\((–2)^4.(–2)\)

\(=-16.\left(-2\right)\)

\(\) \(=32\)

\(\left(-2\right)^4\cdot\left(-2\right)^5=\left(2^4\cdot2^5\right)=-2^9=-512\)

\(\left(-2\right)^{12}:\left(-2\right)^3=-\left(2^{12}:2^3\right)=-2^9=-512\)

72 á nhưng mình ko chắc

6,76

\(\left(\frac{1}{2}\right)^{10}\)

\(=\frac{1}{2}\cdot\frac{1}{2}\cdot...\cdot\frac{1}{2}\)

\(=\frac{1}{1024}\)

\(\left(\frac{1}{2}\right)^{10}=\frac{1}{2}.\frac{1}{2}....\frac{1}{2}\) (10 lần)

                  \(=\frac{1}{1024}\)

3/4

k mk nha

\(5\frac{2}{3}x+1\frac{2}{3}=4\frac{1}{2}\)

\(\Leftrightarrow\frac{17}{3}x+\frac{5}{3}=\frac{9}{2}\)

\(\Leftrightarrow\frac{17}{3}x=\frac{9}{2}-\frac{5}{3}\)

\(\Leftrightarrow\frac{17}{3}x=\frac{17}{6}\)

\(\Leftrightarrow x=\frac{1}{2}\)

Vậy..

Học tốt

#Thảo Vy#

Cho hai điểm A, B thuộc đồ thị hàm số y = 3x + 1

a) Ta có:

b) Ta có:

\(y_B=-8\Rightarrow x_B=\dfrac{y-1}{3}=\dfrac{-8+1}{3}=-\dfrac{9}{3}=-3\)

theo dõi mk nha

\(\left(\frac{2}{3}\right)^3\cdot\frac{9}{4}=\frac{2}{3}\)

\(A\left(\sqrt{2};\sqrt{2}\right)\Rightarrow x=\sqrt{2};y=\sqrt{2}\) Thay vào hàm số \(y=\left(\sqrt{a}-2\right)x\) ta được :

\(\sqrt{2}=\left(\sqrt{a}-2\right)\sqrt{2}\)

\(\Rightarrow\sqrt{a}-2=1\)

\(\Rightarrow\sqrt{a}=3\)

\(\Rightarrow a=9\)

Vậy \(a=9\)