Kq:196/3

`(2x-123)xx3=23`

`=> 2x-123=23:3`

`=> 2x-123=23/3`

`=> 2x=23/3+123`

`=> 2x=23/3+369/3`

`=> 2x=392/3`

`=> x=392/3:2`

`=> x=196/3`

Vậy`x=196/3`

\(C = 49\dfrac{8}{23} - (5\dfrac{7}{32} + 14\dfrac{8}{23} )\)

\(C = 49\dfrac{8}{23} - 5\dfrac{7}{32} - 14\dfrac{8}{23}\)

\(C =( 49\dfrac{8}{23} - 4\dfrac{8}{23}) - 5\dfrac{7}{32}\)

\(C = 45 - 5\dfrac{7}{32}\)

\(C = \dfrac{1273}{32}\)

Câu a:

A = (1\(\frac16\) x \(\frac67\) x 6 : \(\frac35\)) : (4\(\frac15\) x \(\frac{10}{11}\) + 5\(\frac{2}{10}\))

A = (7/6 x 6/7 x 6 x 5/3) :(21/5 x 10/11 + 52/10)

A = (1 x 6 x 5/3) : (210/55 + 26/5)

A = 10 : (210/55 + 286/55)

A = 10 : (496/55)

A = 10 x 55/496

A = 275/248

Câu b:

B = \(1\)\(\frac{13}{15}\) x 25% x 3 + (8/15 - 79/60) : 1\(\frac{23}{4}\)

B = 28/15 x 1/4 x 3 + (32/60 - 79/60) : 27/4

B = 7/15 x 3 - 47/60 x 4/27

B = 7/5 - 47/405

B = 104/81

a)\(-7-25+27+5=\left(27-7\right)+\left(5-25\right)\)

\(=20-20=0\)

b)\(-8+16-\left(-8\right)=-8+16+8=\left(8-8\right)+16=16\)

c)\(1+1-\left(-8\right)=1+1+8=10\)(Vì số nào mũ 0 cũng bằng 1(ngoại trừ số 0))

d)\(65.23+65.35-35.65+35.23\)

\(=\left(65.35-65.35\right)+23.\left(65+35\right)\)

\(=0+23.100=2300\)

f) \(8+\left[1800-\left(64-54\right)^3\right].8-5\)

\(=8+\left(1800-10^3\right).8-5\)

\(=8+800.8-5=6403\)

h)\(-123-46+46+123=\left(123-123\right)+\left(46-46\right)\)

\(=0+0=0\) (phá ngoặc ra thôi nhé)

Thank

Bài làm :

\(a,35.34+35.38+65.75+65.45\)

\(=35.\left(34+38\right)+65.\left(74+45\right)\)

\(=35.72+65.120\)

\(=2520+780\)

\(=10320\)

\(b,39.8+60.2+21.8\)

\(=\left(39+21\right).8+60.2\)

\(=60.8+60.2\)

\(=60.\left(8+2\right)\)

\(=60.10=600\)

\(c,36.28+36.82+64.69+64.4\)

\(=36.\left(28+82\right)+64.\left(69+4\right)\)

\(=36.110+64.73\)

\(=3960+4672\)

\(=8632\)

\(d,123.1001\)

\(=123123\)

Học tốt

1)

\(2.\frac{3}{7}+\left(\frac{2}{9}-1\frac{3}{7}\right)-\frac{5}{3}:\frac{1}{9}\)

\(=\frac{6}{7}+\frac{2}{9}-\frac{10}{7}-\frac{5}{3}.9\)

\(=\left(\frac{6}{7}-\frac{10}{7}\right)+\frac{2}{9}-15\)

\(=\frac{-4}{7}+\frac{2}{9}-\frac{15}{1}\)

\(=\frac{-36}{63}+\frac{14}{63}-\frac{945}{63}\)

\(=\frac{-967}{63}\)

2)

\(-\frac{11}{23}.\frac{6}{7}+\frac{8}{7}.\frac{-11}{23}-\frac{1}{23}\)

\(=\frac{-11}{23}\left(\frac{6}{7}+\frac{8}{7}\right)-\frac{1}{23}\)

\(=\frac{-11}{23}.2-\frac{1}{23}\)

\(=\frac{-22}{23}-\frac{1}{23}\)

\(=\frac{-23}{23}\)

\(=-1\)

3)

\(\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).\left(\frac{1}{6}-\frac{1}{8}-\frac{1}{24}\right)\)

\(=\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).\left(\frac{4}{24}-\frac{3}{24}-\frac{1}{24}\right)\)

\(=\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).\frac{0}{24}\)

\(=\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).0\)

\(=0\)

a) \(\frac{-3}{7}+\frac{15}{26}-\left(\frac{2}{13}-\frac{3}{7}\right)=\frac{-3}{7}+\frac{15}{26}-\frac{2}{13}+\frac{3}{7}=\left(\frac{-3}{7}+\frac{3}{7}\right)+\left(\frac{15}{26}-\frac{2}{13}\right)\)

\(=\frac{15-4}{26}=\frac{11}{26}\)

c) \(\frac{-11}{23}.\frac{6}{7}+\frac{8}{7}.\frac{-11}{23}-\frac{1}{23}=\frac{-11}{23}.\left(\frac{6}{7}+\frac{8}{7}\right)-\frac{1}{23}\)

\(=\frac{-11}{23}.2-\frac{1}{23}=\frac{-22-1}{23}=\frac{-23}{23}=-1\)

câu nầy hơn khó nên mình ko giải đc bạn đợ mình giải đã

1) 2763 + 152 = 2951

2)(-7) + (-14) = -21

1) 2763 +152 =2915

2) (-7) +(-14) = -21

3) (-35) + (-9) = -44

4) (-5) + (-248) = -253

5) (-23) + 105 = 82

6) 78 + (-123) = -45

7) 23 +(-13) = 10

8) (-23) +13 = -10

9) 26 + (-6) = 20

10) (-75) +50 = -25

11) 80 + (-220) = -140

12) (-23) + (-13) = -36

13) (-26) + (-6) = -32

14) (-75) + (-50) = -125

15) ❏-18❏ + (-12) = -17❏ -12

16)17 + ❏ - 33❏ = 17 -32❏

17) (-20) +❏ - 88❏ = -20 -87❏

18) ❏- 3❏+ ❏5❏ = ❏5❏ -2❏

19)❏-37❏+❏15❏ = ❏15❏ -36❏

20) ❏-37❏+(-❏15❏) = -❏15❏ - 36❏

21) (-❏-32❏) +❏5❏ = ❏5❏ -33❏

22) (-❏-22❏) + (-❏16❏) = -❏16❏ -23❏

23) (-23) +13 +(-17) +57 = 30

24) 14 +6 + (-9) + (-14) = -3

25) (-123 ) +❏-13❏+(-7) = -130-12❏

26) ❏0❏ + ❏45❏ +(-❏-455)❏+❏-796❏ = ❏45❏-❏\(^2\) -1250❏