ờ =)

🍀🧡_Trang_🧡🍀 má nó k biết tiếng việt sao nó viết tên Hạ Mặc Tịch được em =))

Bài 2:

a)\(x^3-2x^2+x\)

\(=x\left(x^2-2x+1\right)\)

\(=x\left(x-1\right)^2\)

b)\(x^2-2x-15\)

\(=x^2-5x+3x-15\)

\(=x\left(x-5\right)+3\left(x-5\right)\)

c)\(y\left(x-z\right)+7\left(z-x\right)\)

\(=7\left(z-x\right)-y\left(z-x\right)\)

\(=\left(7-y\right)\left(z-x\right)\)

\(=\left(x-5\right)\left(x+3\right)\)

d)\(36-12x+x^2\)

\(=x^2-12x+36\)

\(=\left(x-6\right)^2\)

Bài 1:

a)\(2x\left(x^2-7x-3\right)=2x^3-14x^2-6x\)

b)\(\left(-2x^3+34y^2-7xy\right)\cdot4xy^2=136xy^4-28x^2y^3-8x^4y^2\)

c)\(\left(x^2-2x+3\right)\left(x-4\right)\)

\(=x^2\left(x-4\right)-2x\left(x-4\right)+3\left(x-4\right)\)

\(=x^3-4x^2-2x^2+8x+3x-12\)

\(=x^3-6x^2+11x-12\)

d)\(\left(2x^3-3x-1\right)\left(5x+2\right)\)

\(=5x\left(2x^3-3x-1\right)+2\left(2x^3-3x-1\right)\)

\(=10x^4-15x^2-5x+4x^3-6x-2\)

\(=10x^4+4x^3-15x^2-11x-2\)

Bài 1:

1 (x+3)²=x²+6x+9

2

a, 2x²(3x-5x³)+10x⁵-5x³=6x³-10x⁵+10x⁵-5x³=x³

b, (x+3)(x²-3x+9)+(x-9)(x+3)=(x³+27)+(x²-6x-27)=x³+x²-6x

Bài 2:

a, x²-25x=0

\(\Leftrightarrow x\left(x-25\right)=0\)

\(\Leftrightarrow\begin{cases}x=0\\x-25=0\end{cases}\)

\(\Leftrightarrow\begin{cases}x=0\\x=25\end{cases}\)

b, (4x-1)²-9=0

\(\Leftrightarrow\left(4x-1-3\right)\left(4x-1+3\right)=0\)

\(\Leftrightarrow\left(4x-4\right)\left(4x+2\right)=0\)

\(\Leftrightarrow4\left(x-1\right)2\left(2x+1\right)=0\)

\(\Leftrightarrow8\left(x-1\right)\left(2x+1\right)=0\)

\(\Leftrightarrow\begin{cases}x-1=0\\2x+1=0\end{cases}\)

\(\Leftrightarrow\begin{cases}x=1\\x=\frac{-1}{2}\end{cases}\)

Bài 3:

a, 3x²-18x+27=3(x²-6x+9)=3(x-3)²

b, xy-y²-x+y=y(x-y)-(x-y)=(y-1)(x-y)

c, x²-5x-6=x²-6x+x-6=x(x-6)+(x-6)=(x+1)(x-6)

Bài 4:

a, ( 12x³y³-3x²y³+4x²y⁴):6x²y³=(12x³y³:6x²y³)-(3x²y³:6x²y³)+(4x²y⁴:6x²y³)

=2x-1/2 + 2/3y

b, bạn ơi mình không biết cách vẽ đường kẻ để chia ý , nếu bạn biết thì chỉ cho mình rồi mình làm cho

Bài 5 :

b, A = x(2x-3)

A= 2x²-3x

A= 2(x²-3/2x)

A= 2(x²-2x3/4+9/16-9/16)

A=2[(x-3/4)²-9/16]

A=2(x-3/4)²-9/8

A=2(x-3/4)²+(-9/8)

Vì (x-3/4)² \(\ge\)0 \(\forall x\)

-> 2(x-3/4)² \(\ge0\forall x\)

-> 2(x-3/4)²+(-9/8)\(\ge-\frac{9}{8}\forall x\)

Vậy MinA= -9/8

Bài 1:

1. Khai triển hằng đẳng thức

(x+3)² = x²+6x+9

2. Thực hiện phép tính

a) 2x²(3x-5x³)+10x⁵-5x³

=6x³-10x⁵+10x⁵-5x³

=x³

b)(x+3)(x²-3x+9)+(x-9)(x+3)

=(x³+27)+(x²+3x-9x-27)

=x³+27+x²+3x-9x-27

=x³+x²-6x

Bài 2:

a) x²-25x=0

\(\Leftrightarrow\)x(x-25)=0

\(\Leftrightarrow\) \(\left[\begin{matrix}x=0\\x-25=0\end{matrix}\right.\)

\(\Leftrightarrow\left[\begin{matrix}x=0\\x=25\end{matrix}\right.\)

Vậy x=0 hoặc x=25

b)(4x-1)² - 9=0

\(\Leftrightarrow\)(4x-1+3)(4x-1-3)=0

\(\Leftrightarrow\)(4x+2)(4x-4)=0

\(\Leftrightarrow\)2(2x+1)(2x-2)=0

\(\Leftrightarrow\left[\begin{matrix}2x+1=0\\2x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[\begin{matrix}x=\frac{-1}{2}\\x=1\end{matrix}\right.\)

Vậy x=1 hoặc x=\(\frac{-1}{2}\)

Bài 3:

a) 3x²-18x+27

=3(x²-6x+9)

=3(x-3)²

b) xy-y²-x+y

=(xy-y²)-(x-y)

=y(x-y)-(x-y)

=(x-y)(y-1)

c) x²-5x-6

=x²-6x+x-6

=(x²-6x)+(x-6)

=x(x-6)+(x-6

=(x-6)(x+1)

Bài 4:

a) (12x³y³-3x²y³+4x²y⁴) : 6x²y³

=x²y³(12x-3+4y): 6x²y³

=(12x-3+4y) : 6

= (12x : 6)-(3 : 6)+(4y : 6)

=2x-\(\frac{1}{2}\)+\(\frac{2y}{3}\)

b) (6x³-19x²+23x-12) : (2x-3)

=(3x²-5x+4)(2x-3) : (2x-3)

=3x²-5x+4

Cho mk xin nha !

Bạn cứ tự nhiên nha!

a)= -(x² -2x +1) +1 +4

GTLN = 5

b)=  -( x² -4x +4) +4

GTLN = 4

c) = -4( x² - x/4 + 1/16) +1/4 -5

GTLN = -19/5

1,Thực hiện phép tính :

a, (x + 2)⁹ : (x + 2)⁶

=(x+2)^9-6

=(x+2)³

b, (x - y) ⁴ : (x - 2)³

=(x-y)^4-3

=x-y

c, ( x²+ 2x + 4)⁵ : (x² + 2x + 4)

=(x²+2x+4)^5-1

=(x²+2x+4)⁴

d, 2(x² + 1)³ : 1/3(x² + 1)

=(2÷1/3).[(x²+1)³÷(x²+1)]

=6(x²+1)²

e, 5 (x - y)⁵ : 5/6 (x - y)²

=(5÷5/6).[(x-y)⁵÷(x-y)²]

=6(x-y)⁾³