= 389/30

a) A={10;17;24;31;38;45;52;59;66;73;80;87;94;101;108;115;122;129;136;143;150}

b) Số phần tử mà tập hợp A có là:                           (150 - 10) : 7 + 1 = 21 ( phần tử )

    Tổng các phần tử của tập hợp A là:

                                                             (150 + 10) x 21 :2 =1680

Bài 35 :

\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\)

\(A=\frac{2^{10}.\left(13+65\right)}{2^8.104}\)

\(A=\frac{2^8.2^2.98}{2^8.104}\)

\(A=\frac{2^8.4.98}{2^8.4.26}\)

\(A=\frac{49}{13}\)

Vậy \(A=\frac{49}{13}\)

\(B=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

\(B=\frac{11.3^{29}-9^{15}}{2^2.\left(3^{14}\right)^2}\)

\(B=\frac{11.3^{29}-9^{15}}{2^2.3^{28}}\)

\(B=\frac{11.3^{29}-\left(3^2\right)^{15}}{4.3^{28}}\)

\(B=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)

\(B=\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)

\(B=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}\)

\(B=\frac{3^{29}.8}{4.3^{28}}\)

\(B=\frac{3^{28}.3.4.2}{4.3^{28}}\)

\(B=3.2\)

\(B=6\)

Vậy B = 6 

A = 2^10 . 13 + 2^10 . 65 / 2^8 . 104

   = 2^10 ( 13 + 65 ) / 2^8 . 104 = 2^10 . 78 / 2^8 . 104 = 2^8 . 2^2 . 78 / 2^8 . 104 = 2^8 . 4 . 78 / 2^8 . 104 = 2^8 . 312 / 2^8 . 104

   = 312/104

   = 3

B = 11 . 3^22 . 3^7 - 9^15 / ( 2.3^14)^2

   = 11 . 3^29 - (3^2)^15 / ( 3.2^14)^2

   = 11 . 3^29 - 3^30 / ( 3. 2 )^28

    = ( 8 + 3 ) . 3^29 - 3^30 / ( 3. 2)^28

    = 8 . 3^29 + 3.3^29 - 3^30 / ( 3.2)^28

     = 8 . 3^29 + 3^30 - 3^30 / ( 3 . 2)^28

    = 8 . 3^29 / 3^28 . 2^28

     = 2^3 . 3 / 2^28

     = 3/ 2^25

a/ 100 : { 2. [ 52 - ( 35 - 8 )]}

= 100 : { 2. [ 52 -  27 ]}

= 100 : { 2. 25 }

= 100 : 50

= 2

b/ 12 : { 390 : [ 500 - ( 125 + 35 . 7 )]}

= 12 : { 390 : [ 500 - ( 125 + 245 )]}

= 12 : { 390 : [ 500 - 370  ]}

= 12 : { 390 : 130 }

= 12 : 3

= 4

c/ 3. 5² - 16 : 2²

= 3 . 25 - 16 : 4

= 75 - 4

= 71

    Bài này dễ mà 

\(7^9:7^7+3^3.3\)

\(=7^2+3^4\)

\(=49+81\)

\(=130\)

a) \(\left(3^{35}+3^{34}-3^{33}\right):3^{32}\)

\(=\frac{3^{35}}{3^{32}}+\frac{3^{34}}{3^{32}}-\frac{3^{33}}{3^{32}}\)

\(=3^3+3^2-3\)

\(=27+9-3\)

\(=33\)

b) \(5^3.37+5^3.64-5^7:5^4\)

\(=5^3.37+5^3.64-5^3\)

\(=5^3\left(37+64-1\right)\)

\(=5^3.100\)

\(=125.100\)

\(=12500\)

\(\left(3^{35}+3^{34}-3^{33}\right)\div3^{32}=3^{33}\left(3^2+3-1\right)\div3^{32}\)

\(=3^{33}.11\div3^{32}=11\left(3^{33-32}\right)=11.3=33\)

\(A=\frac{21.99+21}{35.201-35}=\frac{21\left(99+21\right)}{35\left(201-1\right)}=\frac{21.\left(99+1+20\right)}{35.200}=\frac{21.120}{35.200}=\frac{\left(3.7\right).\left(2.2.3.\right)10}{\left(5.7\right).\left(2.2.5\right).10}=\frac{3.3}{5.5}=\left(\frac{3}{5}\right)^2\)

\(B=\frac{\left(-2\right)^{36}.3^{17}}{3^{18}.2^{35}}=\frac{2^{36}.3^{17}}{2^{35}.3^{18}}=2^{\left(36-35\right)}.3^{17-18}=2.3^{-1}=\frac{2}{3}\)

\(C=\frac{7^{100}-7^{99}}{7^{98}-7^{97}}=\frac{7^{99}\left(7^1-7^0\right)}{7^{97}\left(7^1-7^0\right)}=7^{99-97}.\frac{\left(7-1\right)}{7-1}=7^2.1=49\)

mấy bn giải chi tiết giúp mk nhé !