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\(S1=2+4+6+...+150=\frac{2+150}{2}\cdot\left(\frac{150-2}{2}+1\right)\)
\(S1=\frac{152}{2}\cdot\left(\frac{148}{2}+1\right)=76\cdot\frac{150}{2}=76\cdot75=5700\)
- S3 và S5 tương tự nha bạn :vv
\(S2=5^2+5^3+5^4+...+5^{100}\)
\(\Rightarrow5S2=5^3+5^4+5^5+...+5^{100}+5^{101}\)
\(S2=5^2+5^3+5^4+5^5+...+5^{100}\)
\(\Rightarrow5S2-S2=4S2=5^{101}-5^2\Rightarrow S2=\frac{5^{101}-5^2}{4}\)
\(S4=\frac{5}{11\cdot16}+\frac{5}{16\cdot21}+...+\frac{5}{61\cdot66}\)
\(\Rightarrow S4=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\)
\(\Rightarrow S4=\frac{1}{11}-\frac{1}{16}=\frac{16}{176}-\frac{11}{176}=\frac{5}{176}\)
a/ \(A=\frac{1}{6}+\frac{1}{12}+.........+\frac{1}{56}\)
\(=\frac{1}{2.3}+\frac{1}{3.4}+..........+\frac{1}{7.8}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.........+\frac{1}{7}-\frac{1}{8}\)
\(=\frac{1}{2}-\frac{1}{8}=\frac{3}{4}\)
b/ \(B=\frac{5}{11.16}+\frac{5}{16.21}+........+\frac{5}{61.66}\)
\(=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+........+\frac{1}{61}-\frac{1}{66}\)
\(=\frac{1}{11}-\frac{1}{66}\)
\(=\frac{5}{66}\)
a) \(A=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\)
\(A=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\)
\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(A=\frac{1}{2}-\frac{1}{8}=\frac{3}{8}\)
b) \(B=\frac{5}{11.16}+\frac{5}{16.21}+...+\frac{5}{61.66}\)
\(B=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\)
\(B=\frac{1}{11}-\frac{1}{66}=\frac{5}{66}\)
\(=5.\left(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{26.31}\right)\)
\(=5.\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{26}-\frac{1}{31}\right)\)
\(=5.\left(1-\frac{1}{31}\right)\)
\(=5.\frac{30}{31}\)
\(=\frac{6}{31}\)
\(=5.\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.26}+\frac{5}{26.31}\right)\)
\(=5.\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+\frac{1}{21}-\frac{1}{26}+\frac{1}{26}-\frac{1}{31}\right)\)
\(=5.\left(1-\frac{1}{31}\right)=\frac{150}{31}\)
1) \(\frac{3^{2014}.8^{19}}{6^{60}.3^{1955}}=\frac{3^{2014}.\left(2^3\right)^{19}}{\left(2.3\right)^{60}.3^{1955}}=\frac{3^{2014}.2^{57}}{2^{60}.3^{2015}}=\frac{1}{2^3.3}=\frac{1}{24}\)
2) \(5^x+5^{x+1}=150\)
=> 5x(1 + 5) = 150
=> 5x.6 = 150
=> 5x = 25
=> \(x=\pm2\)
3) \(\frac{3}{11.16}+\frac{3}{16.21}+...+\frac{3}{61.66}=\frac{3}{5}\left(\frac{5}{11.16}+\frac{5}{16.21}+...+\frac{5}{61.66}\right)\)
\(=\frac{3}{5}\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\right)=\frac{3}{5}.\left(\frac{1}{11}-\frac{1}{66}\right)=\frac{3}{5}.\frac{5}{66}=\frac{1}{22}\)
Ta có: B = \(\frac{6}{15}+\frac{6}{35}+\frac{6}{63}+\frac{6}{99}\)
=> B = \(\frac{6}{3.5}\)+ \(\frac{6}{5.7}\)+ \(\frac{6}{7.9}\)+ \(\frac{6}{9.11}\)
=>B =\(3.\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)
=> B = \(3.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
=> B = \(3.\left(\frac{1}{3}-\frac{1}{11}\right)\)
=> B = \(3.\frac{8}{33}\)
=> B = \(\frac{8}{11}\)
Vậy: B = \(\frac{8}{11}\)
Bài 1 mik học xong quên hết òi (mấy bài kia là hok biết luôn :V)
\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{99\cdot100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}\)
\(=\frac{99}{100}\)
\(1)\) \(\frac{\frac{3}{41}-\frac{12}{47}+\frac{27}{53}}{\frac{4}{41}-\frac{16}{47}+\frac{36}{53}}=\frac{3\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}{4\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}=\frac{3}{4}\)
\(2)\) Đặt \(A=4+2^2+2^4+...+2^{20}\)
\(4A=2^4+2^4+2^6+...+2^{22}\)
\(4A-A=\left(2^4+2^4+2^6+...+2^{22}\right)+\left(2^2+2^2+2^4+...+2^{20}\right)\)
\(3A=2^4+2^{22}-2^2-2^2\)
\(3A=2^{22}+2^4-2^3\)
\(A=\frac{2^{22}+2^4-2^3}{3}\)
\(3)\) \(\frac{5^2}{1.6}+\frac{5^2}{6.11}+\frac{5^2}{11.16}+...+\frac{5^2}{26.31}\) ( bạn ghi đầy đủ ra nhé ở đây mk viết "..." cho nhanh )
\(=\)\(5\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+...+\frac{5}{26.31}\right)\)
\(=\)\(5\left(\frac{1}{1}-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+...+\frac{1}{26}-\frac{1}{31}\right)\)
\(=\)\(5\left(1-\frac{1}{31}\right)\)
\(=\)\(5.\frac{30}{31}\)
\(=\)\(\frac{150}{31}\)
Chúc bạn học tốt ~
Ta có:
\(\frac{3\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}{4\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}=\frac{3}{4}\)
dễ mà:
Đặt \(A=\frac{4}{11\cdot16}+\frac{4}{16\cdot21}+\cdots+\frac{4}{61\cdot66}\)
\(A=\frac45\cdot\left(\frac{5}{11\cdot16}+\frac{5}{16\cdot21}+\cdots+\frac{5}{61\cdot66}\right)\)
\(A=\frac45\cdot\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+\cdots+\frac{1}{61}-\frac{1}{66}\right)\)
\(A=\frac45\cdot\left(\frac{1}{11}-\frac{1}{66}\right)\)
\(A=\frac45\cdot\frac{5}{66}\)
\(A=\frac{2}{33}\)
Vậy \(A=\frac{2}{33}\)
easy mà
bài này là toán nâng cao lớp 5 mà?
đặt 4/5 ra ngoài ngoặc cò trong ngoặc là dãy cơ bản
Ta có : \(\frac{4}{11.16}+\frac{4}{16.21}+\cdots+\frac{4}{61.66}\)
Nhận thấy : \(\frac{4}{11.16}=\frac45.\left(\frac{4}{11}-\frac{4}{16}\right)\)
Nên :
\(\frac{4}{11.16}=\frac45.\left(\frac{4}{11}-\frac{4}{16}\right)\)
\(\frac{4}{16.21}=\frac45.\left(\frac{4}{16}-\frac{4}{21}\right)\)
...
\(\frac{4}{61.66}=\frac45.\left(\frac{4}{61}-\frac{4}{66}\right)\)
Cộng lại :
\(S = \frac{4}{5} \left(\right. \frac{1}{11} - \frac{1}{16} + \frac{1}{16} - \frac{1}{21} + . . . + \frac{1}{61} - \frac{1}{66} \left.\right)\)
Các số triệt tiêu nhau:
\(S = \frac{4}{5} \left(\right. \frac{1}{11} - \frac{1}{66} \left.\right)\)
\(\frac{1}{11} - \frac{1}{66} = \frac{6}{66} - \frac{1}{66} = \frac{5}{66}\)
Vậy:
\(S = \frac{4}{5} \times \frac{5}{66} = \frac{4}{66} = \frac{2}{33}\)
Kết quả :
\(\frac{2}{33}\)
Uy tín không viết AI.
=4/5(5/11x16+5/16x21+...+5/61x66)
=4/5(1/11-1/16+1/16-1/21+...+1/61-1/66)
=4/5(1/11-1/66)
=4/5x5/66
=2/33
thế nâng cao lớp 5 học a/b.(b+a)=1/b-1/b+a chưa
giống lớp 6 năm trước
ủa sao giải kì v
Dễ