2x³ : 3² = 48

2x³ : 9 = 48

2x³ = 48.9

2x³ = 432

x³ = 432 : 2

x³ = 216

x³ = 6³

=> x=6.

\(\left(\frac{1}{3}\right)^{2x-1}-\frac{1}{3^2}=-\frac{2}{27}\)

=> \(\left(\frac{1}{3}\right)^{2x-1}=-\frac{2}{27}+\frac{1}{9}\)

=> \(\left(\frac{1}{3}\right)^{2x-1}=\frac{1}{27}\)

=> \(\left(\frac{1}{3}\right)^{2x-1}=\left(\frac{1}{3}\right)^3\)

=> 2x - 1 = 3

=> 2x = 3 + 1

=> 2x = 4

=> x = 4/2 = 2

Bài 1:

6) 3x + 2³ = 17 + 3²

3x + 8 = 17 + 9

3x + 8 = 26

3x = 26 - 8

3x = 18

x = 18 : 3

x = 6

Vậy x = 6

Bài 2:

3) 145 - (125 + x) = 12

125 + x = 145 - 12

125 + x = 133

x = 133 - 125

x = 8

Vậy x = 8

6) 3³ - (x - 5) = 2²

27 - (x - 5) = 4

x - 5 = 27 - 4

x - 5 = 23

x = 23 + 5

x = 28

Vậy x = 28

9) (x + 7) - 15⁰ = 202 - 19

(x + 7) - 1 = 189

x + 7 = 189 + 1

x + 7 = 190

x = 190 - 7

x - 183

Vậy x = 183

thanks bro ! :)

tích cho mk đi bro

1. a) \(45x-37=53\)

\(45x=90\)

\(x=2\)

vay \(x=2\)

b) \(\frac{x}{9}+500=600\)

\(\frac{x}{9}=100\)

\(\frac{x}{9}=\frac{900}{9}\)

\(\Rightarrow x=900\)

vay \(x=900\)

c) \(576-x=139\)

\(x=576-139\)

\(x=437\)

vay \(x=437\)

d) \(\left(48+x\right)-27=79\)

\(48+x=79+27\)

\(48+x=106\)

\(x=58\)

vay \(x=58\)

2. \(2^5.2^7.2^9=2^{5+7+9}=2^{21}\)

 \(3^9.3^2.3=3^{9+2+1}=3^{12}\)

\(10^9:10^7=10^{10-7}=10^3\)

3). \(2.2.2.2.2.2=2^6\)

\(2.3.2.2.3.3.3=2^3.3^4\)

\(10.9.10.10.10.9.9=10^4.9^3\)

1 a) x= 720

b ) x=chín trăm 

c)x= 437

d)x=58

bài2   a)= 2²¹  b)3¹² c ) =10²  

bài 3 a)=2⁶ b)=2² nhân 3⁴ c )= 10³ nhân chín mũ 3 

\(x^{200}=x\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=0\end{cases}}\)

\(x^{100}=1\)

\(\Rightarrow x=1\)

\(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Rightarrow2x-15=2x-15\)

\(\Rightarrow x=1\)

\((\frac23)^5-2x=\frac23\)

\(=\frac{32}{243}-2x=\frac{162}{243}\)

\(=2x=\frac{32}{243}-\frac{162}{243}\)

\(=-2x=\frac{130}{243}\)

\(x=-\frac{65}{243}\)

(\(\frac23\))\(^{5-2x}\) = \(\frac23\)

(\(\frac23\))\(^{5-2x}\) = (\(\frac23\))\(^1\)

5 - 2\(x\) = 1

2\(x\) = 5 - 1

2\(x\) = 4

\(x\) = 4 : 2

\(x\) = 2

Vậy \(x\) = 2