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(1/3 + 12/67 + 13/41) - (79/67 - 28/41)
= 1/3 + 12/67 + 13/41 - 79/67 + 28/41
= 1/3 + (12/67 - 79/67) + (13/41 + 28/41)
= 1/3 + (-1) + 1
= 1/3
(1/3 + 12/67 + 13/41) - (79/67 - 28/41)
= 1/3 + 12/67 + 13/41 - 79/67 + 28/41
= 1/3 + (12/67 - 79/67) + (13/41 + 28/41)
= 1/3 + (-1) + 1
= 1/3.
CHÚC BẠN HỌC TỐT!!! ^^
Đặt \(A=6^3+6^5+6^7+...+6^{99}\)
Ta có: \(A=6^3+6^5+6^7+...+6^{99}\)
\(\Leftrightarrow36\cdot A=6^5+6^7+6^9+...+6^{101}\)
\(\Leftrightarrow A-36A=6^3+6^5+6^7+...+6^{99}-6^5-6^7-6^9-...-6^{101}\)
\(\Leftrightarrow-35\cdot A=6^3-6^{101}\)
\(\Leftrightarrow A=\dfrac{6^{101}-6^3}{35}\)
\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
=\(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)
\(=\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)
\(=\frac{1}{3}-1+1\)
\(=\frac{1}{3}\)
(1/3+12/67+13/41)-(79/67-28/41). =1/3+12/613/41-79/67+28/41. =1/3+(12/67-79/67)+(13/41+28/41) =1/3+(-1)+1=1/3+0. =1/3
dễ đáp án là
22x66+22781139the fraction with numerator 22 x raised to the exponent 66 end-exponent plus 2278 and denominator 1139 end-fraction22𝑥66+22781139
\(=\left(25+\dfrac{12}{67}+9+\dfrac{13}{41}-8-\dfrac{12}{67}+3+\dfrac{28}{41}\right)\cdot\dfrac{-21}{13}\)
\(=\left(25+9-8+3+1\right)\cdot\dfrac{-21}{13}=\dfrac{-630}{13}\)
\(\dfrac{2}{67}-\left(\dfrac{3}{7}+\dfrac{2}{67}\right)\\ =\dfrac{2}{67}-\dfrac{215}{469}\\ =\dfrac{-3}{7}\)
\(\frac{3}{67}+\frac{5}{2}-1\frac{1}{4}\)
\(=\frac{341}{134}-1\frac{1}{4}\)
\(=\frac{341}{134}-\frac{5}{4}\)
\(=\frac{347}{268}\)
chuc bn hoc gioi!
\(\frac{3}{67}+\frac{5}{2}-1\frac{1}{4}\)
\(=\frac{3}{67}+\frac{5}{2}-\frac{5}{4}\)
\(=\frac{12}{268}+\frac{670}{268}-\frac{335}{268}\)
\(=\frac{347}{268}\)
(x-99) (1/30 + 1/32 + 1/34 - 1/36 - 1/38) = 0
SUy ra x - 99 = 0
VẬy x =99
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bớt hỏi xà lơ đc ko:/