrow\hept{\begin{cases}x=9+5=14\\x=9+1=10\end{cases}}\)

c)\(\hept{\begin{cases}x-6=8\\x+2=8\end{cases}}\Rightarrow\hept{\begin{cases}x=8+6=14\\x=8-2=6\end{cases}}\)

a) \(6-2\left(x+4\right)=-4\)

\(\Leftrightarrow6-2x-8=-4\)

\(\Leftrightarrow-2-2x=-4\)

\(\Leftrightarrow-2x=-4+2\)

\(\Leftrightarrow-2x=-2\)

\(\Leftrightarrow x=1\)

Vậy \(x=1\)

b) tự làm.

c) \(2x-15:5=-7\)

\(\Leftrightarrow2x-7,5=-7\)

\(\Leftrightarrow2x=-7+7,5\)

\(\Leftrightarrow2x=0,5\)

\(\Leftrightarrow x=0,25\)

\(\Leftrightarrow x=\dfrac{1}{4}\)

Vậy \(x=\dfrac{1}{4}\)

d) \(231-\left(x-6\right)=1339:13\)

\(\Leftrightarrow231-x+6=103\)

\(\Leftrightarrow237-x=103\)

\(\Leftrightarrow237-x+6=103\)

\(\Leftrightarrow-x=103-237\)

\(\Leftrightarrow-x=-134\)

\(\Leftrightarrow x=134\)

e) đề j mà có 2 dấu bằng >> sai :v

f) \(28-x^3=1\)

\(\Leftrightarrow-x^3=1-28\)

\(\Leftrightarrow-x^3=-27\)

\(\Leftrightarrow x^3=27\)

\(\Leftrightarrow x^3=3^3\)

\(\Leftrightarrow x=3\)

Vậy \(x=3\)

g) \(\left(x+2\right)^3=27\)

\(\Leftrightarrow\left(x+2\right)^3=3^3\)

\(\Leftrightarrow x+2=3\)

\(\Leftrightarrow x=3-2\)

\(\Leftrightarrow x=1\)

Vậy \(x=1\)

h) \(81-\left(x-5\right)^2=56\)

\(\Leftrightarrow-\left(x-5\right)^2=56-81\)

\(\Leftrightarrow-\left(x-5\right)^2=-25\)

\(\Leftrightarrow\left(x-5\right)^2=25\)

\(\Leftrightarrow x-5=\pm5\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=5\\x-5=-5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=5+5\\x=-5+5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=0\end{matrix}\right.\)

Vậy \(x_1=0;x_2=10\)

j) \(x^2=9\)

\(\Leftrightarrow x=\pm3\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

Vậy \(x_1=-3;x_2=3\)

l) tự làm.

(x-12):6=3
x^2-1=3
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