a: \(\Leftrightarrow x\cdot\dfrac{1}{2}-\dfrac{3}{5}x+\dfrac{13}{5}=-\dfrac{7}{5}-\dfrac{7}{10}x\)

=>3/5x=-4

hay x=-4:3/5=-20/3

b: \(\Leftrightarrow4x-6-9=5-3x-2\)

=>4x-15=-3x+3

=>7x=18

hay x=18/7

Câu a:

- \(\frac12\)(3 - 2\(x\)) - 7 = 5 - \(\frac13\)(\(x\) - \(\frac45\))

- \(\frac32\) + \(x\) - 7 = 5 - \(\frac13x\) + \(\frac{4}{15}\)

\(x\) + \(\frac13x\) = 5 + \(\frac{4}{15}\) + 7 + \(\frac32\)

(1 + \(\frac13\))\(x\) = \(\frac{150}{30}\) + \(\frac{8}{30}\) + \(\frac{210}{30}\) + \(\frac{45}{30}\)

\(\frac43x\) = \(\frac{158}{30}\) + \(\frac{210}{30}\) + \(\frac{45}{30}\)

\(\frac43x\) = \(\frac{368}{30}\) + \(\frac{45}{30}\)

\(\frac43x\) = \(\frac{413}{30}\)

\(x\) = \(\frac{413}{30}\) : \(\frac43\)

\(x\) = \(\frac{413}{40}\)

Vậy \(x=\frac{413}{40}\)

Câu b:

(5 - 3x/2) : - 1 3/8 = - 7 1/3

(5 - 3x/2) : (-11/8) = - 22/3

5 - 3x/2 = - 22/3 x (-11/8)

5 - 3x/2 = 121/12

3x/2 = 5 - 121/12

3x/2 = - 61/12

x = - 61/12 : 3/2

x = -61/18

Vậy x = - 61/18

tìm x à ? 

\(4^{3x+1}-8.4^2=8.4^2\)

\(\Rightarrow4^{3x}.4=8.4^2+8.4^2=16.4^2\)

\(\Rightarrow4^{3^x}=4.4.4=4^3\)

\(\Rightarrow3x=3\)

\(\Rightarrow x=1\)

\(7^{5x-1}=7^4\)

\(\Rightarrow5x-1=4\)

\(\Rightarrow5x=5\)

\(\Rightarrow x=1\)

tìm 2 số nguyên a và b biết :a+b=-1 và a.b=-12.Giup mình nha

a.Ta có:|2x-1|=2x-1\(\Leftrightarrow\)2x-1\(\ge\)0\(\Leftrightarrow\)x\(\ge\)\(\dfrac{1}{2}\)

|2x-1|=1-2x\(\Leftrightarrow\)2x-1<0\(\Leftrightarrow\)x<\(\dfrac{1}{2}\)

ĐK:\(x\ge\dfrac{1}{2}\)

\(2x-1=2x-1\)

\(\Leftrightarrow2x-1-2x+1=0\)

\(\Leftrightarrow0x=0\)

\(\Rightarrow\)Tập no của PT là S={\(\forall x\)|x\(\ge\dfrac{1}{2}\)}

b.|0,5-3x|=3x-0,5\(\Leftrightarrow\)x<2,5

=0,5-3x\(\Leftrightarrow x\ge2,5\)

ĐK:x<2,5

Gỉai

0,5-3x=3x-0,5

\(\Leftrightarrow\)0,5-3x-3x+0,5=0

\(\Leftrightarrow\)1-6x=0

\(\Leftrightarrow x=\dfrac{1}{6}\)(TMĐKXĐ)

\(\Rightarrow\)tập no của PT là S={\(\dfrac{1}{6}\)}

c.|5x+1-10x|=0,5\(\Leftrightarrow\)|1-5x|=0,5\(\Leftrightarrow x< \dfrac{1}{5}\)

\(\Leftrightarrow\)|1-5x|=-0,5\(\Leftrightarrow\)x\(\ge\dfrac{1}{5}\)

ĐK:\(x< \dfrac{1}{5}\)

Gỉai

1-5x=0,5

\(\Leftrightarrow5x=0,5\)

\(\Leftrightarrow x=0,1\)(loại)

\(\Rightarrow pt\) trên vô nghiệm

d.|x+2|-|x-7|=0

ĐK:x\(\ne\pm2\);x\(\ne\pm7\)

Gỉai

\(\left\{{}\begin{matrix}x+2-x+7=0\\x-2-x-7=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}-9=0\\-2x-9=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}-9=0\left(KTMĐKXĐ\right)\\x=-4,5\left(TMĐKXĐ\right)\end{matrix}\right.\)

\(\Rightarrow\)tập no của phương trình là S={-4,5}

a) Ta có:

\(\frac{3}{x+2}=\frac{5}{2x+1}\)

\(\Rightarrow3\left(2x+1\right)=5\left(x+2\right)\)

\(\Rightarrow6x+3=5x+10\)

\(\Rightarrow6x-5x=10-3\)

\(\Rightarrow x=7\)

b)Ta có:

\(\frac{5}{8x-2}=\frac{-4}{7-x}\)

\(\Rightarrow5\left(7-x\right)=-4\left(8x-2\right)\)

\(\Rightarrow35-5x=-32x+8\)

\(\Rightarrow-5x+32x=8-35\)

\(\Rightarrow27x=-27\)

\(\Rightarrow x=-1\)

c) Ta có:

\(\frac{4}{3}=\frac{2x-1}{x}\)

\(\Rightarrow4x=3\left(2x-1\right)\)

\(\Rightarrow4x=6x-3\)

\(\Rightarrow3=6x-4x=2x\)

\(\Rightarrow x=\frac{3}{2}\)

d)Ta có:

\(\frac{2x-1}{3}=\frac{3x+1}{4}\)

\(\Rightarrow4\left(2x-1\right)=3\left(3x+1\right)\)

\(\Rightarrow8x-4=9x+3\)

\(\Rightarrow8x-9x=3+4\)

\(\Rightarrow-x=7\Rightarrow x=-7\)

e)Ta có:

\(\frac{4}{x+2}=\frac{7}{3x+1}\)

\(\Rightarrow4\left(3x+1\right)=7\left(x+2\right)\)

\(\Rightarrow12x+4=7x+14\)

\(\Rightarrow12x-7x=14-4\)

\(\Rightarrow5x=10\)

\(\Rightarrow x=2\)

f)Ta có:

\(\frac{-3}{x+1}=\frac{4}{2-2x}\)

\(\Rightarrow-3\left(2-2x\right)=4\left(x+1\right)\)

\(\Rightarrow-6+6x=4x+4\)

\(\Rightarrow6x-4x=4+6\)

\(\Rightarrow2x=10\)

\(\Rightarrow x=5\)