b: \(\left(124567-4567\right):5=240000\)

c: \(751\cdot68+751\cdot32=75100\)

d: \(\left(1300-300\right)\cdot45=45000\)

a:1008:14+28=100

b: 

c: 

d: 

725 x 28 - 14 x 25 x 2 + 300 x 28 

= 725 x 28 - (14 x 2) x 25 + 300 x 28 

= 725 x 28 - 28 x 25 + 300 x 28 

= 28 x ( 725 - 25 + 300 )

= 28 x 1000

 =28000

a) \(\frac{2}{5}+\frac{9}{15}=\frac{2}{5}+\frac{3}{5}=\frac{5}{5}=1\)

b) \(\frac{15}{45}+\frac{25}{30}=\frac{1}{3}+\frac{5}{6}=\frac{2}{6}+\frac{5}{6}=\frac{7}{6}\)

c) \(\frac{28}{32}+\frac{45}{72}=\frac{7}{8}+\frac{5}{8}=\frac{12}{8}=\frac{3}{2}\)

d) \(\frac{8}{28}+\frac{5}{30}=\frac{2}{7}+\frac{1}{6}=\frac{12}{42}+\frac{7}{42}=\frac{19}{42}\)

a) \(\frac{2}{5}+\frac{9}{15}\)=\(\frac{2}{5}+\frac{3}{5}=\frac{2+3}{5}=1\)

b)\(\frac{15}{45}+\frac{25}{30}=\frac{1}{3}+\frac{5}{6}=\frac{2}{6}+\frac{5}{6}=\frac{2+5}{6}=\frac{7}{6}\)

c)\(\frac{28}{32}+\frac{45}{72}=\frac{7}{8}+\frac{5}{8}=\frac{7+5}{8}=\frac{12}{8}=\frac{3}{2}\)

d)\(\frac{8}{28}+\frac{5}{30}=\frac{2}{7}+\frac{1}{6}=\frac{12}{42}+\frac{7}{42}=\frac{12+7}{42}=\frac{19}{42}\)

\(\frac{45x16-17}{45x15-28}\)\(=\frac{703}{647}\)

Tích tớ nha

ai truoc minh cho

ket qua bang 3 nhe

17/45+23/45+28/45+1/27+26/27+22/45

=(17/45+23/45+28/45+22/45)+(1/27+26/27)

=2+1

=3

\(a,\left(\frac{5}{7}+\frac{9}{7}\right)x\frac{21}{28}\)

\(C1:=\frac{14}{7}x\frac{21}{28}=\frac{3}{2}\)

\(C2:=\frac{5}{7}x\frac{21}{28}+\frac{9}{7}x\frac{21}{28}=\frac{15}{28}+\frac{27}{28}=\frac{3}{2}\)

\(b,\frac{4}{5}x\frac{13}{14}+\frac{13}{14}x\frac{1}{5}\)

\(C1:=\frac{26}{35}+\frac{13}{70}=\frac{13}{14}\)

\(C2:=\frac{13}{14}x\left(\frac{4}{5}+\frac{1}{5}\right)=\frac{13}{14}x1=\frac{13}{14}\)

học tốt ~~~

Cảm ơn bạn!

a) \(A=\frac{27\text{x}45+27\text{x}25}{2+4+6+8+...+18}=\frac{27\left(45+25\right)}{\left(18+2\right)\text{x}\left(\frac{18-2}{2}+1\right)}\)

\(A=\frac{27\text{x}70}{20\text{x}9}=\frac{3\text{x}9\text{x}10\text{x}7}{10\text{x}2\text{x}9}\)

\(A=\frac{21}{2}\)

b) \(B=\frac{28\text{x}108-52\text{x}12}{32-28+24-20+16-12+8-4}\)

\(B=\frac{28\text{x}12\text{x}9\text{​​}\text{​​}-52\text{x}12}{\left(32-28\right)+\left(24-20\right)+\left(16-12\right)+\left(8-4\right)}\)

\(B=\frac{12\left(28\text{x}9-52\right)}{4+4+4+4}=\frac{12\text{x}200}{4\text{x}4}\)

\(B=\frac{4\text{x}3\text{x}4\text{x}50}{4\text{x}4}=150\)

cám ơn bn

1153/703 nha bn

ko

\(\frac{2}{7}:y=\frac{10}{21}.\frac{9}{14}\)

\(\frac{2}{7}:y=\frac{15}{49}\)

\(y=\frac{2}{7}:\frac{15}{49}\)

\(y=\frac{2}{7}.\frac{49}{15}\)

\(y=\frac{14}{15}\)

\(y-\frac{1}{3}=\frac{10}{21}:\frac{15}{28}\)

\(y-\frac{1}{3}=\frac{10}{21}.\frac{28}{15}\)

\(y-\frac{1}{3}=\frac{8}{9}\)

\(y=\frac{8}{9}+\frac{1}{3}\)

\(y=\frac{8}{9}+\frac{3}{9}\)

\(y=\frac{11}{9}\)

a) Ta có :  \(y-\frac{1}{3}=\frac{10}{21}\div\frac{15}{28}\)

\(\Rightarrow\)       \(y-\frac{1}{3}=\frac{8}{9}\)

\(\Rightarrow\)       \(y\)        \(=\frac{8}{9}+\frac{1}{3}\)

\(\Rightarrow\)      \(y\)         \(=\frac{11}{9}\)

Vậy \(y=\frac{11}{9}\)

b) Ta có : \(\frac{2}{7}\div y=\frac{10}{21}\times\frac{9}{14}\) 

\(\Rightarrow\)      \(\frac{2}{7}\div y=\frac{15}{49}\)

\(\Rightarrow\)                  \(y=\frac{2}{7}\div\frac{15}{49}\)      

\(\Rightarrow\)                  \(y=\frac{14}{15}\)

Vậy \(y=\frac{14}{15}\)

                     Cbht !!!