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\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}=3\)
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}=\frac{2^2.78}{104}=\frac{2^2.2.39}{2^3.13}=\frac{2^3.39}{2^3.13}=3\)
( 17x - 25 ) : 8 + 65 = 9^2
( 17x - 25 ) : 8 + 65 = 81
( 17x - 25 ) : 8 = 81 - 65
( 17x - 25 ) : 8 = 16
( 17x - 25 ) = 16 x 8
( 17x - 25 ) = 128
17x = 128 + 25
17x = 153
x = 153 : 17
x = 9
\(\left(17x-25\right):8+65=9^2\)
\(\Leftrightarrow\left(17x-25\right):8=81-65\)
\(\Leftrightarrow\left(17x-25\right):8=16\)
\(\Leftrightarrow17x-25=16.8\Leftrightarrow17x=128+25\Leftrightarrow17x=153\Leftrightarrow x=153:17=9\)
(k cho mình với nhá!)
a (-4) . (+3) . (-125) . (+25) . (-8)
=[(-4) . (+25)] . [(-125) . (-8)] . (+3)
=(-100) + (1000) . (+3)
= -300 000
b (-67) . (1 - 301) - 301 . 67
=(-67) . 1 + 67 . 301 - 67 . 301
= - 67
a) 1152-(374+1152)+(-65+374)
=1152-374-1152-65+374
=(1152-1152)+(-374+374)-65
=-65
a, 1152 - ( 374 + 1152 ) + ( -65 + 374 )
= 1152 - 374 - 1152 - 65 + 374
= ( 1152 - 1152 ) - ( 374 - 374 ) - 65
= 0 - 0 - 65
= -65
b, 13 - 12 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1
= ( 13 - 12 ) + 11 + ( 10 - 9 ) + ( 8 - 7 ) - ( 6 - 5 ) - ( 4 - 3 ) + ( 2 - 1 )
= 1 + 11 + 1 + 1 - 1 - 1 + 1
= 13
a, \(\frac{65}{91}+\frac{-33}{55}=\frac{5}{7}+\frac{-3}{5}=\frac{4}{35}\)
b, \(\frac{36}{-84}+\frac{100}{450}=\frac{-3}{7}+\frac{2}{9}=-\frac{13}{63}\)
c, \(\frac{-650}{1430}+\frac{588}{686}=\frac{-5}{11}+\frac{6}{7}=\frac{31}{77}\)
d, \(\frac{2004}{2010}+\frac{8}{-670}=\frac{334}{335}+\frac{-4}{335}=\frac{66}{67}\)
\(b,1.2.3...9-1.2.3...8-1.2.3...7.8^2\)
\(=(1.2.3...8).(9-1-8)\)
\(=(1.2.3...8).0\)
\(=0\)
a, 1 + 3 − 5 − 7 + 9 + 11 − ... − 397 − 399
= (1 + 3 - 5 - 7) + (9 + 11 - 13 - 15) + ... + (393 + 395 - 397 - 399)
= (-8) + (-8) + ... + (-8)
= (-8) . 50 (vì có 50 lần số hạng -8)
= - 400
_Vậy 1 + 3 − 5 − 7 + 9 + 11 − ... − 397 − 399 = -400
73
Bằng 73
73
73
73😎😎😎😎✋✋✋😜😜😜
65+8=73