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A=\(\frac{10^{901}+1}{10^{902}+1}=\frac{10^{902}+10}{10^{903}+10}\)
1-A=\(\frac{10^{902}.9}{10^{903}+10}\)
1-B=\(\frac{10^{902}.9}{10^{903}+1}\)
\(\frac{10^{902}.9}{10^{903}+10}\)<\(\frac{10^{902}.9}{10^{903}+1}\)\(\Rightarrow A>B\)
bạn có thể ra đề 1 cách cụ thể hơn đc không, tui nhìn vào không hiểu j cả
thay các chữ số a;b;c;d bằng các chữ số thích hợp sao cho:
1945abcd : abcd + 2011= 4012
8) ((456.11 + 912).37) : 13 . 74
= [(456.11 + 456 . 2).37] : 13 . 74
= [456.(11 + 2).37] : 13 . 74
= 456 . 13 . 37 : 13 . 74
= 456 . 37 : 74
= 456 : ( 74 : 37 )
= 456 : 2
= 228
9) Ta có:
864 . 48 - 432 . 96
= 432 . 2 . 48 - 432 . 96
= 432 . 96 - 432 . 96
= 432 . ( 96 - 96 )
= 432 . 0
= 0
\(\Rightarrow\left(864.48-432.96\right):864.48.432\)
\(=0:864.48.432\)
\(=0\)
\(8,\left[\left(456.11+912\right).37\right]:13.74\)
\(=\left[\left(5016+912\right).37\right]:13.74\)
\(=\left(5928.37\right):13.74\)
\(=219336:13.74\)
\(=16872.74\)
\(=1248528\)
\(9,\left(864.48-432.96\right):864.48.432\)
\(=\left(41472-41472\right):864.48.432\)
\(=0:864.48.432\)
\(=0\)
\(\frac{\left(456.11+912\right)37}{13.74}\)
= \(\frac{5928.37}{13.74}\)
= 228
Ta có: \(\frac{\left(456.11+912\right).37}{1374}=\frac{\left(456.11+456.2\right).37}{1374}\)
\(=\frac{456.\left(11+2\right).37}{1374}=\frac{456.13.37}{1374}=\frac{76.6.13.37}{6.229}=159,633...\)
gggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg
a) \(\frac{158\cdot168-168\cdot58}{110}\)
\(=\frac{\left(158-58\right)\cdot168}{110}\)
\(=\frac{100\cdot168}{110}=\frac{16800}{110}=\frac{1680}{11}\)
b) \(\frac{\left(456.11+912\right)\cdot37}{13\cdot74}\)
\(=\frac{456\cdot11+456\cdot2\cdot37}{13\cdot37\cdot2}\)
\(=\frac{456\cdot\left(11+2\right)\cdot37}{\left(13\cdot2\right)\cdot37}\)
\(=\frac{456\cdot13\cdot37}{26\cdot37}=228\)
c) \(\frac{864\cdot48-432\cdot96}{864\cdot48\cdot432}\)
\(=\frac{432\cdot2\cdot48-432\cdot48\cdot2}{432\cdot2\cdot48\cdot432}=0\)
=(-190+902+912)+4012=1624+4012=5636