So sánh :

a)\(\frac{2017}{2018}và\frac{2018}{2019}\)                                                 b)\(\frac{201,6}{2017}và\frac{201,7}{2018}\)

c)\(\frac{2015}{2019}và\frac{504}{505}\)                                                     d)\(\frac{2x2018+1}{2x2019+1}và\frac{2x2017+1}{2x2018+1}\)

e)\(\frac{2x2018+1}{2x2019+1}và\frac{3x2018+1}{3x2019+1}\)                            f)\(\frac{223}{334}và\frac{2223}{3334}\)

Tinh dien tich hinh vuong ABCD biet tong chu vi cua 2 hinh chu nhat ABEH va HECD bang 25.2 cm

Điền số đo thích hợp vào chỗ chấm :

6km\(^2\)23456m\(^{^2}\)=.....km\(^2\).....hm\(^2\).....dam\(^2\).....m\(^2\)=.....km\(^2\)

5km\(^2\)246dam\(^2\)=.....km\(^2\).....hm\(^2\).....dam\(^2\)=.....km\(^2\)

57932cm\(^2\)=.....m\(^2\).....dm\(^2\).....cm\(^2\)=.....m\(^2\)

5,405m\(^2\)=.....m\(^2\).....dm\(^2\).....cm\(^2\)=.....cm\(^2\)=.....dm\(^2\)

37805cm\(^2\)=.....m\(^2\).....dm\(^2\).....cm\(^2\)=.....m\(^2\)

57950cm\(^2\)=.....m\(^2\).....dm\(^2\).....cm\(^2\)=.....dm\(^2\)

\(8,96\)\(:\)\(x\)\(-\)\(0,5\)\(=\)\(2,03\)

\(0,54\)\(-\)\(1,2\)\(\cdot\)\(x\)\(=\)\(0,06\)

Chuyển các phân số sau thành hỗn số

\(\frac{17}{5}\)\(;\)\(\frac{139}{12}\)\(;\)\(\frac{150}{13}\)

\(55+88-77+6666-4444=?\)\(?\)

\(Trả\)\(lời\)\(nhanh\)\(mk\)\(tk\)\(cho\)\(nha\)

\(~\)\(Kim\)\(Sở\)\(Sở\)\(~\)

1.

\(\frac{1}{2}\)+\(\frac{2}{3}\)+\(\frac{3}{4}\)

\(\frac{4}{5}\)+\(\frac{4}{3}\)+\(\frac{6}{7}\)

\(\frac{1}{4}\)+\(\frac{2}{5}\)+\(\frac{1}{3}\)

\(\frac{3}{5}\)+\(\frac{5}{6}\)+\(\frac{7}{9}\)

\(\frac{8}{9}\)-\(\frac{5}{6}\)

\(\frac{99}{108}\)-\(\frac{40}{72}\)

\(\frac{16}{17}\)-\(\frac{12}{13}\)

\(\frac{99}{153}\)-\(\frac{75}{125}\)

\(2m^2\)\(13dm^2\)\(=...................m^2\)

\(1m^2\)\(20dm^2\)\(=..........m^2\)

\(4m^2\)\(5dm^2\)\(=.............m^2\)

\(3m^2\)\(17dm^2\)\(=............dm^2\)