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\(48\cdot19+48\cdot115+134\cdot52\)
\(=48\cdot\left(19+115\right)+134\cdot52\)
\(=48\cdot134+134\cdot52=134\left(48+52\right)=134\cdot100=13400\)
a,
58.75 + 58.50 - 58.25
= 58.(75 + 50 - 25)
= 58. (125 - 25)
= 58.100
= 5800
b, 27.39 + 27.63 - 2.27
= 27.(39 + 63 - 2)
= 27.(102 - 2)
= 27.100
= 2700
a) 58.75 + 58.50 - 58.25
= 58. (75 + 50 - 25)
= 58. 100
= 5800
b) 27.39 + 27.63 + 2.27
= 27. (39 + 63 - 2)
= 27. 100
= 2700
c) 128.46 + 128.32 + 128.22
= 128.(46 + 32 + 22)
= 128. 100
= 12800
d) 12.35 + 35.182 - 35.94
= 35.(12 + 182 - 94)
= 35. 100
= 3500
e) 48.19 + 48.115 + 134.52
= 48.(19 + 115) + 134.52
= 48.134 + 134.52
= 134.(48 + 52)
= 134.100
= 13400
f) 136.23 + 136.17 - 40.36
= 136.(23 + 17) - 40.36
= 136.40 - 40.36
= 40.(136 - 36)
= 40.100
= 4000
g) 17.93 + 116.83 + 17.23
= 17.(93 + 23) + 116.83
= 17.116 + 116.83
= 116.(17 + 83)
= 116.100
= 11600
h) 19.27 + 47.81 + 19.20
= 19.(27 + 20) + 47.81
= 19.47 + 47.81
= 47.(19 + 81)
= 47.100
= 4700
i) 87.23 + 13.93 + 70.87
= 87.(23 + 70) + 13.93
= 87.93 + 13.93
= 93.(87 + 13)
= 93.100
= 9300
#NgHn
Ta có : A = \(\frac{10^{2020}+1}{10^{2021}+1}\)
=> 10A = \(\frac{10^{2021}+10}{10^{2021}+1}=1+\frac{9}{10^{2021}+1}\)
Lại có : \(B=\frac{10^{2021}+1}{10^{2022}+1}\)
=> \(10B=\frac{10^{2022}+10}{10^{2022}+1}=1+\frac{9}{10^{2022}+1}\)
Vì \(\frac{9}{10^{2022}+1}< \frac{9}{10^{2021}+1}\)
=> \(1+\frac{9}{10^{2022}+1}< 1+\frac{9}{10^{2022}+1}\)
=> 10B < 10A
=> B < A
b) Ta có : \(\frac{2019}{2020+2021}< \frac{2019}{2020}\)
Lại có : \(\frac{2020}{2020+2021}< \frac{2020}{2021}\)
=> \(\frac{2019}{2020+2021}+\frac{2020}{2020+2021}< \frac{2019}{2020}+\frac{2020}{2021}\)
=> \(\frac{2019+2020}{2020+2021}< \frac{2019}{2020}+\frac{2020}{2021}\)
=> B < A
Ta có: \(A=\frac{2020}{2021}+\frac{2021}{2022}\)
\(\Rightarrow A=\frac{2021}{2021}-\frac{1}{2021}+\frac{2022}{2022}-\frac{1}{2022}\)
\(\Rightarrow A=1-\frac{1}{2021}+1-\frac{1}{2022}\)
\(\Rightarrow A=1+1-\frac{1}{2021}-\frac{1}{2022}\)
\(\Rightarrow A=2-\frac{1}{2021}-\frac{1}{2022}\)
\(\Rightarrow A=2-\frac{1}{2021\cdot2022}\)
\(B=\frac{2020+2021}{2021+2022}\)
\(\Rightarrow B=\frac{2021+2022}{2021+2022}-\frac{2}{2021+2022}\)
\(\Rightarrow B=1-\frac{2}{2021+2022}\)
\(\Rightarrow B=1-\frac{2}{4043}\)
Vậy ta sẽ so sánh:
\(1-\frac{1}{2021\cdot2022};\frac{2}{4043}\)
Vì \(2021\cdot2022>4043\)nên \(\frac{1}{2021\cdot2022}< \frac{2}{4043}\)vậy \(1-\frac{1}{2021\cdot2022}>\frac{2}{4043}\)
\(\Rightarrow\frac{2020}{2021}+\frac{2021}{2022}>\frac{2020+2021}{2021+2022}\)
\(\Rightarrow A>B\)
a, 5800
b, 2700
c, 12800
d, 5082
e, 10080
f, 13400
g, 5020
h, 5200
a) 29.75.2+58.50-58.25 b) 9.39.3+27.63-2.27
= (29.2).75+58.50-58.25 = (9.3).39+27.63-2.27
= 58.75+58.50-58.25 = 27.39+27.63-2.27
= 58.(75+50-25) = 27.(39+63-2)
= 58.100 = 27.100
= 5800. = 2700.
c)64.46.2+16.32.8+128.22 d)6.25.11+5.22.3+66.14+33.66
= (64.2).46+(16.8).32+128.22 = (6.11).25+5.(22.3)+66.14+33.66
= 128.46+128.32+128.22 = 66.25+5.66+66.14+33.66
= 128.(46+32+22) = 66.(25+5+14+33)
= 128.100 = 66.77
= 12800. = 5082
1)
a) 35.23 + 35.41 + 64.65 = 35(23+41) + 64.65 = 35 . 65 + 64.65 =65. 99 = 65(100 - 1 ) = 6500 - 65 = 6435
b) 29.87 - 29.23 + 64.71 = 29(87-23) + 64.71 = 29.64 + 64.71 = 64(71+29) = 64.100= 6400
c) 48.19 + 48.115 + 134.52 = 48(19+115) + 134.52 = 48 . 134+134.52=134(52+48)=134.100=13400
d) 27.121 - 87.27 + 73.34 = 27(121-87) +73 .34 = 27 .34 + 73.34 = 34(73+27)=34.100=3400
e) 125.98-125.46-52.25 = 125(98-46) -52.25 = 125 . 52 - 52.25 =52(125-25) =52.100=5200
f)136.23 + 136.17 - 40.36 = 136(23+17) - 40.36 = 136.40 -40.36 = (136-36)40 = 100.40=4000
g) 17.93 + 116.83 + 17.23 = 17(93+23) + 116.83 = 17.116 + 116.83 =116(83+17) = 116.100=11600
h)19.27 +47.81 + 19.20 = 19(27+20) + 47.81 = 19. 47 + 47.81 = 47(81+19)=47.100 = 4700
i) 87.23 + 13.93 + 70.87 = 87(23+70) + 13.93 = 87 .93 + 13.93 = 93(87+13)=93.100=9300
2)Tìm x
a) [(6x-39):37].4 = 12
(6x - 39) : 37 = 12 : 4 = 3
x =(3.37 + 39): 6 = 25
b) ( x : 3 - 4 ) .5=15
x : 3 -4 = 3
x = (3+4).3 = 21
c) 128 - 3(x+4) =23
3x + 12 = 128 -23 = 105
x = (105-12):3 = 31
d) (3x - 34).73=2.74
3x - 81 = 2.74:73=2.7=14
x =(81 + 14 ) : 3= \(31\frac{2}{3}\)
e) x - [42 + (-28) ] = -8
x - 14 = -8
x- 14 + 14 = -8 + 14
x = 6
1. Tính nhanh:
a, 35.23+35.41+64.65
= 35. (23+41) +64.65
= 35. 64 + 64.65
= 64. ( 35 + 65 )
= 64 . 100
= 6400
b, 29.87 - 29.23 + 64.71
= 29.(87-23) + 64.71
= 29.64 + 64.71
= 64.(29 + 71)
= 64.100
= 6400
c, 48.19 + 48.115 + 134.52
= 48.(19 + 115) + 134.52
= 48.134 + 134.52
= 134.(48 + 52)
= 134.100
= 13400
d, 27.121 - 87.27 + 73.34
= 27.(121 - 87) + 73.34
= 27.34 + 73.34
= 34.(27 + 73)
= 34.100
= 3400
e, 125.98 - 125.46 - 52.25
= 125.(98 - 46) - 52.25
= 125.52 - 52.25
= 52.(125 - 25)
= 52.100
= 5200
f, 136.23 + 136.17 - 40.36
= 136.(23 + 17) - 40.36
= 136.40 - 40.36
= 40.(136 - 36)
= 40.100
= 4000
g, 17.93 + 116.83 + 17.23
= 17.(93+23) + 116.83
= 17.116 + 116.83
= 116.(17 + 83)
= 116.100
= 11600
Lát nữa mình làm tiếp, giờ mình phải đi học rồi
a)-(-21+43+7)-(11-53-17)
= (21 - 11) + (53 - 43) + (17-7)
= 10 + 10 + 10 = 30 b )12.35+35.182-35.94
= 35. (12 + 182 - 94) = 35 . 100 = 3500 c)(-2022)+25+2022+(-2025)
= (-2022 + 2022) + (25 - 2025)
= 0 - 2000 = -2000 d)48.19+48.115 - 134.52
= 48 . (19 + 115 - 134)
= 48. 0 = 0 e)(-2021)-(199-2021)
= (2021 - 2021) - 199
= 0 - 199 = -199
a) -(-21+43+7)-(11-53-170
=21-43-7-11+53+170
=(21-11)+(53-43)+(170-7)
=10+10+163
=20+163
=183
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