Ta có:

\(A=\frac{67^{2016}}{67^{2016}-11}=1+\frac{11}{67^{2016}-11}\)

\(B=\frac{67^{2016}+13}{67^{2016}+2}=1+\frac{11}{67^{2016}+2}\)

Vì \(67^{2016}-11< 67^{2016}+2\) nên \(\frac{11}{67^{2016}-11}>\frac{11}{67^{2016}+2}\Rightarrow1+\frac{11}{67^{2016}-11}>1+\frac{11}{67^{2016}+2}\)

Vậy A > B 

\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\frac{79}{67}+\frac{28}{41}\) \(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}=\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\) \(=\frac{1}{3}+\left(-1\right)+1=\frac{1}{3}\)

Chúc bạn hc giỏi ,Trần Phúc Đông❣ღ!

\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{7.9}{67}-\frac{27}{41}\right)\)

\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{63}{67}-\frac{27}{41}\right)\)

\(=\frac{6836}{8241}-\frac{774}{2747}\)

\(=\frac{4514}{8241}\)

bằng \(\frac{4514}{8241}\)

tk nha , thanks nhìu

\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)

=\(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)

=\(\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)

=\(\frac{1}{3}+\left(\frac{-67}{67}\right)+\left(\frac{41}{41}\right)\)

=\(\frac{1}{3}-1+1\)

=\(\frac{1}{3}\)

\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)

=\(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)

=\(\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)

=\(\frac{1}{3}+\left(\frac{-67}{67}\right)+\left(\frac{41}{41}\right)\)

=\(\frac{1}{3}-1+1\)

=\(\frac{1}{3}\)

\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)

\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}-\frac{28}{41}\)

\(=\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)+\frac{1}{3}\)

\(=\left(-1\right)+1+\frac{1}{3}\)

\(=0+\frac{1}{3}\)

\(=\frac{1}{3}\)

=1/3+12/67+13/41-79/67+28/41

=1/3+(12/67-79/67)+(13/41+28/41)

=1/3+(-1)+1

=1/3+0

=1/3

a)(37-17).(-5)+23.(-6).(-8)

=20.(-5)+23.[(-6).(-8)]

=-100+23.(-48)

=-100+(-1104)

=-1004

b)(-57).(67-34)-67.(34-57)

=(-57).33-67.(-23)

=(-1881)-(-1541)

=-340